The Curve Space in Maths

we all know, the force is multiplied by force is equal to work. It
is abstracted to be maths problem, it becomes dot product of vector ,
namely the inner procudt of vector.

namely : ¦Á£®¦Â=¦ò¦Á¦ò¦ò¦Â¦òcos¦Á,¦Â.

Also, the force is multiplied by moment of force, it also can be
abstracted to be maths problem, it becomes the vector problem, it is
the exterior product of vector.

namely: ¦ò¦Á¡Á¦Â¦ò=¦ò¦Á¦ò¦ò¦Â¦òsin¦Á,¦Â.

Also, to the Coulomb's law: F=kq1q2/r^2.we also abstract it into a
maths problem, and when we calculate it respective in a dot, a line,
an area,or a sphere.we can conclude the same result with by using the
Gauss's electric flux theorem.but from the maths principle,it is
contradiction,because from the title meaning, it cann't get into the
dot,the line (this can get the correct and the same result with by
using the Gauss's electric flux theorem),an area or a sphere(we use
the calculous -the double integral in maths to calculte it, we get the
result that it can get into the area or the shpere,and this result is
the same with using the Gauss's electric flux theorem).So all of it
shows we must create a new maths field to resolve this problem, this
is calculous in the curve space.

At the Gauss's electric flux theorem: it is false all.

So, the curve space in maths, we can defined it im maths as
following:

In right handed system in quadrature frame,namely in three
dimensional coordinate space:in X¡¢Y¡¢Z, r is the dot of function f(x)
of vector, r¡Êf(x¡¢Y¡¢Z).or is the vector that from the origin of
coordinates O to r. If any function F(x¡¢Y¡¢Z)£¬has the relation with the
origin of coordinates, namely:

F(x¡¢Y¡¢Z)=f(x¡¢Y¡¢Z)/or^2 £ûx¡¢Y¡¢Z¡ÊR£ý£¬comes into existence,it says
f(x¡¢Y¡¢Z) is in right handed system coordinate, it means there is a
only core in the origin coordinates and the three dimensional
coordinate in this space with the core in origin coordinate is a
curve sapce in maths.

The integral with the function to the origin coordinate ,
¡ÒF=¡Òf(x¡¢Y¡¢Z)/or^2d£¨x¡¢Y¡¢Z£© is the true calculous in curve sapce.

I have found this question 20 years ago, but up to now, no one still
find and support me.

caoyan

2007-5-2

Do you wonder why I want to create new maths field?
Calculous in curve space, I have found and studied this question for
over 20 years. It comes from this: the Coulomb's law F=kq1q2/r^2 and
the universal gravitation formula F=Km1m2/r^2, there are so
similitude. When we abstract these two formulas (F=kq1q2/r^2, F=Gm1m2/
r^2)into a pure maths problems, and then we use these two formulas as
the pure maths formulas and double integral to calculate the following
graph of functions : a dot point, a line, and an area. According to
the title meaning and the two formulas and the maths principles, we
know that the distance r cann't be equal to zero, that is to say we
can't get into the graph of functions--the dot point, the line, and
also the area. But the results of the calculation we get are as
following: we can't get into the dot point, it is true, because if the
distance r^2 is equal to zero, the two formulas will be null. and also
we can get the result that we can't get into the line, it is true
also, and it is accord with the maths principle, because if the
distance r is equal to zero, then also the result will be null. And
when we use the double integral to calculate the area, from the result
we conclude, we can get into the area, it is false I think, because it
is contradict with the maths principle and the two formulas. These
contradiction results not because of the we had made a mistake in the
course of calculation, it not also the physics, because it is nothing
to do with the physics, we have abstract the two formulas from the
physics, it is just a pure maths questions. The problem is ,I think,
the double integral, we have ignored the dx, dy,dz when we use the
double integral in the course of calculation. So we must have a new
maths field to resolve this problem. This is the reason I want to
create a new maths field.

It has great value: A it is a new maths field, it can resolve much
more proboems. B it can prove the false of the Gauss's electric flux
theorem, and it can prove the unified field theory in physics, this
can get the thrid achievement of pyhsics after Newton and Einstein.

But this maths field need many many more scientists join and have
a push on it.

I am do the founder of this new maths field.

Everyone can have a try and test on it and then know whether I am
correct or incorrect.

caoyan

2007-5-6

calculous in the curve space theorem 1
Calculous in the curve space:

Throrem 1: Y=¡Òdxdx=1

The meaning of maths is as following (figure 1),



there is a line L above the X-axis, the line L is parallel with the X-
axis, dx is the distance from the line L to the X-axis, when dx¡ú0, it
means in the maths the line L is constantly close to the X-axis,
namely dx=1/¡Þ£¬and the length of the line L is : L¡ú¡Þ¡£


the meaning of the formula Y=¡Òdxdx

in the maths is :the area of the line L to the X-axis.

Namely L§çdx=(1/¡Þ)§ç¡Þ=1

So we can conclude: Y=¡Òdxdx=1

The theorem 1 is the first theorem in the calculous in the maths. The
theorem 1 shows: although the line has no area, we cann't say the
area of the line is zero. Because in every area which is unit 1 , it
is made up of much much more lines, and every area of the line is: L¡ú1/
¡Þ¡ú0£¬but it is not zero, it is two things.

The theorem 1 also shows, y is not the area of the line of X-axis, it
is just the area when the L¡úX-axis, the area from L to X-axis.

The theorem 1 tell us in the formula of calculus, even if a very very
less dx, we cann't think the dx is zero in the calculus, because the
dx is been integral, it is also a very big number: 1.
Cao's theory

2007-4-20

figuhttp://www.sunbo.com/bbs.php?
xname=A8QJCV0&action=xfile&bpos=24&bid=101&fname=7 29221_figure1.JPG

calculous in the curve space theorem 2
theorem 2

Dxdy=1,determine y=?

who can answer the y=?, who will be the great master in maths in the
world, who is willing to do it?

I am do the founder in the calculus in maths, here is the beginning of
the new maths field in the calculus.

caoyan

caoyanwh2003 wrote:

The Curve Space in Maths

we all know, the force is multiplied by force is equal to work.
[snip crap]

force = (mass)(displacement)/time(^2)
work = (mass)(displacement)^2/time(^2)
force^2 = (mass)^2(displacement)^2/time(^4)

Idiot.

--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2

On May 8, 2:31 am, caoyanwh2003 wrote:
The Curve Space in Maths

we all know, the force is multiplied by force is equal to work. It
is abstracted to be maths problem, it becomes dot product of vector ,
namely the inner procudt of vector.

namely : ¦Á£®¦Â=¦ò¦Á¦ò¦ò¦Â¦òcos¦Á,¦Â.

Also, the force is multiplied by moment of force, it also can be
abstracted to be maths problem, it becomes the vector problem, it is
the exterior product of vector.

namely: ¦ò¦Á¡Á¦Â¦ò=¦ò¦Á¦ò¦ò¦Â¦òsin¦Á,¦Â.

Also, to the Coulomb's law: F=kq1q2/r^2.we also abstract it into a
maths problem, and when we calculate it respective in a dot, a line,
an area,or a sphere.we can conclude the same result with by using the
Gauss's electric flux theorem.but from the maths principle,it is
contradiction,because from the title meaning, it cann't get into the
dot,the line (this can get the correct and the same result with by
using the Gauss's electric flux theorem),an area or a sphere(we use
the calculous -the double integral in maths to calculte it, we get the
result that it can get into the area or the shpere,and this result is
the same with using the Gauss's electric flux theorem).So all of it
shows we must create a new maths field to resolve this problem, this
is calculous in the curve space.

At the Gauss's electric flux theorem: it is false all.

So, the curve space in maths, we can defined it im maths as
following:

In right handed system in quadrature frame,namely in three
dimensional coordinate space:in X¡¢Y¡¢Z, r is the dot of function f(x)
of vector, r¡Êf(x¡¢Y¡¢Z).or is the vector that from the origin of
coordinates O to r. If any function F(x¡¢Y¡¢Z)£¬has the relation with the
origin of coordinates, namely:

F(x¡¢Y¡¢Z)=f(x¡¢Y¡¢Z)/or^2 £ûx¡¢Y¡¢Z¡ÊR£ý£¬comes into existence,it says
f(x¡¢Y¡¢Z) is in right handed system coordinate, it means there is a
only core in the origin coordinates and the three dimensional
coordinate in this space with the core in origin coordinate is a
curve sapce in maths.

The integral with the function to the origin coordinate ,
¡ÒF=¡Òf(x¡¢Y¡¢Z)/or^2d£¨x¡¢Y¡¢Z£© is the true calculous in curve sapce.

I have found this question 20 years ago, but up to now, no one still
find and support me.

caoyan

2007-5-2

I'm having trouble understanding your gibberish, but I think part of
the problem is that inner products and divergence operators have much
more generalized forms in curved spaces. You may need to look them
up.

Calculous in the Curve Space

Calculous in the Curve Space is diferent with the double integral,
it has much much more its own characteristic, principle, formula and
theorem.

such as:

Calculous in the Curve Space formula

F=¡Òdxdx £¬

F=¡Ò(1/dx)dx

F=¡Ò(x+dx)dx £¬

F=¡Ò1/(x+dx)dx £¬

F=¡Òf(x)/(x+dx)^(2/3)dx ¡£

......

¡ÒF=¡Ò[f(x¡¢Y¡¢Z)/or^2]d£¨x¡¢Y¡¢Z£©£¬

etc, I call it cao's theory here.



In these integral formula, there are all dx in them, because dx
tends infinitesimal.At present, in the double integral, we usually
deal dx as zero first, then calculate them.Thus, we get some
contradiction result. This all because of, although dx¡ú0, it doesn't
mean dx=0.In the differential coefficient dx is a tending zero number,
it is a tiny figure, but in the integral, the tiny dx was been
integral, it is a very "big" number. so we cann't drop the tiny dx in
the integral formula.

If we want to resolve this problem, we must have a new maths
field, it is calculous in curve sapce.

¡ÒF=f(x¡¢Y¡¢Z)/or^2d£¨x¡¢Y¡¢Z£©£¬is calculous curve sapce in maths.It is
the beginning of the new maths field, calculous in curve sapce.

for example:

y=¡Òdxdx=1, not y=¡Òdxdx=0, this is the first theorem in calculous
in curve space.

F=¡Òf(x)/(x+dx)^(2/3)dx can prove the Unified Field Theory in
physics.

caoyan

2007-5-14

http://thre-firewh2.home.sunbo.net/

Calculous in the Curve Space

Calculous in the Curve Space is diferent with the double integral,
it has much much more its own characteristic, principle, formula and
theorem.

such as:

Calculous in the Curve Space formula

F=¡Òdxdx £¬

F=¡Ò(1/dx)dx

F=¡Ò(x+dx)dx £¬

F=¡Ò1/(x+dx)dx £¬

F=¡Òf(x)/(x+dx)^(2/3)dx ¡£

......

¡ÒF=¡Ò[f(x¡¢Y¡¢Z)/or^2]d£¨x¡¢Y¡¢Z£©£¬

etc, I call it cao's theory here.



In these integral formula, there are all dx in them, because dx
tends infinitesimal.At present, in the double integral, we usually
deal dx as zero first, then calculate them.Thus, we get some
contradiction result. This all because of, although dx¡ú0, it doesn't
mean dx=0.In the differential coefficient dx is a tending zero number,
it is a tiny figure, but in the integral, the tiny dx was been
integral, it is a very "big" number. so we cann't drop the tiny dx in
the integral formula.

If we want to resolve this problem, we must have a new maths
field, it is calculous in curve sapce.

¡ÒF=f(x¡¢Y¡¢Z)/or^2d£¨x¡¢Y¡¢Z£©£¬is calculous curve sapce in maths.It is
the beginning of the new maths field, calculous in curve sapce.

for example:

y=¡Òdxdx=1, not y=¡Òdxdx=0, this is the first theorem in calculous
in curve space.

F=¡Òf(x)/(x+dx)^(2/3)dx can prove the Unified Field Theory in
physics.

caoyan

2007-5-14

http://thre-firewh2.home.sunbo.net/