Since there are really only 3 fundamental Variables in mechanics: Force
(f), [& weight (w)]; displacement (s), and time(t); this simplifies
acceleration to [a=2s/t^2]; so that the ratios w/g=f/a are also
simplified to wt^2/s = ft^2/s: These _ratios_ are the long sought
fundamental Constants of mechanics: 'Gravitational mass' (w/g), and
'Inertial mass' (f/a).

To simplify writing the equations. we'll use the following
abbreviations: Symbol # to abbreviate 1 pound, the symbol ' to
abbreviate 1 foot, and the symbol sec^2 to abbreviate 1 second
squared:

Therefo w/g=f/a; becomes: wt^2/s = ft^2/s = 1# sec^2/1'=2#
sec^2/2'=3# sec^2/3'= 4# sec^2/4';; up to thousands of pounds, or more.
[For the moon; the ratio of w/g is 5.53# sec^2/5.53 feet; for the
Earth; w/g is 32.174# sec^2/32.174feet.]

Notice that the units [pounds(#), seconds(sec), and feet(')] cancel;
leaving ONE pound second squared, per foot: Therefo ONE#
sec^2/'=wt^2/s=ft^2/s; applies anywhere, and (these ratios) are the
long sought constants of physics.

Don

"Don1" wrote in message
oups.com...

Since there are really only 3 fundamental Variables in mechanics: Force
(f), [& weight (w)]; displacement (s), and time(t); this simplifies
acceleration to [a=2s/t^2]; so that the ratios w/g=f/a are also

Have you thought in which direction the forces are acting in?

For a body (a point mass) on a horizontal frictionless surface, at rest,
it's weight force w=mg will be at normal N to the ground, therefore there
are no horizontal components of force due to the weight for this point mass.

That is, for x axis representing the horizontal plane, N_x = 0, N_y = mg

Even if the body moves along the frictionless horizontal surface, N_x = 0,
since mg is always normal to this surface. Therefore you can't equate mg
with the f=ma at all.

Dyl.

Don1 wrote:
Since there are really only 3 fundamental Variables in mechanics: Force
(f), [& weight (w)]; displacement (s), and time(t); this simplifies
acceleration to [a=2s/t^2]; so that the ratios w/g=f/a are also
simplified to wt^2/s = ft^2/s: These _ratios_ are the long sought
fundamental Constants of mechanics: 'Gravitational mass' (w/g), and
'Inertial mass' (f/a).

To simplify writing the equations. we'll use the following
abbreviations: Symbol # to abbreviate 1 pound, the symbol ' to
abbreviate 1 foot, and the symbol sec^2 to abbreviate 1 second
squared:

Therefo w/g=f/a; becomes: wt^2/s = ft^2/s = 1# sec^2/1'=2#
sec^2/2'=3# sec^2/3'= 4# sec^2/4';; up to thousands of pounds, or more.
[For the moon; the ratio of w/g is 5.53# sec^2/5.53 feet; for the
Earth; w/g is 32.174# sec^2/32.174feet.]

Notice that the units [pounds(#), seconds(sec), and feet(')] cancel;
leaving ONE pound second squared, per foot: Therefo ONE#
sec^2/'=wt^2/s=ft^2/s; applies anywhere, and (these ratios) are the
long sought constants of physics.

Don

you are a fool.

your post is perfect example of why the si system is better than the
imperial system.

not to mention your confusion over how forces work.