Lets suppose we have a flat surface that is
as far as we know infinite in length and width.

We mark a line and call it the 0 point.
we then mark lines that are 1 mile away from
this 0 point so we will have parallel lines every 1 mile.

An observer stays at the 0 point (A)
an second observer is in a spaceship (B)
traveling at at .5c and the clock that is
at the 0 point(A) starts when it (B) passes the 0 point.
According to basic math, the object will pass by
the 93,000th line in 1/2 second.
and the 186,000th line in 1 second..
(silly basic math)

so...
What time does (B) pass the line according to
the time dilation of (B) while in motion?

Spaceman wrote:
Lets suppose we have a flat surface that is
as far as we know infinite in length and width.



If you want to do a real problem, forget the infinite
Newtonian space and time ****, space****. Learn some
relativity.

How Do You Add Velocities in Special Relativity?
http://edu-observatory.org/physics-f.../velocity.html

"Sam Wormley" wrote in message
news:w8vGf.754583$x96.752786@attbi_s72...
| Spaceman wrote:
| Lets suppose we have a flat surface that is
| as far as we know infinite in length and width.
|
|
|
| If you want to do a real problem, forget the infinite
| Newtonian space and time ****, space****. Learn some
| relativity.
|
| How Do You Add Velocities in Special Relativity?
| http://edu-observatory.org/physics-f.../velocity.html

Sam is real afraid to answer such a question.
so instead he sticks his head in the sand of relativity.
and expects me to join him..
Sam the osterich..
LOL

Spaceman wrote:
Lets suppose we have a flat surface that is
as far as we know infinite in length and width.

We mark a line and call it the 0 point.
we then mark lines that are 1 mile away from
this 0 point so we will have parallel lines every 1 mile.

An observer stays at the 0 point (A)
an second observer is in a spaceship (B)
traveling at at .5c and the clock that is
at the 0 point(A) starts when it (B) passes the 0 point.
According to basic math, the object will pass by
the 93,000th line in 1/2 second.
and the 186,000th line in 1 second..
(silly basic math)

so...
What time does (B) pass the line according to
the time dilation of (B) while in motion?

In return, I ask that you commit seppuku or something that garners a
similar result. When you have completed this task, I will help you
learn.

"Eric Gisse" wrote in message
oups.com...
| In return, I ask that you commit seppuku or something that garners a
| similar result. When you have completed this task, I will help you
| learn.

Yet another simply afraid to give the answer and pleading
the fifth amendment silently.

"Spaceman" wrote in message
...
Lets suppose we have a flat surface that is
as far as we know infinite in length and width.

We mark a line and call it the 0 point.
we then mark lines that are 1 mile away from
this 0 point so we will have parallel lines every 1 mile.

An observer stays at the 0 point (A)
an second observer is in a spaceship (B)
traveling at at .5c and the clock that is
at the 0 point(A) starts when it (B) passes the 0 point.
According to basic math, the object will pass by
the 93,000th line in 1/2 second.
and the 186,000th line in 1 second..
(silly basic math)

so...
What time does (B) pass the line according to
the time dilation of (B) while in motion?

What 'object' ?

"OG" wrote in message
...
|
| "Spaceman" wrote in message
| ...
| Lets suppose we have a flat surface that is
| as far as we know infinite in length and width.
|
| We mark a line and call it the 0 point.
| we then mark lines that are 1 mile away from
| this 0 point so we will have parallel lines every 1 mile.
|
| An observer stays at the 0 point (A)
| an second observer is in a spaceship (B)
| traveling at at .5c and the clock that is
| at the 0 point(A) starts when it (B) passes the 0 point.
| According to basic math, the object will pass by
| the 93,000th line in 1/2 second.
| and the 186,000th line in 1 second..
| (silly basic math)
|
| so...
| What time does (B) pass the line according to
| the time dilation of (B) while in motion?
|
| What 'object' ?

The spaceship (B)..
sorry bout that.

Spaceman wrote:
"Eric Gisse" wrote in message
oups.com...
| In return, I ask that you commit seppuku or something that garners a
| similar result. When you have completed this task, I will help you
| learn.

Yet another simply afraid to give the answer and pleading
the fifth amendment silently.


I would give you the answer if I obtained something in return. I don't
get that warm fuzzy "helping people learn" feeling when I am explaining
something to you, so I want something tangible. I think ritual suicide,
or an honest attempt at, would be an adequate compensation.

In sci.physics, Spaceman

wrote
on Wed, 8 Feb 2006 20:09:11 -0500
:

"OG" wrote in message
...
|
| "Spaceman" wrote in message
| ...
| Lets suppose we have a flat surface that is
| as far as we know infinite in length and width.
|
| We mark a line and call it the 0 point.
| we then mark lines that are 1 mile away from
| this 0 point so we will have parallel lines every 1 mile.
|
| An observer stays at the 0 point (A)
| an second observer is in a spaceship (B)
| traveling at at .5c and the clock that is
| at the 0 point(A) starts when it (B) passes the 0 point.
| According to basic math, the object will pass by
| the 93,000th line in 1/2 second.
| and the 186,000th line in 1 second..
| (silly basic math)
|
| so...
| What time does (B) pass the line according to
| the time dilation of (B) while in motion?
|
| What 'object' ?

The spaceship (B)..
sorry bout that.



The spacecraft will pass by 161080.7 lines per second.
(93000 * sqrt(1+.5) / sqrt(1-.5) )

--
#191,
It's still legal to go .sigless.

Spaceman wrote:
Lets suppose we have a flat surface that is
as far as we know infinite in length and width.

We mark a line and call it the 0 point.
we then mark lines that are 1 mile away from
this 0 point so we will have parallel lines every 1 mile.

Measured how? According to what frame of reference?


An observer stays at the 0 point (A)
an second observer is in a spaceship (B)
traveling at at .5c and the clock that is
at the 0 point(A) starts when it (B) passes the 0 point.
According to basic math, the object will pass by
the 93,000th line in 1/2 second.
and the 186,000th line in 1 second..
(silly basic math)

so...
What time does (B) pass the line according to
the time dilation of (B) while in motion?