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| Tags: absorbemit, electrons, light, unbound |
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#1
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Hi,
I enrolled in a course about astronomical spectroscopy in my university. The lecturer made a remark which I don't fully understand and I'd appreciate your comments. We were discussing how electronic transitions produce specific absorption or emission lines. At some point he said that this was true for bound electrons but that not for unbound electrons, which wouldn't produce either absorption or emission, and that this was explained by both relativity and quantum mechanics. I can see that it should not be possible for an unbound electron to produce an absorption or emission line because an unbound electron can have any energy value, but then, shouldn't a cloud of unbound electrons be able to produce a continuous absorption from a source in the background? It is less clear to me whether the same cloud would be able to produce continuous emission because I don't see why they would spontaneously decelerate and emit photons. Also, which may be the relativistic and quantum mechanical reasons for these processes being forbidden? Many thanks in advance. Vivianne |
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#2
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On Jun 26, 10:58 am, wrote:
Hi, I enrolled in a course about astronomical spectroscopy in my university. The lecturer made a remark which I don't fully understand and I'd appreciate your comments. We were discussing how electronic transitions produce specific absorption or emission lines. At some point he said that this was true for bound electrons but that not for unbound electrons, which wouldn't produce either absorption or emission, and that this was explained by both relativity and quantum mechanics. I can see that it should not be possible for an unbound electron to produce an absorption or emission line because an unbound electron can have any energy value, but then, shouldn't a cloud of unbound electrons be able to produce a continuous absorption from a source in the background? It is less clear to me whether the same cloud would be able to produce continuous emission because I don't see why they would spontaneously decelerate and emit photons. Also, which may be the relativistic and quantum mechanical reasons for these processes being forbidden? Many thanks in advance. Vivianne It's not that unbound electrons cannot emit or absorb photons. It's that they do not display a discrete spectrum and can emit and absorb all frequencies and wavelengths, so their spectrum is continuous. Bound electrons in atoms only emit and absorb energies at certain values corresponding to differences in their shell energies, which are dependent on quantum numbers, and hence are discretely arranged. Free electrons are without such restrictions. The main difference is due to the presence of a potential energy in the Schrodinger equation for the bound electrons which is not there for the unbound. |
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#4
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On Jun 26, 7:58 am, wrote:
We were discussing how electronic transitions produce specific absorption or emission lines. At some point he said that this was true for bound electrons but that not for unbound electrons, which wouldn't produce either absorption or emission, and that this was explained by both relativity and quantum mechanics. [...] Also, which may be the relativistic and quantum mechanical reasons for these processes being forbidden? A free electron cannot emit photons. This is forbidden by the laws of conservation of momentum and energy. Suppose that in the initial state you have one free electron at rest. It's mass is m, its momentum is zero, and its energy is E=mc^2. Suppose that this electron emits a photon with momentum k. In the final state you have two particles: a photon with momentum k and energy c|k| and an electron with momentum -k (from the momentum conservation law) and energy E= sqrt(m^2c^4 + k^2c^2). The energy conservation law now reads mc^2 = c|k| + sqrt(m^2c^4 + k^2c^2) You can now see that this equation can be true only if k=0. But there are no photons with zero momentum and energy. So, the emission is impossible. Eugene. |
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#5
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On Jun 26, 12:50 pm, Sam Wormley wrote:
A free [unbound] electron cannot emit photons. This is forbidden by the laws of conservation of momentum and energy. Synchrotron Radiation http://hyperphysics.phy-astr.gsu.edu...nchrotron.html Electrons emitting synchrotron radiation are not free in my definition. There is a (magnetic) force acting on them. So, my analysis does not apply to this situation. I was talking about electrons moving freely in empty space. Eugene. |
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#6
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On Jun 26, 9:44 pm, Sam Wormley wrote:
wrote: Hi, I enrolled in a course about astronomical spectroscopy in my university. The lecturer made a remark which I don't fully understand and I'd appreciate your comments. We were discussing how electronic transitions produce specific absorption or emission lines. At some point he said that this was true for bound electrons but that not for unbound electrons, which wouldn't produce either absorption or emission, and that this was explained by both relativity and quantum mechanics. I can see that it should not be possible for an unbound electron to produce an absorption or emission line because an unbound electron can have any energy value, but then, shouldn't a cloud of unbound electrons be able to produce a continuous absorption from a source in the background? It is less clear to me whether the same cloud would be able to produce continuous emission because I don't see why they would spontaneously decelerate and emit photons. Also, which may be the relativistic and quantum mechanical reasons for these processes being forbidden? Many thanks in advance. Vivianne An electron doesn't need to be bound to a nucleus to absorb or emit photons. In the early universe up till about 380,000 years all the electrons were unbound and absorbing (and re-emitting) light. Consider the interior of stars--photons being absorbed and emitted by all those charged particles. More than just true. Electrons only emit and receive photons all the time. If you think about it its all hanging around the same basic idea again and again - every twist and turn, bending and fields created inside... Some of those spectrums are quantum and others are super :-)) |
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