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#21
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Henri Wilson wrote: On 29 Oct 2006 06:00:20 -0800, "RP" wrote: Len Gaasenbeek wrote: "RP" wrote in message oups.com... Pentcho Valev wrote: In Appendix 3 in his "Relativity" Einstein starts from the time dilation factor 1/gamma = (1-v^2/c^2)^(1/2) and eventually deduces the frequency shift factor 1+V/c^2 where V is the gravitational potential. In the process Einstein replaces the time dilation factor 1/gamma with its Taylor approximation 1-v^2/2c^2 and for almost 100 years Einsteinians have been absolutely sure that this replacement can only be due to Einstein's genial intuition and sense of harmony. However lately Einsteinians with powerful intellects have been haunted by a difficult question: Why should the approximation 1-v^2/2c^2 be more suitable than the exact quantity 1/gamma? The inquiry is going to turn into a panic since the frequency shift factor 1+V/c^2 can be rigorously deduced from the principle of variability of the speed of light and this alternative deduction involves no suspicious approximations at all: http://www.physlink.com/Education/AskExperts/ae13.cfm : "So, it is absolutely true that the speed of light is _not_ constant in a gravitational field [which, by the equivalence principle, applies as well to accelerating (non-inertial) frames of reference]. If this were not so, there would be no bending of light by the gravitational field of stars. One can do a simple Huyghens reconstruction of a wave front, taking into account the different speed of advance of the wavefront at different distances from the star (variation of speed of light), to derive the deflection of the light by the star. Indeed, this is exactly how Einstein did the calculation in: "On the Influence of Gravitation on the Propagation of Light," Annalen der Physik, 35, 1911. which predated the full formal development of general relativity by about four years. This paper is widely available in English. You can find a copy beginning on page 99 of the Dover book "The Principle of Relativity." You will find in section 3 of that paper, Einstein's derivation of the (variable) speed of light in a gravitational potential, eqn (3). The result is, c' = c0 ( 1 + V / c^2 ) where V is the gravitational potential relative to the point where the speed of light c0 is measured." Einsteinians love Einstein passionately but, on the other hand, their honest hearts would not tolerate any trickery. As soon as they manage to understand why Einstein hid the obviously correct deduction VARIABLE SPEED OF LIGHT - FREQUENCY SHIFT and replaced it with the trumped-up deduction TIME DILATION - FREQUENCY SHIFT they will unmask him. There can be no doubt about that. Pentcho Valev Variable speed of light doesn't produce a Frequency shift. Try dropping a series of pebbles from an arbitrary altitude --1 pebble per second. Wrt you these will strike the ground at the same frequency, i.e. at 1 pebble per second, even though each of them accelerated on the way down. Wrt a ground obsever the frequency will be higher, thus requiring a ticking rate offset of his clock wrt the high altitude clock. Richard Perry .................................................. .................... To Richard Perry, Your statement above is not true. The frequency at which the pebbles fall will be the same for the person that dropped them as well as the ground observer which receives them. Len Gaasenbeek. This is too hard for a relativists to understand, Len. They rely on fairies to eat up the missing pebbles. Then how would you explain the gravitational red shift? The number of pebbles reaching the ground per second is the same for observers at the origin and on the ground. The frequency is constant for both observers, but they don't measure the same frequency. The distance between pebbles increases as they accelerate. However, if the pebbles have a distinct 'crystaline grain', the number of crystals reaching the GO per second increases with individual pebble speed Sure, but the two observers will not measure the same frequency of crystals passing by. Light is a series of waves whose maxima are not mechanically coupled together, and the pebble frequency is thus a better analogy. In the case of the individual crystals of the pebble, there are electromagnetic binding forces to consider. The tendency of gravity is to stretch the crystal along the vertical direction, because the gravitational force is slightly greater on the bottom of the pebble than the top. The electromagnetic forces prevent the separation of the crystals within the pebble. That's too hard for you to understand though. Thus, if a high laser fires 0.4um pulses of light towards the ground at a rate of 1 per second, they will reach the ground at the same rate of 1 per second. However because the pulses accelerate slightly on the way down, the frequency of the individual photons that make up the pulses will also be slightly blue-shifted. In which case there would be no gravitational clock ticking rate offset. Just because relativists in general tend to ascribe the gravitational redshift to a decrease in the energy of the photons on their way out of a gravitational well, this doesn't make it an actual prediction of the theory. Light is massless, and thus has no gravitational potential to alter. My theory says that, as with the pebbles, the photons themselves do not stretch although the average 'spacing between photons' increases. My theory says that there are no photons to stretch. The wavelength will increase. A simple model can be formulated using sound waves propagating upward or downward through the atmosphere. If the detector is at rest wrt the source, the latter of which is at a high altitude and the former on the ground, then the wavelength will change over their course, but no frequency shift will be detected. Thus the only way to get a frequency shift wrt the two observers in this situation is to have the observers clocks tick at different rates. They will then measure different frequencies of the same wave. Richard Perry Richard Perry HW. www.users.bigpond.com/hewn/index.htm The difference between a preacher and a used car salesman is that the latter's product doesn't fall apart till AFTER the sale. |
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"Henri Wilson" HW@.. wrote in message ... | On 29 Oct 2006 06:00:20 -0800, "RP" wrote: | Then how would you explain the gravitational red shift? | | The number of pebbles reaching the ground per second is the same for observers | at the origin and on the ground. The distance between pebbles increases as they | accelerate. | However, if the pebbles have a distinct 'crystaline grain', the number of | crystals reaching the GO per second increases with individual pebble speed. | | Thus, if a high laser fires 0.4um pulses of light towards the ground at a rate | of 1 per second, they will reach the ground at the same rate of 1 per second. ****ing nonsense. Rate of emission is not rate of reception or there would be no shift, ****ing stupid wabo, and in any event what you describe would be blue shift. |
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#23
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On 1 Nov 2006 16:06:37 -0800, "RP" wrote:
Henri Wilson wrote: On 29 Oct 2006 06:00:20 -0800, "RP" wrote: Len Gaasenbeek wrote: "RP" wrote in message oups.com... Pentcho Valev wrote: In Appendix 3 in his "Relativity" Einstein starts from the time dilation factor 1/gamma = (1-v^2/c^2)^(1/2) and eventually deduces the frequency shift factor 1+V/c^2 where V is the gravitational potential. In the process Einstein replaces the time dilation factor 1/gamma with its Taylor approximation 1-v^2/2c^2 and for almost 100 years Einsteinians have been absolutely sure that this replacement can only be due to Einstein's genial intuition and sense of harmony. However lately Einsteinians with powerful intellects have been haunted by a difficult question: Why should the approximation 1-v^2/2c^2 be more suitable than the exact quantity 1/gamma? The inquiry is going to turn into a panic since the frequency shift factor 1+V/c^2 can be rigorously deduced from the principle of variability of the speed of light and this alternative deduction involves no suspicious approximations at all: http://www.physlink.com/Education/AskExperts/ae13.cfm : "So, it is absolutely true that the speed of light is _not_ constant in a gravitational field [which, by the equivalence principle, applies as well to accelerating (non-inertial) frames of reference]. If this were not so, there would be no bending of light by the gravitational field of stars. One can do a simple Huyghens reconstruction of a wave front, taking into account the different speed of advance of the wavefront at different distances from the star (variation of speed of light), to derive the deflection of the light by the star. Indeed, this is exactly how Einstein did the calculation in: "On the Influence of Gravitation on the Propagation of Light," Annalen der Physik, 35, 1911. which predated the full formal development of general relativity by about four years. This paper is widely available in English. You can find a copy beginning on page 99 of the Dover book "The Principle of Relativity." You will find in section 3 of that paper, Einstein's derivation of the (variable) speed of light in a gravitational potential, eqn (3). The result is, c' = c0 ( 1 + V / c^2 ) where V is the gravitational potential relative to the point where the speed of light c0 is measured." Einsteinians love Einstein passionately but, on the other hand, their honest hearts would not tolerate any trickery. As soon as they manage to understand why Einstein hid the obviously correct deduction VARIABLE SPEED OF LIGHT - FREQUENCY SHIFT and replaced it with the trumped-up deduction TIME DILATION - FREQUENCY SHIFT they will unmask him. There can be no doubt about that. Pentcho Valev Variable speed of light doesn't produce a Frequency shift. Try dropping a series of pebbles from an arbitrary altitude --1 pebble per second. Wrt you these will strike the ground at the same frequency, i.e. at 1 pebble per second, even though each of them accelerated on the way down. Wrt a ground obsever the frequency will be higher, thus requiring a ticking rate offset of his clock wrt the high altitude clock. Richard Perry .................................................. .................... To Richard Perry, Your statement above is not true. The frequency at which the pebbles fall will be the same for the person that dropped them as well as the ground observer which receives them. Len Gaasenbeek. This is too hard for a relativists to understand, Len. They rely on fairies to eat up the missing pebbles. Then how would you explain the gravitational red shift? The number of pebbles reaching the ground per second is the same for observers at the origin and on the ground. The frequency is constant for both observers, but they don't measure the same frequency. In your ****ing dreams. The distance between pebbles increases as they accelerate. However, if the pebbles have a distinct 'crystaline grain', the number of crystals reaching the GO per second increases with individual pebble speed Sure, but the two observers will not measure the same frequency of crystals passing by. Who said? Light is a series of waves whose maxima are not mechanically coupled together, and the pebble frequency is thus a better analogy. In the case of the individual crystals of the pebble, there are electromagnetic binding forces to consider. The tendency of gravity is to stretch the crystal along the vertical direction, because the gravitational force is slightly greater on the bottom of the pebble than the top. The electromagnetic forces prevent the separation of the crystals within the pebble. That's too hard for you to understand though. It's too negligible to worry about. Thus, if a high laser fires 0.4um pulses of light towards the ground at a rate of 1 per second, they will reach the ground at the same rate of 1 per second. However because the pulses accelerate slightly on the way down, the frequency of the individual photons that make up the pulses will also be slightly blue-shifted. In which case there would be no gravitational clock ticking rate offset. It doesn't exist. Just because relativists in general tend to ascribe the gravitational redshift to a decrease in the energy of the photons on their way out of a gravitational well, this doesn't make it an actual prediction of the theory. Light is massless, and thus has no gravitational potential to alter. Whether it is massless or not, it accelerates down a a gravity well like anything else. My theory says that, as with the pebbles, the photons themselves do not stretch although the average 'spacing between photons' increases. My theory says that there are no photons to stretch. The wavelength will increase. A simple model can be formulated using sound waves propagating upward or downward through the atmosphere. ] so you think light is like sound, eh? If the detector is at rest wrt the source, the latter of which is at a high altitude and the former on the ground, then the wavelength will change over their course, but no frequency shift will be detected. There will be no frequency shift in the case of a generated radio signal but individual photons that make up a light beam WILL accelerate and therefore show a frequency increase.....frequency being the rate at which the intrinsic 'nodes' of the photon pass the observer. Thus the only way to get a frequency shift wrt the two observers in this situation is to have the observers clocks tick at different rates. They will then measure different frequencies of the same wave. Clocks are not affected by velocity changes and any change in rate in different gravity potentials is an indication that the clock has actually physically changed. Richard Perry Richard Perry HW. www.users.bigpond.com/hewn/index.htm The difference between a preacher and a used car salesman is that the latter's product doesn't fall apart till AFTER the sale. HW. www.users.bigpond.com/hewn/index.htm The difference between a preacher and a used car salesman is that the latter's product doesn't fall apart till AFTER the sale. |
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On Thu, 02 Nov 2006 00:51:29 GMT, "Hexenmeister"
wrote: "Henri Wilson" HW@.. wrote in message .. . | On 29 Oct 2006 06:00:20 -0800, "RP" wrote: | Then how would you explain the gravitational red shift? | | The number of pebbles reaching the ground per second is the same for observers | at the origin and on the ground. The distance between pebbles increases as they | accelerate. | However, if the pebbles have a distinct 'crystaline grain', the number of | crystals reaching the GO per second increases with individual pebble speed. | | Thus, if a high laser fires 0.4um pulses of light towards the ground at a rate | of 1 per second, they will reach the ground at the same rate of 1 per second. ****ing nonsense. Rate of emission is not rate of reception or there would be no shift, ****ing stupid wabo, and in any event what you describe would be blue shift. Oh! Have Paul Andersen's famous tick fairies been niggling at you? HW. www.users.bigpond.com/hewn/index.htm The difference between a preacher and a used car salesman is that the latter's product doesn't fall apart till AFTER the sale. |
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#25
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"Henri Wilson" HW@.. wrote in message ... | On Thu, 02 Nov 2006 00:51:29 GMT, "Hexenmeister" | wrote: | | | "Henri Wilson" HW@.. wrote in message | .. . | | On 29 Oct 2006 06:00:20 -0800, "RP" wrote: | | Then how would you explain the gravitational red shift? | | | | The number of pebbles reaching the ground per second is the same for | observers | | at the origin and on the ground. The distance between pebbles increases as | they | | accelerate. | | However, if the pebbles have a distinct 'crystaline grain', the number of | | crystals reaching the GO per second increases with individual pebble | speed. | | | | Thus, if a high laser fires 0.4um pulses of light towards the ground at a | rate | | of 1 per second, they will reach the ground at the same rate of 1 per | second. | | ****ing nonsense. | Rate of emission is not rate of reception or there would be no shift, | ****ing stupid wabo, and in any event what you describe would | be blue shift. | | Oh! | | Have Paul Andersen's famous tick fairies been niggling at you? Not me, I understand more physics than you or the Tusselad between you ever will. Toss a ball in the air, it comes to a complete stop before falling back. Toss balls at one a second and they'll come to a complete stop once a second, UNLESS they have differing velocities. You are right, a high laser fires 0.4um pulses of light towards the ground at a rate of 1 per second, they will reach the ground at the same rate of 1 per second, but wrong if you think that is redshift and wrong if you think the velocity is constant. The correct answer to gravitational redshift is that the light is slowed. ****ing obvious for someone that understands c+at. You DO understand v = at? It doesn't get more basic than that. Androcles |
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#26
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On Thu, 02 Nov 2006 09:03:22 GMT, "Sorcerer"
wrote: "Henri Wilson" HW@.. wrote in message .. . | On Thu, 02 Nov 2006 00:51:29 GMT, "Hexenmeister" | wrote: | | | "Henri Wilson" HW@.. wrote in message | .. . | | On 29 Oct 2006 06:00:20 -0800, "RP" wrote: | | Then how would you explain the gravitational red shift? | | | | The number of pebbles reaching the ground per second is the same for | observers | | at the origin and on the ground. The distance between pebbles increases as | they | | accelerate. | | However, if the pebbles have a distinct 'crystaline grain', the number of | | crystals reaching the GO per second increases with individual pebble | speed. | | | | Thus, if a high laser fires 0.4um pulses of light towards the ground at a | rate | | of 1 per second, they will reach the ground at the same rate of 1 per | second. | | ****ing nonsense. | Rate of emission is not rate of reception or there would be no shift, | ****ing stupid wabo, and in any event what you describe would | be blue shift. | | Oh! | | Have Paul Andersen's famous tick fairies been niggling at you? Not me, I understand more physics than you or the Tusselad between you ever will. Toss a ball in the air, it comes to a complete stop before falling back. Toss balls at one a second and they'll come to a complete stop once a second, UNLESS they have differing velocities. You are right, a high laser fires 0.4um pulses of light towards the ground at a rate of 1 per second, they will reach the ground at the same rate of 1 per second, but wrong if you think that is redshift and wrong if you think the velocity is constant. The correct answer to gravitational redshift is that the light is slowed. Light is slowed when leaving a planet. It is blue shifted when flling towardsa a planet. ****ing obvious for someone that understands c+at. You DO understand v = at? It doesn't get more basic than that. You couldn't eve work out how much light accelerates when it falls.. Androcles HW. www.users.bigpond.com/hewn/index.htm The difference between a preacher and a used car salesman is that the latter's product doesn't fall apart till AFTER the sale. |
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Henri Wilson wrote: [...] Clocks are not affected by velocity changes and any change in rate in different gravity potentials is an indication that the clock has actually physically changed. Hafele-Keating, retard. [...] |
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#28
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"Henri Wilson" HW@.. wrote in message ... | On Thu, 02 Nov 2006 09:03:22 GMT, "Sorcerer" | wrote: | | | "Henri Wilson" HW@.. wrote in message | .. . | | On Thu, 02 Nov 2006 00:51:29 GMT, "Hexenmeister" | | wrote: | | | | | | "Henri Wilson" HW@.. wrote in message | | .. . | | | On 29 Oct 2006 06:00:20 -0800, "RP" wrote: | | | Then how would you explain the gravitational red shift? | | | | | | The number of pebbles reaching the ground per second is the same for | | observers | | | at the origin and on the ground. The distance between pebbles increases | as | | they | | | accelerate. | | | However, if the pebbles have a distinct 'crystaline grain', the number | of | | | crystals reaching the GO per second increases with individual pebble | | speed. | | | | | | Thus, if a high laser fires 0.4um pulses of light towards the ground at | a | | rate | | | of 1 per second, they will reach the ground at the same rate of 1 per | | second. | | | | ****ing nonsense. | | Rate of emission is not rate of reception or there would be no shift, | | ****ing stupid wabo, and in any event what you describe would | | be blue shift. | | | | Oh! | | | | Have Paul Andersen's famous tick fairies been niggling at you? | | Not me, I understand more physics than you or the Tusselad | between you ever will. | Toss a ball in the air, it comes to a complete stop before falling back. | Toss balls at one a second and they'll come to a complete | stop once a second, UNLESS they have differing velocities. | You are right, a high laser fires 0.4um pulses of light towards | the ground at a rate of 1 per second, they will reach the ground at | the same rate of 1 per second, but wrong if you think that is | redshift and wrong if you think the velocity is constant. | The correct answer to gravitational redshift is that the light | is slowed. | | Light is slowed when leaving a planet. It is blue shifted when flling towardsa | a planet. Ok...and when leaving a star, too. Getting drunk already? You've moved the 'a' in 'falling' to the end of the line. But anyway, we agree light falls. Starlight will bend toward the sun, too, just as any massive object will, and the amount of bending can be used a measure of its speed. Now... what does that tell us about the nature of mass? | ****ing obvious for someone that understands c+at. | You DO understand v = at? | It doesn't get more basic than that. | | You couldn't eve work out how much light accelerates when it falls.. You ARE drunk. The acceleration is 9.8 metres per second squared. 100,000 metres to the top of the atmosphere, t =333 usec, gain in velocity is 3 millimetres per second. Measured speed of light: 299,792.4562 kilometers per second, plus or minus 1.1 meters per second The gain is a fraction of the tolerance and therefore not measurable. Hence the ****wit Perry is spouting the usual bull**** that all relativists do. Tell him I said so. Androcles |
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#29
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On Thu, 02 Nov 2006 11:44:32 GMT, "Sorcerer"
wrote: "Henri Wilson" HW@.. wrote in message .. . | On Thu, 02 Nov 2006 09:03:22 GMT, "Sorcerer" | | | | Have Paul Andersen's famous tick fairies been niggling at you? | | Not me, I understand more physics than you or the Tusselad | between you ever will. | Toss a ball in the air, it comes to a complete stop before falling back. | Toss balls at one a second and they'll come to a complete | stop once a second, UNLESS they have differing velocities. | You are right, a high laser fires 0.4um pulses of light towards | the ground at a rate of 1 per second, they will reach the ground at | the same rate of 1 per second, but wrong if you think that is | redshift and wrong if you think the velocity is constant. | The correct answer to gravitational redshift is that the light | is slowed. | | Light is slowed when leaving a planet. It is blue shifted when flling towardsa | a planet. Ok...and when leaving a star, too. Getting drunk already? You've moved the 'a' in 'falling' to the end of the line. The computer did that, not I. But anyway, we agree light falls. Starlight will bend toward the sun, too, just as any massive object will, and the amount of bending can be used a measure of its speed. Now... what does that tell us about the nature of mass? Not much, actually. | ****ing obvious for someone that understands c+at. | You DO understand v = at? | It doesn't get more basic than that. | | You couldn't eve work out how much light accelerates when it falls.. You ARE drunk. The acceleration is 9.8 metres per second squared. 100,000 metres to the top of the atmosphere, t =333 usec, gain in velocity is 3 millimetres per second. Measured speed of light: 299,792.4562 kilometers per second, plus or minus 1.1 meters per second The gain is a fraction of the tolerance and therefore not measurable. The effect they are claiming is around 4 parts in 10^10. It is mesurable. Hence the ****wit Perry is spouting the usual bull**** that all relativists do. Tell him I said so. Now, Mr. Engineer, try calculating the change in light speed from a GPS clock in orbit about 26000 kms from the Earth's centre. I hope you learnt how to perform simple integrations. Androcles HW. www.users.bigpond.com/hewn/index.htm The difference between a preacher and a used car salesman is that the latter's product doesn't fall apart till AFTER the sale. |
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#30
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To all,
The rate (frequency) at which the pebbles are dropped and the rate at which they reach their target remains the same as long as all the pebbles are exposed to the same gravitational force over the same path length. However the speed at which they hit the earth gets greater the higher the distance from which the pebbles are dropped. But since whatever happens to any one pebble happens to all the others, the frequency at which they hit the target remains the same. That is to say, if one pebble is released each second, one pebble will hit the earth each second. The above is based on simple logic, 'relativity' doesn't come into it. Len Gaasenbeek. .............................................. "Henri Wilson" HW@.. wrote in message ... On Thu, 02 Nov 2006 11:44:32 GMT, "Sorcerer" wrote: "Henri Wilson" HW@.. wrote in message .. . | On Thu, 02 Nov 2006 09:03:22 GMT, "Sorcerer" | | | | Have Paul Andersen's famous tick fairies been niggling at you? | | Not me, I understand more physics than you or the Tusselad | between you ever will. | Toss a ball in the air, it comes to a complete stop before falling back. | Toss balls at one a second and they'll come to a complete | stop once a second, UNLESS they have differing velocities. | You are right, a high laser fires 0.4um pulses of light towards | the ground at a rate of 1 per second, they will reach the ground at | the same rate of 1 per second, but wrong if you think that is | redshift and wrong if you think the velocity is constant. | The correct answer to gravitational redshift is that the light | is slowed. | | Light is slowed when leaving a planet. It is blue shifted when flling towardsa | a planet. Ok...and when leaving a star, too. Getting drunk already? You've moved the 'a' in 'falling' to the end of the line. The computer did that, not I. But anyway, we agree light falls. Starlight will bend toward the sun, too, just as any massive object will, and the amount of bending can be used a measure of its speed. Now... what does that tell us about the nature of mass? Not much, actually. | ****ing obvious for someone that understands c+at. | You DO understand v = at? | It doesn't get more basic than that. | | You couldn't eve work out how much light accelerates when it falls.. You ARE drunk. The acceleration is 9.8 metres per second squared. 100,000 metres to the top of the atmosphere, t =333 usec, gain in velocity is 3 millimetres per second. Measured speed of light: 299,792.4562 kilometers per second, plus or minus 1.1 meters per second The gain is a fraction of the tolerance and therefore not measurable. The effect they are claiming is around 4 parts in 10^10. It is mesurable. Hence the ****wit Perry is spouting the usual bull**** that all relativists do. Tell him I said so. Now, Mr. Engineer, try calculating the change in light speed from a GPS clock in orbit about 26000 kms from the Earth's centre. I hope you learnt how to perform simple integrations. Androcles HW. www.users.bigpond.com/hewn/index.htm The difference between a preacher and a used car salesman is that the latter's product doesn't fall apart till AFTER the sale. |
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