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| Tags: atom, broglie, wavelengths |
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#1
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Can anyone tell me how to calculate the known orbital wavelengths of the
Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. Thanks in advance. Jeff |
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#2
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Jeff Lee wrote:
Can anyone tell me how to calculate the known orbital wavelengths What do you mean by "orbital wavelengths"? of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. What are [N1] and [N2]? using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. There is no such thing as "orbital velocity". Electrons don't move on "orbits" in the atom. Or do you mean something like the square root of the expectation value of velocity squared? (in other words, the standard deviation of velocity, because the expectation value for the velocity itself is zero). Bye, Bjoern |
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#3
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Don't post in HTML. It makes a mess of replying in-line.
The Bohr model of the hydrogen atom died a death about seventy or eighty years ago. Learn to understand the solution to the Schrodinger equation for the Hydrogen atom instead. Franz Heymann "Jeff Lee" wrote in message ... Can anyone tell me how to calculate the known orbital wavelengths of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. Thanks in advance. Jeff |
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#4
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In article , Jeff Lee wrote:
-=-=-=-=-=- Can anyone tell me how to calculate the known orbital wavelengths of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. Thanks in advance. As has been said, the Bohr atom is an historical footnote and the electrons in an atom don't really have a velocity. But it's a perfectly good question in the context of Bohr's model of the atom. If the atom were treated as a classical system, the orbit of the electron would be determined the same way as the orbit of a planet about the Sun. Assume a circular orbit, and F = ma = mv^2/r = -kqQ/r^2 for some nuclear charge Q, electron charge q, electron mass m, assuming the mass of the nucleus is much greater than the mass of the electron and it's a hydrogen-like atom -- one electron, regardless of nuclear charge. And not really ignoring the problem of radiation, since that's what Bohr was trying to overcome. Bohr added the quantization of angular momentum, L=nh. Or n*hbar, something like that. L is angular momentum, L=mvr. That constrains the velocities of the electron, hence constrains the orbits. Bohr hypothesized there would be no radiation for those angular momenta. Determining a wavelength involves some simple algebra to find v_n, or the velocity for a particular orbit n, then plug it into Planck's relation, which you've given. The other way is to assume one complete wavelength wraps around the electron's orbit, the find r_n, and the wavelength is equal to the circumference. -- "When the fool walks through the street, in his lack of understanding he calls everything foolish." -- Ecclesiastes 10:3, New American Bible |
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#5
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Bjoern Feuerbacher wrote:
Jeff Lee wrote: Can anyone tell me how to calculate the known orbital wavelengths What do you mean by "orbital wavelengths"? of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. What are [N1] and [N2]? using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. There is no such thing as "orbital velocity". Electrons don't move on "orbits" in the atom. Or do you mean something like the square root of the expectation value of velocity squared? (in other words, the standard deviation of velocity, because the expectation value for the velocity itself is zero). Bye, Bjoern Bjoern, Since you don't know what [N1] and [N2] are (notations for the electron orbits) then I can see why you don't know about electron velocity. What does the electron do when it spins around the atom, I mean how does it move around the nucleus if it has no velocity? all the best, Jeff |
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#6
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Sorry dude, I remember you from before. You weren't worth answering then
and from your reply I can see by your obvious lack of knowledge that you're really not worth answering now. all the best, Jeff Franz Heymann wrote: Don't post in HTML. It makes a mess of replying in-line.The Bohr model of the hydrogen atom died a death about seventy or eighty years ago.Learn to understand the solution to the Schrodinger equation for the Hydrogen atom instead. Franz Heymann "Jeff Lee" wrote in message anyone tell me how to calculate the known orbital wavelengths of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. Thanks in advance. Jeff |
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#7
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"Gregory L. Hansen" wrote:
In article , Jeff Lee wrote: -=-=-=-=-=- Can anyone tell me how to calculate the known orbital wavelengths of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. Thanks in advance. As has been said, the Bohr atom is an historical footnote and the electrons in an atom don't really have a velocity. But it's a perfectly good question in the context of Bohr's model of the atom. If the atom were treated as a classical system, the orbit of the electron would be determined the same way as the orbit of a planet about the Sun. Assume a circular orbit, and F = ma = mv^2/r = -kqQ/r^2 for some nuclear charge Q, electron charge q, electron mass m, assuming the mass of the nucleus is much greater than the mass of the electron and it's a hydrogen-like atom -- one electron, regardless of nuclear charge. And not really ignoring the problem of radiation, since that's what Bohr was trying to overcome. Bohr added the quantization of angular momentum, L=nh. Or n*hbar, something like that. L is angular momentum, L=mvr. That constrains the velocities of the electron, hence constrains the orbits. Bohr hypothesized there would be no radiation for those angular momenta. Determining a wavelength involves some simple algebra to find v_n, or the velocity for a particular orbit n, then plug it into Planck's relation, which you've given. The other way is to assume one complete wavelength wraps around the electron's orbit, the find r_n, and the wavelength is equal to the circumference. -- "When the fool walks through the street, in his lack of understanding he calls everything foolish." -- Ecclesiastes 10:3, New American Bible Gregory, Thanks for your reply. What if we take the de Broglie wavelength equation: wavelength of moving particle = Plank's constant / mass x velocity, instead of using the electron's mass we divide the orbital energy of the [N1] orbit: 13.6 ev by "c^2", to obtain the "mass loss" from the electron used to form the orbit to be: 2.42x10^-35 kg.. We now take the orbital velocity of [N1] which is 2.1885x10^6 m/sec. and plug it into the Fitzgerald Formula, and then multiply this result by "c" to get a "Photon Spin Velocity" within the particle (electron) to be: 299,992,017 m/sec. (since according to this way of thinking subatomic particles (electrons, etc.) are made up of "photon spin" that slows it's rate of spin at the same rate time dilation occurs, as orbital velocity increases) such that: wavelength of moving electron = h / 2.42x10^-35 kg. x 299,992,017 m/sec. = 9.12x10^-8 meters = [N1] wavelength Now, ain't that one hell of a coincidence? What's even weirder is that it works for all of the electron orbits of the atom. LOOK OUT academia - BOHR's back! All comments and opinions appreciated. Thanks. All the best, JLee CENTER FOR REALITY PHYSICS |
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#8
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"Jeff Lee" wrote in message ... Bjoern Feuerbacher wrote: Jeff Lee wrote: Can anyone tell me how to calculate the known orbital wavelengths What do you mean by "orbital wavelengths"? of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. What are [N1] and [N2]? using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. There is no such thing as "orbital velocity". Electrons don't move on "orbits" in the atom. Or do you mean something like the square root of the expectation value of velocity squared? (in other words, the standard deviation of velocity, because the expectation value for the velocity itself is zero). Bye, Bjoern Bjoern, Since you don't know what [N1] and [N2] are (notations for the electron orbits) then I can see why you don't know about electron velocity. What does the electron do when it spins around the atom, I mean how does it move around the nucleus if it has no velocity? The notation does not occur in any of my texts on atomic physics. There are no "electron orbits" in a hydrogen atom. What experimental evidence can you cite to the effect that the electron does in fact move around the nucleus? The stationary states of the electron in, for instance, a hydrogen atom, are eigenstates of energy, but not of velocity. Franz Heymann |
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#9
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"Jeff Lee" wrote in message ... Sorry dude, I remember you from before. You weren't worth answering then and from your reply I can see by your obvious lack of knowledge that you're really not worth answering now. You have also now buggered the attribution marks. You have neen waffling for so many years now that you could surely have learnt "how" to post, even if you don't know "what" to post. You won't be hearing from me until you fix your posting style Franz Franz Heymann wrote: Don't post in HTML. It makes a mess of replying in-line.The Bohr model of the hydrogen atom died a death about seventy or eighty years ago.Learn to understand the solution to the Schrodinger equation for the Hydrogen atom instead. Franz Heymann "Jeff Lee" wrote in message anyone tell me how to calculate the known orbital wavelengths of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. Thanks in advance. Jeff |
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#10
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If I thought you had the intelligence to understand it I would refer you
to the post I just made to Mr. Hanson where it has been found that it IS possible to calculate the electron orbital wavelengths with the de Broglie equation, if you use the right physics. But since you obviously don't - well, all the best. Jeff Franz Heymann wrote: "Jeff Lee" wrote in message dude, I remember you from before. You weren't worth answering then and from your reply I can see by your obvious lack of knowledge that you're really not worth answering now. You have also now buggered the attribution marks.You have neen waffling for so many years now that you could surely have learnt "how" to post, even if you don't know "what" to post. You won't be hearing from me until you fix your posting style Franz Franz Heymann wrote: Don't post in HTML. It makes a mess of replying in-line.The Bohr model of the hydrogen atom died a death about seventy or eighty years ago.Learn to understand the solution to the Schrodinger equation for the Hydrogen atom instead. Franz Heymann "Jeff Lee" wrote in message anyone tell me how to calculate the known orbital wavelengths of the Bohr Hydrogen atom whe [N1] = 9.12x10^-8 m, [N2] = 3.65x10^-7 m, etc. using the de Broglie wavelength equation of current Quantum Mechanics whe wavelength of moving particle = Plank's constant / mass x orbital velocity. Thanks in advance. Jeff |
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