On Mar 8, 11:10 pm, JanPB wrote:
On Mar 8, 10:10 pm, Koobee Wublee wrote:



On Mar 8, 8:50 am, JanPB wrote:

On Mar 7, 11:10 pm, Koobee Wublee wrote:
How can you argument with the mathematics? ds^2 is a scalar according
to the mathematics above. shrug

Take a 2D sphere of radius 1 (say). Pick a point p on it. Tell us,
what real number is ds^2 equal to at p?

Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

Where is the number? You said ds^2 was a scalar. Which number is ds^2
equal to on the sphere? Either write down the actual number or say
that you were wrong.
There is no other exit.

Not to interfere, let KW have 1st crack,
but I think that's a good problem.
I think I could give it a shot.
Regards
Ken

Jan Bielawski

On Mar 9, 12:10 am, JanPB wrote:
On Mar 8, 10:10 pm, Koobee Wublee wrote:

Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

Where is the number? You said ds^2 was a scalar. Which number is ds^2
equal to on the sphere? Either write down the actual number or say
that you were wrong.

Oh, no. I am not wrong on this one.

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

On Mar 9, 2:37 pm, Koobee Wublee wrote:
On Mar 9, 12:10 am, JanPB wrote:



On Mar 8, 10:10 pm, Koobee Wublee wrote:
Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

Where is the number? You said ds^2 was a scalar. Which number is ds^2
equal to on the sphere? Either write down the actual number or say
that you were wrong.

Oh, no. I am not wrong on this one.

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

You said ds^2 was a scalar. If this is so, then why can't you tell us
what number is ds^2 equal to on the sphere?

There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

I'm buying off Microsoft, did I tell you?

--
Jan Bielawski

On Mar 9, 12:37 pm, Koobee Wublee wrote:
On Mar 9, 12:10 am, JanPB wrote:



On Mar 8, 10:10 pm, Koobee Wublee wrote:
Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

Where is the number? You said ds^2 was a scalar. Which number is ds^2
equal to on the sphere? Either write down the actual number or say
that you were wrong.

Oh, no. I am not wrong on this one.

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

The dq_1 and dq_2, as you call them, are not specifiable. Which is the
whole point.


There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

On Mar 9, 1:37 pm, Koobee Wublee wrote:
On Mar 9, 12:10 am, JanPB wrote:



On Mar 8, 10:10 pm, Koobee Wublee wrote:
Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

Where is the number? You said ds^2 was a scalar. Which number is ds^2
equal to on the sphere? Either write down the actual number or say
that you were wrong.

Oh, no. I am not wrong on this one.

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

I was thinking ds=0, which is true for light,
then take the path on/at an event horizon so
the light is a world line around a sphere.
Of course ds being a differential can't be
non-zero.
Regards
Ken S. Tucker

On Mar 9, 2:45 pm, JanPB wrote:
On Mar 9, 2:37 pm, Koobee Wublee wrote:
On Mar 8, 10:10 pm, Koobee Wublee wrote:

Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

You said ds^2 was a scalar.

Yes, I did. Thank your for repeating it many times. You must know
that by heart by now.

If this is so, then why can't you tell us
what number is ds^2 equal to on the sphere?

I told you already. As soon as you can give me the numbers for these
elements, I can give you a number. What are these numbers again?

There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

I'm buying off Microsoft, did I tell you?

Please keep on dreaming, you majesty. It is also good for your sanity
to dream about your fat castle in the air able to withstand more than
200 years of nonsense, BS, and lies.

On Mar 9, 7:50 pm, Koobee Wublee wrote:
On Mar 9, 2:45 pm, JanPB wrote:



On Mar 9, 2:37 pm, Koobee Wublee wrote:
On Mar 8, 10:10 pm, Koobee Wublee wrote:
Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

You said ds^2 was a scalar.

Yes, I did. Thank your for repeating it many times. You must know
that by heart by now.

If this is so, then why can't you tell us
what number is ds^2 equal to on the sphere?

I told you already. As soon as you can give me the numbers for these
elements, I can give you a number. What are these numbers again?

There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

I'm buying off Microsoft, did I tell you?

Please keep on dreaming, you majesty. It is also good for your sanity
to dream about your fat castle in the air able to withstand more than
200 years of nonsense, BS, and lies.

Say KW, I think JanPB through us a nifty
problem. What's the physics?
Regards
Ken S. Tucker

On Mar 9, 8:50 pm, Koobee Wublee wrote:
On Mar 9, 2:45 pm, JanPB wrote:



On Mar 9, 2:37 pm, Koobee Wublee wrote:
On Mar 8, 10:10 pm, Koobee Wublee wrote:
Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

You said ds^2 was a scalar.

Yes, I did. Thank your for repeating it many times. You must know
that by heart by now.

If this is so, then why can't you tell us
what number is ds^2 equal to on the sphere?

I told you already. As soon as you can give me the numbers for these
elements, I can give you a number. What are these numbers again?

You said ds^2 was a scalar. That means it gives you a number once you
give it a point. Can you tell me why you cannot answer this question?

--
Jan Bielawski