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| Tags: field, magnetic, problem |
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#1
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Hi all,
I am a 2nd semester general physics student and have a problem I'm trying to figure out. Here is the problem and my attempt. A uniform magnetic field is established perpendicular to the plane of a loop of radius 5.0 cm, resistance .4 ohm and negligible self-inductance. The magnitude is increasing at a rate of 40mT/s. Find the rate of Joule heating in the loop. My attempted work F=NBA dF/dt=NA(dB/dt) N=1 A=3.14*.05^2=.00785 m^2 dB/dt=40*10^6 dF/dt=314,000 T m^2/s This is all I've done so far, and I don't think it's even right to start out. I think that this is probably a classic Related Rates problem from differential calculus, but am unsure how to go about it. Any help would be appreciated. Thanks! David Moran |
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#2
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In article ,
David Moran wrote: A uniform magnetic field is established perpendicular to the plane of a loop of radius 5.0 cm, resistance .4 ohm and negligible self-inductance. The magnitude is increasing at a rate of 40mT/s. Find the rate of Joule heating in the loop. My attempted work F=NBA dF/dt=NA(dB/dt) N=1 A=3.14*.05^2=.00785 m^2 dB/dt=40*10^6 dF/dt=314,000 T m^2/s This is all I've done so far, and I don't think it's even right to start out. No, it looks like you're OK so far, assuming that "mT" means microtesla and F is the magnetic flux. By Faraday's Law, dF/dt equals the magnitude of the electromotive force around the loop (in volts, since you're using MKSA units). Now, if you have a loop of wire with s specified emf (which could just as well come from a battery) and a specified resistance, what is the current in the loop? And what is the power dissipated by that current, passing through that resistance? -- Jon Bell Presbyterian College Dept. of Physics and Computer Science Clinton, South Carolina USA |
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