Eero wrote:

oo ln(x)
S --------------------- dx
0 (x^n) -1

n=2,3,4,.....

You'll get feedback if you show your work to date and give some idea
of its application. Ditto sci.math

Good folks are happy to lend a hand. That is not the same as carrying
the load gratis.

--
Uncle Al
http://www.mazepath.com/uncleal/
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oo ln(x)
S --------------------- dx
0 (x^n) -1

n=2,3,4,.....

"Eero" wrote in message
...




oo ln(x)
S --------------------- dx
0 (x^n) -1

n=2,3,4,.....







Methinks it cannot be evaluated in closed form. I could be wrong.

On Fri, 7 Nov 2003 20:42:38 -0600, "Brian"
wrote:


"Eero" wrote in message
...




oo ln(x)
S --------------------- dx
0 (x^n) -1

n=2,3,4,.....







Methinks it cannot be evaluated in closed form. I could be wrong.

ln(0) looks tough

Mr. Dual Space
(If you have something to say, write an equation.
If you have nothing to say, write an essay).

Well, I leave it to you to show that for n = 2 and n = 4 the integrals are
pi^2/4 and pi^2/8 respectively. If n is anything else, things get a little
tougher but not impossible.


"John C. Polasek" wrote in message
...
On Fri, 7 Nov 2003 20:42:38 -0600, "Brian"
wrote:


"Eero" wrote in message
...




oo ln(x)
S --------------------- dx
0 (x^n) -1

n=2,3,4,.....







Methinks it cannot be evaluated in closed form. I could be wrong.

ln(0) looks tough

Mr. Dual Space
(If you have something to say, write an equation.
If you have nothing to say, write an essay).