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| Tags: invacu, tom, uncle, zero |
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#1
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$ Mathematically speaking, a vacuum is ZERO particle COUNT.
Experimental MEASUREMENTs in AiR vary with AMBiENT particle COUNT.!! (EinsteiN SPECiFiED ZERO particle-COUNT, for the VELOCiTY of light.) (And, STP&g AiR is 26 Orders-of-Magnitude LESS EMPTY than "vacuum".) SPECiFiCALLY ..EinsteiN's ((focus)) is on a *ZERO particle-COUNT*.!! (Light VELOCiTY v VARiEs ..inversely, WiTH the PATH-particle-COUNT.) Light-VELOCiTY c is, NOW, a MATHEMATiCAL constant ..just as is pi.!! Light-VELOCiTY v "constancy", is ONLY per *CONSTANT particle-COUNT*. Light VELOCiTY v *DECREASES*, inversely, with PATH-particle-COUNT.!! $ CONCLUSiON: Light VELOCiTY v *iNCREASES*, inversely, with PATH-particle-COUNT.!! (Note, VARiOUS vacu ONLY exist in squeezed-SWiSS-cheese-LiKE minds.) Brian A M Stuckless ^ jem wrote: Harry wrote: "jem" wrote in message news:B2hlf.3958$fz5.1074@dukeread04... [John Kennaugh wrote earlier: 3/ It cannot be the speed relative to the observer because -=- insert ..see top of PAGE, dooOPs.!! -=- there is no causality whereby an observer's speed can effect the speed at which light leaves the source besides which light leaves the source when there is no observer so it can only be a function of the source.] SNIP Your claim was that the speed at which light is measured to leave its source can't depend on the speed of the measurer, but the *fact* that it *does* in a logically consistent theory (e.g. SR), means that your claim is wrong. It's as simple as that. What a big mistake! but *whose* mistake? Instead, in SRT it does not depend on the speed of either the source, the receiver, or the measurer. It is measured to be constant (in vacuum and at constant gravitational potential) relative to any calibrated inertial coordinate system. This system may be virtual, and all three may be moving arbitrarily relative to it. So at what speed does an SR observer measure light to leave its source, when the observer is approaching that source at speed v? (Read carefully this time). Is that speed independent of v? Zero particle-count-error-bars.!! (i.e. in-vacu) by Uncle Tom. |
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#2
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You know, the idea behind written communication is to use the tool not
for your own satisfaction, but rather to convey your message. Oh, but you did that, didn't you? Your message, having more to do with you than the speed of light, IS clear. |
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#3
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Joe Fischer wrote: General Relativity has a stress-energy
tensor, which includes not only mass but also energy and -=- PROFOUNDLY, there is NO "mass" ..in General Relativity (gtr). PROFOUNDLY, iRONiCALLY, there's NO GR "space-time-curvature". (The GR, G_uv = T_uv CANNOT be DEFiNED, in TERMs of "mass".!!) possibly other factors relating to density and momentum, -=- There is NO "mass -=- density and momentum", in GEOMETRY, duh. This is NOT fluffy-level math ..it's whole-wheat arithmetic.!! G*Mp*{mph} C1*(C2a*C2b) C1 -- --- -- = -- -- -- -- = -- = 4*pi*Vu*{e}*lo = 4*pi*#*{e}*c ; (n - 1) C2^2*c c C1*(p1*p2)*c C1*({e}^2*c^2)*c C1(q1*q2)*c^3 C1*{e}*c = -- --- -- -- = -- -- ---- -- -- = -- - --- - -- = -- -- -- C2^2 C2^2 C2^2 C2 . GENERAL GUESS photon mass [mph] = nA*{mph}*ls / rA = m1 = mD / n. PARTiCULAR iSS photon mass {mph} = 2*pi*h / tp*c^2 = hbar / ls*c = hbar / ts*c^2 = h / 2*pi*ls*c. $ Planck common-centre-of-mass (c.c.m.) orbitals GRAViTY acceleration g = (g1 + g2) = G*(M1 + m2) / (n - 1)*d^2: |G*(M1 + m2)| |4*(pi)^2*d| | 4*(pi)^2*r1 4*(pi)^2*r2 | |-- -- -- --| = |-- -- - --| = |(-- -- -- --) + (-- -- -- --)| |(n - 1)*d^2| | T^2 | | T^2 T^2 | | | |4*(pi)^2*(r1 + r2)| = |-- -- -- --| = |-- -- --- -- -- --| = (g1 + g2) = gravity g. | | | T^2 | Note therefore, as radii r1 & r2 vary and/or M1 & m2 vary, etc, then, BOTH, M1 & m2 can *TOUCH down* ON each other's SURFACE.!! Depending, of course, on M1's & m2's SiZE, SHAPE, DENSiTY, etc. Note, the dimension "d" = (r1 + r2) ..is "separation" distance; $ M1*v1^2 m2*v2^2 Also, note that -- - -- = -- - -- = M1*r1 = m2*r2. FiNALLY.. $ g1 g2 NOTE: Mp*lp = {mph)*ls = me*wls = Moo*loo / 4*pi = hbar / c. Brian A M Stuckless ^ |
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