A Physics forum. Physics Banter

If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.

Go Back   Home » Physics Banter forum » Physics Newsgroups » Physics - General Discussion
Site Map Home Register Authors List Search Today's Posts Mark Forums Read Web Partners

Tags: , ,

Magnetic Field Problem



 
 
Thread Tools Display Modes
  #1  
Old November 22nd 03 posted to sci.physics
David Moran
external usenet poster
 
Posts: 68
Default Magnetic Field Problem

Hi all,

I am a 2nd semester general physics student and have a problem I'm
trying to figure out. Here is the problem and my attempt.

A uniform magnetic field is established perpendicular to the plane of a loop
of radius 5.0 cm, resistance .4 ohm and negligible self-inductance. The
magnitude is increasing at a rate of 40mT/s. Find the rate of Joule heating
in the loop.

My attempted work

F=NBA
dF/dt=NA(dB/dt)

N=1
A=3.14*.05^2=.00785 m^2
dB/dt=40*10^6

dF/dt=314,000 T m^2/s

This is all I've done so far, and I don't think it's even right to start
out. I think that this is probably a classic Related Rates problem from
differential calculus, but am unsure how to go about it. Any help would be
appreciated.

Thanks!
David Moran


Ads
  #2  
Old November 22nd 03 posted to sci.physics
Jon Bell
external usenet poster
 
Posts: 106
Default Magnetic Field Problem

In article ,
David Moran wrote:

A uniform magnetic field is established perpendicular to the plane of a loop
of radius 5.0 cm, resistance .4 ohm and negligible self-inductance. The
magnitude is increasing at a rate of 40mT/s. Find the rate of Joule heating
in the loop.

My attempted work

F=NBA
dF/dt=NA(dB/dt)

N=1
A=3.14*.05^2=.00785 m^2
dB/dt=40*10^6

dF/dt=314,000 T m^2/s

This is all I've done so far, and I don't think it's even right to start
out.


No, it looks like you're OK so far, assuming that "mT" means microtesla
and F is the magnetic flux.

By Faraday's Law, dF/dt equals the magnitude of the electromotive force
around the loop (in volts, since you're using MKSA units). Now, if you
have a loop of wire with s specified emf (which could just as well come
from a battery) and a specified resistance, what is the current in the
loop? And what is the power dissipated by that current, passing through
that resistance?

--
Jon Bell Presbyterian College
Dept. of Physics and Computer Science Clinton, South Carolina USA
 




Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
Dynamic magnetic field is open Sergey Karavashkin Physics - General Discussion 20 January 9th 04 05:31 PM
magnetic field Wayne Physics - General Discussion 2 September 9th 03 05:04 PM
Integration Problem / Finding Contour lines Problem blah12@mail.com Physics - General Discussion 3 September 8th 03 01:28 AM
Integration Problem / Finding Contour lines Problem blah12@mail.com Current Physics Research (Moderated) 3 September 8th 03 01:28 AM
Magnetic field strength measurement Rod Physics - General Discussion 2 September 1st 03 06:03 PM


All times are GMT +1. The time now is 06:07 PM.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.Search Engine Friendly URLs by vBSEO 2.4.0
Copyright ©2004-2008 Physics Banter, part of the NewsgroupBanter project.
The comments are property of their posters.
Personal Car Finance - Send Money Online - Learn PHP free - Free Credit Report - Loans