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| Tags: exclusion, paulis, principle |
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#1
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One basic Q: Is pauli's exclusion principle an axiom?? Or can it be
derived using the electromagnetic force + .....?? ganesh |
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#2
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"ganesh" wrote in message
om... | One basic Q: Is pauli's exclusion principle an axiom?? Or can it be | derived using the electromagnetic force + .....?? Not sure if it can be derived, but it is maybe just plain common sense made into a rule of physics. FrediFizzx |
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#3
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ganesh wrote:
One basic Q: Is pauli's exclusion principle an axiom?? Or can it be derived using the electromagnetic force + .....?? It can be proven using basic quantum field theory and some quite natural assumptions. I have the paper lying around somewhere, but I don't know where, and I don't have the reference at hand, sorry. Bye, Bjoern |
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#5
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In article ,
ganesh wrote: One basic Q: Is pauli's exclusion principle an axiom?? Or can it be derived using the electromagnetic force + .....?? ganesh Identical particles in quantum mechanics are not identical in the sense of two cue balls with the same mass, shape, color, and so on. They're identical in the strongest possible sense -- you can't say particle A is here and particle B is there because particle B is also here and A is also there. When you work out the two-particle wavefunction you must compute both possibilities and add them together. If the properties are indicated by A and B and our assumption of which is which is indicated by position, we have psi(A,B) + psi(B,A) Fermions, particles with half-integral spin (1/2, 3/2, 5/2,...) anti-commute, which means there's a minus sign. psi(A,B) - psi(B,A) If A and B are the same (two particles in identical quantum states) we have psi(A,A) - psi(A,A) = 0 The probability goes to zero, hence, no two fermions can share the same state. -- "Let us learn to dream, gentlemen, then perhaps we shall find the truth... But let us beware of publishing our dreams before they have been put to the proof by the waking understanding." -- Friedrich August Kekulé |
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#6
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Gregory L. Hansen wrote: In article , ganesh wrote: One basic Q: Is pauli's exclusion principle an axiom?? Or can it be derived using the electromagnetic force + .....?? ganesh Identical particles in quantum mechanics are not identical in the sense of two cue balls with the same mass, shape, color, and so on. They're identical in the strongest possible sense -- you can't say particle A is here and particle B is there because particle B is also here and A is also there. When you work out the two-particle wavefunction you must compute both possibilities and add them together. If the properties are indicated by A and B and our assumption of which is which is indicated by position, we have psi(A,B) + psi(B,A) Fermions, particles with half-integral spin (1/2, 3/2, 5/2,...) anti-commute, which means there's a minus sign. psi(A,B) - psi(B,A) If A and B are the same (two particles in identical quantum states) we have psi(A,A) - psi(A,A) = 0 The probability goes to zero, hence, no two fermions can share the same state. For instance, in the two-point, one pathway standing wave below http://rapfast.petcom.com/~john/He.GIF the first five positions a 0,0,80 0,0,-80 5.9726,-14.4192,78.4128 -5.9726,14.4192,-78.4128 21.6478,-21.6478,73.9104 -21.6478,21.6478,-73.9104 41.0624,-17.0086,66.5176 -41.0624,17.0086,-66.5176 56.5685,0,56.5685 -56.5685,0,-56.5685 The Galaxy pattern orbital is produced when a point is rotating round a circle at a fixed radius from a center and the circle is precessing at twice the frequency of the rotation. If there are more than two points on the circle, ONLY points exactly opposite each other will follow the same path. THIS is why the Pauli Exclusion Principle holds. John http://rapfast.petcom.com/~john/ |
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#7
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hi,
In response to everyone who replied to my querry.... The fermionic wavefunction changes sign when we interchange two fermions: this can be used to explain the pauli exclusion principle...And why do the wavefunction changes sign?? because the relevant operators (talking of QFT) anticommute instead of commuting. So now the anticommutation principle becomes the axion instead of pauli's exclusion principle....This probably may be a slightly deeper axion,...but it still doesnt seem to fundamentally answer some Qs. If we can come up with a reason as to how say, em force, strong force, along with space time geometry (gravity) ends up in anticommuting observables (for fermions) instead of commuting observable then one wud have explain the PEP in terms of some fundamental axioms. Maybe in future the theory of everything (if ever there is one) may explain...But as of now, I havent come across anything that really explains why anticommuting should take place. In the absence of such an explanation, what prevents me from assuming PEP to be a fifth force?? I mean, its a force, because it prevents two identical spins to have the same state, and it cannot be explained in terms of em, strong, weak and gravity. But no one ever talks of it as a "fifth force". So it (PEP or anticommutation or whatever) should be derivable from the em, strong, weak and spacetime geometry. John, when you talk of galaxy pattern orbital, arent you implicitly assuming that spin will not commute with space?? (I'm right now going back to pre QFT, since QFT doesnt talk of spacetime as an observable and this is something I really dont feel comfortable with). Since spin commutes with space, the spin should really be independent of how the electron moves in space...or am I missing something?? ganesh |
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#8
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#9
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John Sefton wrote:
Gregory L. Hansen wrote: In article , ganesh wrote: One basic Q: Is pauli's exclusion principle an axiom?? Or can it be derived using the electromagnetic force + .....?? ganesh Identical particles in quantum mechanics are not identical in the sense of two cue balls with the same mass, shape, color, and so on. They're identical in the strongest possible sense -- you can't say particle A is here and particle B is there because particle B is also here and A is also there. When you work out the two-particle wavefunction you must compute both possibilities and add them together. If the properties are indicated by A and B and our assumption of which is which is indicated by position, we have psi(A,B) + psi(B,A) Fermions, particles with half-integral spin (1/2, 3/2, 5/2,...) anti-commute, which means there's a minus sign. psi(A,B) - psi(B,A) If A and B are the same (two particles in identical quantum states) we have psi(A,A) - psi(A,A) = 0 The probability goes to zero, hence, no two fermions can share the same state. For instance, in the two-point, one pathway standing wave below http://rapfast.petcom.com/~john/He.GIF the first five positions a 0,0,80 0,0,-80 5.9726,-14.4192,78.4128 -5.9726,14.4192,-78.4128 21.6478,-21.6478,73.9104 -21.6478,21.6478,-73.9104 41.0624,-17.0086,66.5176 -41.0624,17.0086,-66.5176 56.5685,0,56.5685 -56.5685,0,-56.5685 The Galaxy pattern orbital is produced when a point is rotating round a circle at a fixed radius from a center and the circle is precessing at twice the frequency of the rotation. If there are more than two points on the circle, ONLY points exactly opposite each other will follow the same path. THIS is why the Pauli Exclusion Principle holds. Does this explain also why the electrons inside a metal obey the Fermi-Dirac statistic? Bye, Bjoern |
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#10
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ganesh wrote:
hi, In response to everyone who replied to my querry.... The fermionic wavefunction changes sign when we interchange two fermions: this can be used to explain the pauli exclusion principle...And why do the wavefunction changes sign?? because the relevant operators (talking of QFT) anticommute instead of commuting. Right. So now the anticommutation principle becomes the axion instead of pauli's exclusion principle.... This probably may be a slightly deeper axion,...but it still doesnt seem to fundamentally answer some Qs. I think you wanted to say "axiom". You are wrong there, this isn't an axiom. As I already told you, this can be proven using QFT, using some quite sensible assumptions. If we can come up with a reason as to how say, em force, strong force, along with space time geometry (gravity) ends up in anticommuting observables (for fermions) instead of commuting observable then one wud have explain the PEP in terms of some fundamental axioms. I already told you that there is a paper by Pauli which gives the proof. Didn't you read this? Maybe in future the theory of everything (if ever there is one) may explain... It is already explained. But as of now, I havent come across anything that really explains why anticommuting should take place. There is a paper by Pauli on this, should be from around 1932, IIRC. In the absence of such an explanation, what prevents me from assuming PEP to be a fifth force?? Well, for example, that this makes no sense? I mean, its a force, because it prevents two identical spins to have the same state, What has this to do with being a force? May I remind you that "forces" are the things which accelerate particles? and it cannot be explained in terms of em, strong, weak and gravity. But no one ever talks of it as a "fifth force". Because this would make no sense. So it (PEP or anticommutation or whatever) should be derivable from the em, strong, weak and spacetime geometry. It is derivable, IIRC, from the requirement that the energy of particles should be positive. John, when you talk of galaxy pattern orbital, arent you implicitly assuming that spin will not commute with space?? No, he is assuming nothing like that. I guess he doesn't even know what commuting and anticommuting means. He is a crackpot. (I'm right now going back to pre QFT, since QFT doesnt talk of spacetime as an observable It doesn't use hermitean operators for position and time, right. So what? Even QM doesn't has time as an observable! You shouldn't confuse the use of the noun "observable" in quantum theory with the question if something can be observed or not! and this is something I really dont feel comfortable with). Well, that's your problem. Physics doesn't care about if you feel comfortable with it or not. Since spin commutes with space, What is this supposed to mean, specifically? That spin commutes with the position operator or what? the spin should really be independent of how the electron moves in space...or am I missing something?? Yes, definitely. What have you read about QM and QFT so far? Bye, Bjoern |
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