When a cube of ice is floating in a bucket of water, what happens to the
water level when it melts?
What if the cube is underwater?
What if inside the cube there is trapped a metal ball. How are the above
answers different?
(I am interested only in the last question really)

In sci.physics
"Timaras" wrote:

When a cube of ice is floating in a bucket of water, what happens to the
water level when it melts?

It remains the same because the ice displaces exactly its mass when
floating.

What if the cube is underwater?

The level goes down about 9% of the volume of the original ice cube because
you are now displacing a greater volume of water than that contained in the
ice cube..

What if inside the cube there is trapped a metal ball. How are the above
answers different?


I assume the ball is not of sufficient mass to submerge the floating cube?
The level will do down but not by as much as the plain cube. In the case
of the submerged cube, the level drops by 9% of the volume of the cube -
the volume of the ball.

"Timaras" wrote in message
...
When a cube of ice is floating in a bucket of water, what happens to the
water level when it melts?
What if the cube is underwater?
What if inside the cube there is trapped a metal ball. How are the above
answers different?
(I am interested only in the last question really)

School ust be back in session.

I assume the ball is not of sufficient mass to submerge the floating cube?
The level will do down but not by as much as the plain cube.
What exactly do you mean by "plain cube"? The plain cube does not affect the
water level.

In the case
of the submerged cube, the level drops by 9% of the volume of the cube -
the volume of the ball.

How do you figure out this 9% ?

In sci.physics
"Timaras" wrote:

I assume the ball is not of sufficient mass to submerge the floating cube?
The level will do down but not by as much as the plain cube.
What exactly do you mean by "plain cube"? The plain cube does not affect the
water level.

The floating cube with NO ball imbedded within.

In the case
of the submerged cube, the level drops by 9% of the volume of the cube -
the volume of the ball.

How do you figure out this 9% ?

Because when water freezes, it expands to about 9% its liquid volume.

"Bruce" wrote in message
. ..
In sci.physics
"Timaras" wrote:

I assume the ball is not of sufficient mass to submerge the floating
cube?
The level will do down but not by as much as the plain cube.
What exactly do you mean by "plain cube"? The plain cube does not affect
the
water level.

The floating cube with NO ball imbedded within.

In the case
of the submerged cube, the level drops by 9% of the volume of the
cube -
the volume of the ball.

How do you figure out this 9% ?

Because when water freezes, it expands to about 9% its liquid volume.


I assume you mean it expands BY 9% (to 109%) of it's liquid volume. And if
thats true then when a cube (or any shape) of ice melts it loses only 8.25%
of it's volume.