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#41
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On Feb 7, 5:08 am, Albertito wrote:
On 6 feb, 20:10, Randy Poe wrote: On Feb 6, 2:57 pm, Albertito wrote: On 6 feb, 19:15, Randy Poe wrote: On Feb 6, 2:00 pm, Albertito wrote: On 6 feb, 18:54, Randy Poe wrote: On Feb 6, 12:39 pm, Albertito wrote: On 6 feb, 16:48, "Androcles" wrote: wrote in message ... On 6 fév, 02:34, Pentcho Valev wrote: http://philipball.blogspot.com/2007/...-was-innocent-... "With the technology then available, measuring the bending of starlight was very challenging. And contrary to popular belief, Newtonian physics did not predict that light would remain undeflected - Einstein himself pointed out in 1911 that Newtonian gravity should cause some deviation too. So the matter was not that of an all-or- nothing shift in stars' positions, but hinged on the exact numbers." | Right. | Classical Newtonian mechanics predicts that light will bend with | twice the angle observed. How? I'll tell you how. In order to see how newtonian gravity can bend the trajectory of a photon, relativists fake it. They magically tranform a photon with energy E into a particle with mass m = E/2c^2, it is saying half the mass in E = mc^2. Then, relativists assume that particle passes by the massive body from infinity travelling locally at c, and then they can apply newtonian gravity to see how its trajectory is deflected into a hyperbolic one. As a result there is a deflection angle twice the observed one. A particle with mass m = E/c^2, travelling locally at c from infinity, would be deflected in the correct angle, under newtonian gravity. Why don't you do the Newtonian calculation before making this claim? - Randy The calculations have been already done by you relativists,http://www.theory.caltech.edu/people.../obsertop.html Correct. I'm only witness of that, and I see that if we double the mass assumed for a photon we attain the correct answer. There are a great many assumptions in those equations which you are not aware of. You are trying to change the meaning of the symbols midstream. Here's what those orbital mechanics equations look like for planetary orbits:http://www.go.ednet.ns.ca/~larry/orbits/kepler.html Note that E is the sum of kinetic energy and potential energy. So what are you going to use for this E? Do you really want to use mc^2 and claim it's a Newtonian model? If you were doing Newtonian gravitation the way Newton did it to calculate the planetary orbits, you'd say the kinetic energy is (1/2)*mc^2, and the potential energy is -GMm/r. Then you'd find out that the mass m drops out, that is the parameter E/m = [c^2/2 - GM/r] does not depend on m. Let's start from the basics: What is the initial velocity, what is the acceleration, what is the result? Start out with a velocity c, mass m, distance R as it passes near mass M. The acceleration experienced by the mass m is GM/R^2. That is what you would apply to the velocity vector to get the change in velocity. It does not depend on m. Trajectories of small bodies through solar systems do not depend on mass. It's simpler than that. Under newtonian gravity you never can say that a photon is predicted to be deflected by twice the correct angle, because under newtonian gravity photons can't be addressed at all, only bodies with mass. Right. Unless you assume it has mass, as people did long before Einstein. Once you do, the path is independent of whatever mass you assume, just as any Newtonian path is. You never can fake a photon to behave as a particle with non-zero mass, that's unphysical. If you do fake a photon to behave so, then you attain a particle with mass travelling at c, which is impossible under your assumptions (i.e nothing with mass can travel at c). What point are you trying to make? If the photon truly has no mass (as we believe) then the Newtonian model says it won't be deflected. Therefore gravitational lensing won't happen. To claim that a theory predicts a photon will not be deflected and to claim photons are outside the domain of applicability of a theory are not the same claim. Photons are outside the domain of applicability of newtonian gravity. If massless. This is part of the standard model and would certainly upset a lot of modern physics if false, but it's still a caveat in all your statements, an assumption you're making. Thus the only theory which predicts deflection of photons in gravitational fields (to date) is GR. Are we agreeing on this? If so, I can't figure out what anti-relativistic stance you're trying to make. Therefore, newtonian gravity gives no answers to questions concerning photons. Unless you assume gravitational mass which is nonzero. Once you do, you get a deflection which is half the GR prediction. What YOU stated was that the deflection depends on the assumed mass. It does not. YOU are the one claiming that a Newtonian calculation is possible which will show deflection, if you assume the right mass. Are you backing off of that? Newtonian gravity is concerned with neutral bulk matter, not with bosons. Newtonian gravity is concerned with anything with mass. Even if it were found out that photons have mass, newtonian gravity would still remain without answers for them, because they would still be bosons. ??? And where are you getting this from? So what's your point? Are you backing off your claim that the evil relativists goofed on the Newtonian calculation and if they did it right, Newtonian gravity would predict the correct deflection? Because that seems to contradict this post. - Randy |
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#42
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On 7 feb, 14:55, Randy Poe wrote:
On Feb 7, 5:08 am, Albertito wrote: On 6 feb, 20:10, Randy Poe wrote: On Feb 6, 2:57 pm, Albertito wrote: On 6 feb, 19:15, Randy Poe wrote: On Feb 6, 2:00 pm, Albertito wrote: On 6 feb, 18:54, Randy Poe wrote: On Feb 6, 12:39 pm, Albertito wrote: On 6 feb, 16:48, "Androcles" wrote: wrote in message ... On 6 fév, 02:34, Pentcho Valev wrote: http://philipball.blogspot.com/2007/...-was-innocent-... "With the technology then available, measuring the bending of starlight was very challenging. And contrary to popular belief, Newtonian physics did not predict that light would remain undeflected - Einstein himself pointed out in 1911 that Newtonian gravity should cause some deviation too. So the matter was not that of an all-or- nothing shift in stars' positions, but hinged on the exact numbers." | Right. | Classical Newtonian mechanics predicts that light will bend with | twice the angle observed. How? I'll tell you how. In order to see how newtonian gravity can bend the trajectory of a photon, relativists fake it. They magically tranform a photon with energy E into a particle with mass m = E/2c^2, it is saying half the mass in E = mc^2. Then, relativists assume that particle passes by the massive body from infinity travelling locally at c, and then they can apply newtonian gravity to see how its trajectory is deflected into a hyperbolic one. As a result there is a deflection angle twice the observed one. A particle with mass m = E/c^2, travelling locally at c from infinity, would be deflected in the correct angle, under newtonian gravity. Why don't you do the Newtonian calculation before making this claim? - Randy The calculations have been already done by you relativists,http://www.theory.caltech.edu/people.../obsertop.html Correct. I'm only witness of that, and I see that if we double the mass assumed for a photon we attain the correct answer. There are a great many assumptions in those equations which you are not aware of. You are trying to change the meaning of the symbols midstream. Here's what those orbital mechanics equations look like for planetary orbits:http://www.go.ednet.ns.ca/~larry/orbits/kepler.html Note that E is the sum of kinetic energy and potential energy. So what are you going to use for this E? Do you really want to use mc^2 and claim it's a Newtonian model? If you were doing Newtonian gravitation the way Newton did it to calculate the planetary orbits, you'd say the kinetic energy is (1/2)*mc^2, and the potential energy is -GMm/r. Then you'd find out that the mass m drops out, that is the parameter E/m = [c^2/2 - GM/r] does not depend on m. Let's start from the basics: What is the initial velocity, what is the acceleration, what is the result? Start out with a velocity c, mass m, distance R as it passes near mass M. The acceleration experienced by the mass m is GM/R^2. That is what you would apply to the velocity vector to get the change in velocity. It does not depend on m. Trajectories of small bodies through solar systems do not depend on mass. It's simpler than that. Under newtonian gravity you never can say that a photon is predicted to be deflected by twice the correct angle, because under newtonian gravity photons can't be addressed at all, only bodies with mass. Right. Unless you assume it has mass, as people did long before Einstein. Once you do, the path is independent of whatever mass you assume, just as any Newtonian path is. You never can fake a photon to behave as a particle with non-zero mass, that's unphysical. If you do fake a photon to behave so, then you attain a particle with mass travelling at c, which is impossible under your assumptions (i.e nothing with mass can travel at c). What point are you trying to make? If the photon truly has no mass (as we believe) then the Newtonian model says it won't be deflected. Therefore gravitational lensing won't happen. To claim that a theory predicts a photon will not be deflected and to claim photons are outside the domain of applicability of a theory are not the same claim. Photons are outside the domain of applicability of newtonian gravity. If massless. This is part of the standard model and would certainly upset a lot of modern physics if false, but it's still a caveat in all your statements, an assumption you're making. Thus the only theory which predicts deflection of photons in gravitational fields (to date) is GR. Are we agreeing on this? Yes, GR tries to predict deflection of photons, and it works nearly fine :-) If so, I can't figure out what anti-relativistic stance you're trying to make. Are you seeing in my stance any anti-relativist fashion?. I only say that newtonian gravity can't address bosons, and that it is not correct claiming that newtonian gravity predicts half the correct deflection angle. Even for W(+), W(-) and Z bosons, which have mass, newtonian gravity can't predict their respective deflection angles. Bosons are outside the domain of applicability of newtonian gravity. Therefore, newtonian gravity gives no answers to questions concerning photons. Unless you assume gravitational mass which is nonzero. Once you do, you get a deflection which is half the GR prediction. No. It is clear that gravity behaves differently for fermions that for bosons (included bosons with nonzero mass). What YOU stated was that the deflection depends on the assumed mass. It does not. YOU are the one claiming that a Newtonian calculation is possible which will show deflection, if you assume the right mass. Are you backing off of that? No, I only said that if you can say that newtonian gravity predicts half the correct angle, then I could also say that newtonian gravity can predict the correct angle if you assume the right mass for a fake photon. Newtonian gravity is concerned with neutral bulk matter, not with bosons. Newtonian gravity is concerned with anything with mass. No. Newtonian gravity is not concerned with bosons, regardless they are massless or not. Even if it were found out that photons have mass, newtonian gravity would still remain without answers for them, because they would still be bosons. ??? And where are you getting this from? This should need a new dedicated thread to explain you where :-) . But, I'll give you a clue. Pauli exclusion principle. So what's your point? Are you backing off your claim that the evil relativists goofed on the Newtonian calculation and if they did it right, Newtonian gravity would predict the correct deflection? Because that seems to contradict this post. No, see above |
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#43
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On Feb 7, 11:11 am, Albertito wrote:
On 7 feb, 14:55, Randy Poe wrote: Thus the only theory which predicts deflection of photons in gravitational fields (to date) is GR. Are we agreeing on this? Yes, GR tries to predict deflection of photons, and it works nearly fine :-) Where does it fail in predicting deflection of photons? If so, I can't figure out what anti-relativistic stance you're trying to make. Are you seeing in my stance any anti-relativist fashion?. Yes. Since you've been on the newsgroup. In practically every post. I only say that newtonian gravity can't address bosons, and that it is not correct claiming that newtonian gravity predicts half the correct deflection angle. Even for W(+), W(-) and Z bosons, which have mass, newtonian gravity can't predict their respective deflection angles. Bosons are outside the domain of applicability of newtonian gravity. Why do you declare this? Newtonian gravity predicts the interaction of masses. What is special about these masses that makes them exempt? Therefore, newtonian gravity gives no answers to questions concerning photons. Unless you assume gravitational mass which is nonzero. Once you do, you get a deflection which is half the GR prediction. No. It is clear that gravity behaves differently for fermions that for bosons (included bosons with nonzero mass). It is clear from what? Show your reasoning. By "Newtonian gravity" you still seem to have something other than F = GMm/r^2 in mind, since that is silent on fermions, bosons, or any property other than mass. What YOU stated was that the deflection depends on the assumed mass. It does not. YOU are the one claiming that a Newtonian calculation is possible which will show deflection, if you assume the right mass. Are you backing off of that? No, I only said that if you can say that newtonian gravity predicts half the correct angle, then I could also say that newtonian gravity can predict the correct angle if you assume the right mass for a fake photon. Ah... finally we get to an assertion about Newtonian gravity. So the answer is "Yes", not "No". You claim that you could do a Newtonian prediction with a different mass and get a different deflection. Or by saying "can predict the correct angle" you don't really mean getting a different answer from "half the correct angle". Once again, you are saying that if you change the mass, you'll get a different angle. Yes? Fine. The answer is No. Not in standard Newtonian mechanics. There is nothing about the trajectory of small masses near large ones which depends on the small mass. What you are talking about is the parameter E/m, the ratio of total energy (kinetic plus gravitational potential) to mass. In Newtonian mechanics, KE = 0.5*mv^2. So there is no possible ratio E/m except [0.5*v^2 - GM/r], a quantity which you will note does not depend on m. Now, what you are REALLY claiming is that if we use E/m = c^2, then the "Newtonian" prediction would be a different angle. Look at the web page you cited again. On that I certainly agree. But that's not Newtonian mechanics. You are using a non-Newtonian expression for KE. If you use Newtonian mechanics, then E/m = c^2 for any mass moving at c. And if you don't change E/m, then what happens to those formulas you were looking at? I tried to get you to see this by talking about planetary orbits. The orbital parameters of a satellite around the earth, or of a planet around the sun, do NOT depend on the mass of the satellite/planet. You won't get a different trajectory by changing mass. - Randy Even if it were found out that photons have mass, newtonian gravity would still remain without answers for them, because they would still be bosons. ??? And where are you getting this from? This should need a new dedicated thread to explain you where :-) . But, I'll give you a clue. Pauli exclusion principle. Your hint fails. Newtonian gravity is silent on the Pauli exclusion principle, as Pauli is silent on gravitational potential between two masses. There is no relation between these things. If you think otherwise, state why. In a new thread if you like. But one small sanity check: Do you really think it should be called "Newtonian mechanics" if it includes the Pauli exclusion principle? - Randy |
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#44
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wrote in message ... On 6 fév, 18:03, "Androcles" wrote: wrote in message ... On 6 fév, 16:36, "Androcles" wrote: wrote in message ... On 6 fév, 15:04, "Androcles" wrote: wrote in message ... On 6 fév, 12:15, "Androcles" wrote: wrote in message ... On 6 fév, 11:48, "Androcles" wrote: wrote in message ... On 6 fév, 02:34, Pentcho Valev wrote: http://philipball.blogspot.com/2007/...-was-innocent-... "With the technology then available, measuring the bending of starlight was very challenging. And contrary to popular belief, Newtonian physics did not predict that light would remain undeflected - Einstein himself pointed out in 1911 that Newtonian gravity should cause some deviation too. So the matter was not that of an all-or- nothing shift in stars' positions, but hinged on the exact numbers." | Right. | Classical Newtonian mechanics predicts that light will bend with | twice the angle observed. How? | Lapsus. Its the reverse. | I meant to write half the angle observed. and for corrected | relativistic | Newtonian, the angle is twice that of classical Newtonian, as is | observed. Ok, but my real question is how does classical Newtonian mechanics prophesy that light will bend at all? It does, I'm wondering if you, Eddington or Einstein knows how. | They certainly did since Einstein did the calculation himself. | And I do too. | Explained summarily, to proceed, for the requirements of | calculation he converted the energy of a photon to its | equivalent mass (m=E/c^2) and proceeded to calculate | the deflection of theoretical "masses" for visible light | photons as they grazed the Sun mass. | This gave half the deflection angle that was later observed. | His calculations are in a paper from 1911 titled | "Über den Einfluß der Schwerkraft auf die Ausbreitung | des Lichter" | He later 1915 corrected the figures and obtained the | right deflection (twice that of classical Newtonian). | However, the same correct deflection angle can easily | be obtained from upgraded relativistic Newtonian, | something that has never been documented, since the | 1919 Eddington et al. observation was specifically | meant to prove the superiority of GR over classical | mechanics. | Just like the community never considered confirming | atomic clock speeding up with altitude with parallel | mechanical clocks experiments. | They were not looking for the truth, but to prove | a point. Androcles' third law: For every photon there is an equal and opposite rephoton. http://www.androcles01.pwp.blueyonde...k/rephoton.gif (from Newton's third law and Huygens's wave superposition, photons have direction and come in pairs) | My view is de Broglie's on photons. I see them as complex | standing harmonic oscillators in motion, with only half | their energy oscillating electromagnetically. The other | half is is oriented in the direction of motion and is | thus impervious to transverse force interaction. Whilst I concur with "harmonic oscillators in motion" http://www.androcles01.pwp.blueyonder.co.uk/AC/AC.gif http://www.androcles01.pwp.blueyonde.../AC/Photon.gif http://www.androcles01.pwp.blueyonder.co.uk/photon.gif | I see. Standing dephased pi/2. Of course... the magnetic field cannot be zero at the same time as the electric field or energy would not be conserved. E = -dB/dt | In 3D + time classical wave theory yes. Fine, that's the world I live in. | But with 9D + time Go away, crank, go live in your 9D universe. |
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#45
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On Feb 7, 4:35 am, wrote:
On 6 fév, 22:29, Eric Gisse wrote: On Feb 6, 2:10 pm, wrote: On 6 fév, 17:38, Eric Gisse wrote: On Feb 6, 6:33 am, wrote: On 6 fév, 02:34, Pentcho Valev wrote: http://philipball.blogspot.com/2007/...-was-innocent-... "With the technology then available, measuring the bending of starlight was very challenging. And contrary to popular belief, Newtonian physics did not predict that light would remain undeflected - Einstein himself pointed out in 1911 that Newtonian gravity should cause some deviation too. So the matter was not that of an all-or- nothing shift in stars' positions, but hinged on the exact numbers." Right. Classical Newtonian mechanics predicts that light will bend with twice the angle observed. Relativistic Newtonian mechanics however predicts the correct angle since it is now understood that only half a photon's energy is sensitive to transverse interaction. Uhhhhh....no. General relativity [is NOT "relativistic Newtonian mechanics] makes the correct prediction So does relativistic Newtonian mechanics, in perfect harmony with Maxwell's theory. A relativistic Newtonian mechanics is a contradiction in terms. The fact is that general relativity makes the predictions about light bending /without/ reference to Maxwell's equations or anything about light /other/ than it traveling on a null path. Any theory that predicts anything about light without reference to electromagnetism and Maxwell can only be a mathematical patchwork doomed to end up in file 13. Where do you think the massless assumption came from? You could, in theory, solve the field equations for a electromagnetic stress-energy tensor with a plane wave solution. Good luck solving that. Is there a particular reason you can't open up a textbook, see the derivation, repeat the derivation, and compare with observation? I have and have rejected the method. I have a much better integrated one that can even explain the stuff that GR can't deal with. If you still don't understand how GR can make the predictions it does and that it doesn't assume the things you don't think it does, no, you haven't. Work on the mundane before you attack the subtle. If your theory can't explain prosaic effects like perihelion precession, why would it accurately explain whatever fringe effect you are focusing on this time? André Michaud |
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#46
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On Feb 7, 4:28 am, wrote:
On 7 fév, 01:27, "Timo A. Nieminen" wrote: On Wed, 6 Feb 2008, wrote: On 6 fév, 17:38, Eric Gisse wrote: On Feb 6, 6:33 am, wrote: Classical Newtonian mechanics predicts that light will bend with twice the angle observed. Relativistic Newtonian mechanics however predicts the correct angle since it is now understood that only half a photon's energy is sensitive to transverse interaction. Uhhhhh....no. General relativity [is NOT "relativistic Newtonian mechanics] makes the correct prediction So does relativistic Newtonian mechanics, in perfect harmony with Maxwell's theory. OK, I'll bite. What is "relativistic Newtonian mechanics"? How is it in perfect harmony with Maxwell's theory? To clarify, do you mean _Maxwell's_ theory, or do you mean modern classical electrodynamics? I mean Maxwell's wave theory. The point is that Maxwell's theory can be seamlessly expanded, contrary to belief, from a disregarded de Broglie hypothesis, to directly describe localized photons and by linking it with classical Newton, to also describe localized massive particles, moving or not. No, it can't. Maxwell's equations are incompatible with all of quantum theory. I'll gladly revise my opinion when you show a published work supporting your assertions. You were kind enough to insist on only published works when complaining that nobody has tested GR's predictions with a mechanical clock - it's only fair. But I'll settle for anything that contains the math. And by "math" I mean ALL FOUR of Maxwell's equations. Now as to what it is, this media couldn't possibly allow full explanation. but as an example, if you correct Newton's classical kinetic energy equation to correctly include the energy he could know nothing about and that goes into relativistic mass increase and if you convert it to its correct exponential form, you then end up with an equation that allows calculating the complete range of possible velocities, from zero for massive particles at rest to c for free photons not associated with massive particles. A hopeful set of words that doesn't have the requisite mathematics anywhere nearby. Here is a generalized form of this equation f(x)=c [sqrt(4ax + x^2)) / (2a - x)] where f(x) = velocity a = rest energy of a massive particle (electron) x = any energy you wish to associate to the electron. If you set a to zero (so no massive particle is involved) you end up with only the free energy, and velocity c If you set x to zero (no added energy), you end up with velocity zero for the massive particle. This is called a "dispersion relation". Would you care to show how you derive this? Any value of x other than zero will restitute the correct relativistic velocity of the massive particle. From this equation you can even derive another similar equation that allows calculating f(x) from the wavelength only and also the gamma factor to link up with SR's equations. Ordinary Newtonian mechanics is in perfect harmony with Maxwell's theory, You must be kidding! Explain to me how straight k=1/2 mv^2 is in harmony with Maxwell's theory. André Mchaud although not with modern classical EM. -- Timo Nieminen - Home page:http://www.physics.uq.edu.au/people/nieminen/ E-prints:http://eprint.uq.edu.au/view/person/...,_Timo_A..html Shrine to Spirits:http://www.users.bigpond.com/timo_nieminen/spirits.html |
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#47
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On 7 fév, 13:26, Eric Gisse wrote:
On Feb 7, 4:35 am, wrote: On 6 fév, 22:29, Eric Gisse wrote: On Feb 6, 2:10 pm, wrote: On 6 fév, 17:38, Eric Gisse wrote: On Feb 6, 6:33 am, wrote: On 6 fév, 02:34, Pentcho Valev wrote: http://philipball.blogspot.com/2007/...-was-innocent-... "With the technology then available, measuring the bending of starlight was very challenging. And contrary to popular belief, Newtonian physics did not predict that light would remain undeflected - Einstein himself pointed out in 1911 that Newtonian gravity should cause some deviation too. So the matter was not that of an all-or- nothing shift in stars' positions, but hinged on the exact numbers." Right. Classical Newtonian mechanics predicts that light will bend with twice the angle observed. Relativistic Newtonian mechanics however predicts the correct angle since it is now understood that only half a photon's energy is sensitive to transverse interaction. Uhhhhh....no. General relativity [is NOT "relativistic Newtonian mechanics] makes the correct prediction So does relativistic Newtonian mechanics, in perfect harmony with Maxwell's theory. A relativistic Newtonian mechanics is a contradiction in terms. The fact is that general relativity makes the predictions about light bending /without/ reference to Maxwell's equations or anything about light /other/ than it traveling on a null path. Any theory that predicts anything about light without reference to electromagnetism and Maxwell can only be a mathematical patchwork doomed to end up in file 13. Where do you think the massless assumption came from? From ignorance of the nature of electromagnetic energy. You could, in theory, solve the field equations for a electromagnetic stress-energy tensor with a plane wave solution. Good luck solving that. The Copenhagen community's moto: Why make things simple when you can make them complicated ? Is there a particular reason you can't open up a textbook, see the derivation, repeat the derivation, and compare with observation? I have and have rejected the method. I have a much better integrated one that can even explain the stuff that GR can't deal with. If you still don't understand how GR can make the predictions it does and that it doesn't assume the things you don't think it does, no, you haven't. Work on the mundane before you attack the subtle. If your theory can't explain prosaic effects like perihelion precession, why would it accurately explain whatever fringe effect you are focusing on this time? You are so disconnected Eric that it edges on unconsciousness. Why don't you wake up. André Michaud |
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On 7 fév, 13:30, Eric Gisse wrote:
On Feb 7, 4:28 am, wrote: On 7 fév, 01:27, "Timo A. Nieminen" wrote: On Wed, 6 Feb 2008, wrote: On 6 fév, 17:38, Eric Gisse wrote: On Feb 6, 6:33 am, wrote: Classical Newtonian mechanics predicts that light will bend with twice the angle observed. Relativistic Newtonian mechanics however predicts the correct angle since it is now understood that only half a photon's energy is sensitive to transverse interaction. Uhhhhh....no. General relativity [is NOT "relativistic Newtonian mechanics] makes the correct prediction So does relativistic Newtonian mechanics, in perfect harmony with Maxwell's theory. OK, I'll bite. What is "relativistic Newtonian mechanics"? How is it in perfect harmony with Maxwell's theory? To clarify, do you mean _Maxwell's_ theory, or do you mean modern classical electrodynamics? I mean Maxwell's wave theory. The point is that Maxwell's theory can be seamlessly expanded, contrary to belief, from a disregarded de Broglie hypothesis, to directly describe localized photons and by linking it with classical Newton, to also describe localized massive particles, moving or not. No, it can't. Maxwell's equations are incompatible with all of quantum theory. As I said, you are so disconnected with reality. Perfect Copenhagen physicist material. Carry on. I'll gladly revise my opinion when you show a published work supporting your assertions. You were kind enough to insist on only published works when complaining that nobody has tested GR's predictions with a mechanical clock - it's only fair. How can you be so conceited as to think that I care whether or not you revise whatever opinion you have ? Just go your merry way blissfully believing anything you want. But I'll settle for anything that contains the math. And by "math" I mean ALL FOUR of Maxwell's equations. You will have to settle with vacuum. Like all orthodoxes, you will have to wait till your kids explain the stuff out to you from their intro physics refs. As more than once occurred in the past, the occidental physics community will be the last to try and play catch up when this blows over. Now as to what it is, this media couldn't possibly allow full explanation. but as an example, if you correct Newton's classical kinetic energy equation to correctly include the energy he could know nothing about and that goes into relativistic mass increase and if you convert it to its correct exponential form, you then end up with an equation that allows calculating the complete range of possible velocities, from zero for massive particles at rest to c for free photons not associated with massive particles. A hopeful set of words that doesn't have the requisite mathematics anywhere nearby. Not for your eyes, that's for sure. Here is a generalized form of this equation f(x)=c [sqrt(4ax + x^2)) / (2a - x)] where f(x) = velocity a = rest energy of a massive particle (electron) x = any energy you wish to associate to the electron. If you set a to zero (so no massive particle is involved) you end up with only the free energy, and velocity c If you set x to zero (no added energy), you end up with velocity zero for the massive particle. This is called a "dispersion relation". Would you care to show how you derive this? Please don't make me laugh too loud. My ribs hurt enough already from the excess snow shoveling I had to do lately. As you said, you will have to wait till formal publication, since peer pressure prevents any orthodox to even even think of stuff not formally published. This is called the classical kinetic energy equation upgraded to relativistic status. Ok, I'll be candid. I just plucked it out of my back pocket... or not! Maybe I just plucked it out of thin air. André Michaud Any value of x other than zero will restitute the correct relativistic velocity of the massive particle. From this equation you can even derive another similar equation that allows calculating f(x) from the wavelength only and also the gamma factor to link up with SR's equations. Ordinary Newtonian mechanics is in perfect harmony with Maxwell's theory, You must be kidding! Explain to me how straight k=1/2 mv^2 is in harmony with Maxwell's theory. André Mchaud although not with modern classical EM. -- Timo Nieminen - Home page:http://www.physics.uq.edu.au/people/nieminen/ E-prints:http://eprint.uq.edu.au/view/person/...,_Timo_A..html Shrine to Spirits:http://www.users.bigpond.com/timo_nieminen/spirits.html |
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On Feb 7, 10:51 am, wrote:
[...} Any theory that predicts anything about light without reference to electromagnetism and Maxwell can only be a mathematical patchwork doomed to end up in file 13. Where do you think the massless assumption came from? From ignorance of the nature of electromagnetic energy. Wrong, try again. 1) Solid research places error bars on photon mass at the 10^-17 eV level. Consistent with zero. 2) Maxwell's equations have no mass coupling. 3) Proca's equations - Maxwell's equations for a massive photon - are distinctly different from Maxwell's equations. You could, in theory, solve the field equations for a electromagnetic stress-energy tensor with a plane wave solution. Good luck solving that. The Copenhagen community's moto: Why make things simple when you can make them complicated ? You were the one bitching about me giving the simple answer. In the optics limit, Maxwell's equations do not matter so long as waves travel along null paths. If you want the exact answer, yea it's gonna be complicated. Pretending it isn't is dishonest. Is there a particular reason you can't open up a textbook, see the derivation, repeat the derivation, and compare with observation? I have and have rejected the method. I have a much better integrated one that can even explain the stuff that GR can't deal with. If you still don't understand how GR can make the predictions it does and that it doesn't assume the things you don't think it does, no, you haven't. Work on the mundane before you attack the subtle. If your theory can't explain prosaic effects like perihelion precession, why would it accurately explain whatever fringe effect you are focusing on this time? You are so disconnected Eric that it edges on unconsciousness. Why don't you wake up. Why don't you prove your ability before making sweeping claims about the physics community? André Michaud |
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On Feb 7, 11:13 am, wrote:
On 7 fév, 13:30, Eric Gisse wrote: On Feb 7, 4:28 am, wrote: On 7 fév, 01:27, "Timo A. Nieminen" wrote: On Wed, 6 Feb 2008, wrote: On 6 fév, 17:38, Eric Gisse wrote: On Feb 6, 6:33 am, wrote: Classical Newtonian mechanics predicts that light will bend with twice the angle observed. Relativistic Newtonian mechanics however predicts the correct angle since it is now understood that only half a photon's energy is sensitive to transverse interaction. Uhhhhh....no. General relativity [is NOT "relativistic Newtonian mechanics] makes the correct prediction So does relativistic Newtonian mechanics, in perfect harmony with Maxwell's theory. OK, I'll bite. What is "relativistic Newtonian mechanics"? How is it in perfect harmony with Maxwell's theory? To clarify, do you mean _Maxwell's_ theory, or do you mean modern classical electrodynamics? I mean Maxwell's wave theory. The point is that Maxwell's theory can be seamlessly expanded, contrary to belief, from a disregarded de Broglie hypothesis, to directly describe localized photons and by linking it with classical Newton, to also describe localized massive particles, moving or not. No, it can't. Maxwell's equations are incompatible with all of quantum theory. As I said, you are so disconnected with reality. Perfect Copenhagen physicist material. Carry on. I'll gladly revise my opinion when you show a published work supporting your assertions. You were kind enough to insist on only published works when complaining that nobody has tested GR's predictions with a mechanical clock - it's only fair. How can you be so conceited as to think that I care whether or not you revise whatever opinion you have ? Just go your merry way blissfully believing anything you want. But I'll settle for anything that contains the math. And by "math" I mean ALL FOUR of Maxwell's equations. You will have to settle with vacuum. Like all orthodoxes, you will have to wait till your kids explain the stuff out to you from their intro physics refs. As more than once occurred in the past, the occidental physics community will be the last to try and play catch up when this blows over. Now as to what it is, this media couldn't possibly allow full explanation. but as an example, if you correct Newton's classical kinetic energy equation to correctly include the energy he could know nothing about and that goes into relativistic mass increase and if you convert it to its correct exponential form, you then end up with an equation that allows calculating the complete range of possible velocities, from zero for massive particles at rest to c for free photons not associated with massive particles. A hopeful set of words that doesn't have the requisite mathematics anywhere nearby. Not for your eyes, that's for sure. Here is a generalized form of this equation f(x)=c [sqrt(4ax + x^2)) / (2a - x)] where f(x) = velocity a = rest energy of a massive particle (electron) x = any energy you wish to associate to the electron. If you set a to zero (so no massive particle is involved) you end up with only the free energy, and velocity c If you set x to zero (no added energy), you end up with velocity zero for the massive particle. This is called a "dispersion relation". Would you care to show how you derive this? Please don't make me laugh too loud. My ribs hurt enough already from the excess snow shoveling I had to do lately. As you said, you will have to wait till formal publication, since peer pressure prevents any orthodox to even even think of stuff not formally published. You were the one being all butthurt about there not being an explicit publication about mechanical clocks testing relativity, I'm just returning the favor. Irritating, isn't it? This is called the classical kinetic energy equation upgraded to relativistic status. In other words, you are using special relativity else you are being internally inconsistent if you mix SR and Newton. Ok, I'll be candid. I just plucked it out of my back pocket... or not! Maybe I just plucked it out of thin air. André Michaud Any value of x other than zero will restitute the correct relativistic velocity of the massive particle. From this equation you can even derive another similar equation that allows calculating f(x) from the wavelength only and also the gamma factor to link up with SR's equations. Ordinary Newtonian mechanics is in perfect harmony with Maxwell's theory, You must be kidding! Explain to me how straight k=1/2 mv^2 is in harmony with Maxwell's theory. André Mchaud although not with modern classical EM. -- Timo Nieminen - Home page:http://www.physics.uq.edu.au/people/nieminen/ E-prints:http://eprint.uq.edu.au/view/person/...,_Timo_A..html Shrine to Spirits:http://www.users.bigpond.com/timo_ni.../spirits..html |