Rest Energy of particle = Potential Energy + Rotational Energy
= mgh + 2/5 m(r/omega)^2

mass of particle or atom Kg
gravitational field m/sec^2
height of particle or atom in the gravitational field meters
r radius of atom or particle
omega = angular speed

The rest energy of a particle isn't

E = m0c^2

If the partcle is moving then add

KE = 1/2 mv^2

where v = velocity the particle or atom moving

This should give the total energy of the atom, not

E = mc^2

v can only approach c the speed of light

If you want to find the total energy further away form the particle or atom r
simply increases.


E = hf

is incorrect too.

Einstein said it measured photon packets of energy, but each packet of photon
energy varies and the way they determined h ( planck's constant was by using
mass of black bodies. Blackbody mass varies per atom and element. H is not
constant. Each element has different colors and some are invisible. So E = hf
can't apply to anything. Photon energy and the number of photons vary, and mass
with frequency energy applied varies in overall energy too. H is not constant.

E = hf is incorrect

hf = mc^2 is incorrect

Here you are relating photon energy traveling at the speed of light with
mass at the speed of light at rest.

This doesn't work. In fact, if hf is photon energy then it must have mass,

hf/c^2 = m

photons have no mass.

This equation is wrong too.

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Rest Energy of particle = Potential Energy + Rotational Energy
= mgh + 2/5 m(r/omega)^2

mass of particle or atom Kg
gravitational field m/sec^2
height of particle or atom in the gravitational field meters
r radius of atom or particle
omega = angular speed

The rest energy of a particle isn't

E = m0c^2

If the partcle is moving then add

KE = 1/2 mv^2

rough calculations

v = about 2.9999 X10^8m/sec
( near speed of light)

KE = (10^-27) (10^8)^2

KE = 10^-11 Joules

1 eV = 10^-19 joules

so an electron traveling in a particle accelerator near the speed of light
has

about 10 MeV of energy

This is close to the collsion energy creation of an electron where a photon
collides with an electron near the speed of light and it equals

about 1 MeV.

near speed of light in a particle accelerator


I guess if you add in all the other equations shown above you get a closer
answer, without the use of

E = mc^2


where v = velocity the particle or atom moving

This should give the total energy of the atom, not

E = mc^2

v can only approach c the speed of light

If you want to find the total energy further away form the particle or atom
r
simply increases.


E = hf

is incorrect too.

Einstein said it measured photon packets of energy, but each packet of
photon
energy varies and the way they determined h ( planck's constant was by using
mass of black bodies. Blackbody mass varies per atom and element. H is not
constant. Each element has different colors and some are invisible. So E = hf
can't apply to anything. Photon energy and the number of photons vary, and
mass
with frequency energy applied varies in overall energy too. H is not
constant.

E = hf is incorrect

hf = mc^2 is incorrect

Here you are relating photon energy traveling at the speed of light with
mass at the speed of light at rest.

This doesn't work. In fact, if hf is photon energy then it must have mass,

hf/c^2 = m

photons have no mass.

This equation is wrong too.



S. Enterprize Co. (Membership)
http://www.s-enterprize.com/
S. Enterprize (Science Journal)
http://smart1234.s-enterprize.com/

S. Enterprize Company wrote:
Rest Energy of particle = Potential Energy + Rotational Energy
= mgh + 2/5 m(r/omega)^2

mass of particle or atom Kg
gravitational field m/sec^2
height of particle or atom in the gravitational field meters
r radius of atom or particle
omega = angular speed

The rest energy of a particle isn't

E = m0c^2



A recurring theme throughout your ramblings is that they bear no
relation to empirically established fact. The mass of the electron is
0.511MeV/c^2; an electron and a positron can be created in a system with
a CM energy of 1.022MeV. Coincidence? No, the amount of energy to
create the particles must be at least their rest mass energy, which if
you do the sums you will find to be the case.
--
FM

Frodo Morris wrote in message ...
S. Enterprize Company wrote:
Rest Energy of particle = Potential Energy + Rotational Energy


E = m0c^2



A recurring theme throughout your ramblings is that they bear no
relation to empirically established fact. The mass of the electron is
0.511MeV/c^2; an electron and a positron can be created in a system with
a CM energy of 1.022MeV. Coincidence? No, the amount of energy to
create the particles must be at least their rest mass energy, which if
you do the sums you will find to be the case.
------------
i agree with that last sentence.
yet
there is no relativistic mass as a result of motion.
there is only 'reletivistic force'
ie as speed grows the driving force has more and more difficulty
to add velocity-- untill the upper limit of C
(that is because the fastest driver has no more velocity than C)
see the
'the third Porat Postulation'
all the best
Y.Porat
-------------------

S. Enterprize Company wrote:
Rest Energy of particle = Potential Energy + Rotational Energy
= mgh + 2/5 m(r/omega)^2

mass of particle or atom Kg
gravitational field m/sec^2
height of particle or atom in the gravitational field meters
r radius of atom or particle
omega = angular speed

The rest energy of a particle isn't

E = m0c^2



A recurring theme throughout your ramblings is that they bear no
relation to empirically established fact. The mass of the electron is
0.511MeV/c^2; an electron and a positron can be created in a system with
a CM energy of 1.022MeV. Coincidence? No, the amount of energy to
create the particles must be at least their rest mass energy, which if
you do the sums you will find to be the case.
--
FM


I made typo's late last night, I was sleepy. I should get near those values
later....


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