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| Tags: circular, dilatation, motion, time |
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#31
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"Eric Gisse" escreveu na mensagem ... On May 4, 10:07 am, "El Enrrabadore-mor" wrote: "Greg Neill" escreveu na sting.com..."El Enrrabadore-mor" wrote in message Can you see how much out-of-topic you are? Hey, *you're* the one who posted the nonsense, "A system in resonance is a closed system that exchanges no energy with surroundings. Energy is conserved in resonance." I just pointed out your misconceptions and errors. Obviously you must agree that for a case of electromagnetic radiation I'm right. Why? Microwave ovens have a nonunity Q factor. I'll tell you why. Because no friction, dissipation, or damping exists in electromagnetic radiation (or Maxwell equations). The Q factor is a direct measurement of the dissipation factor. Dissipation is the CAUSE that limits the theoretical infinite displacement value of resonance. Did you know? Or do I need to draw you a picture? Like I said, NO MORE RESONANCE please. |
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#32
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"Greg Neill" escreveu na mensagem m... "El Enrrabadore-mor" wrote in message [aka "Phantom"?] Now, energy is the time derivative of the angular momentum, and that time is an absolute time. Huh? The time derivative of angular momentum is torque. Remember T = dL/dt? Just because the units of Torque can be equated to Joules does not mean that it is appropriate to interpret them in such a way. Rotational kinetic energy is still given by (1/2)*I*w^2, the analog of the linear (1/2)*m*v^2. I'm surprised that you would attempt to perpetrate such a flimsy subterfuge. You've missed the fact that during a given amount of time a torque T = dL/dt have moved the body a given angle theta (which is a basic coordinate). You forget the fact that derivatives are of the form: d/dt f(x(t)) = x df/dt x - is an angular displacement Energy = Torque . angular displacement (dot product) Power = Torque . angular velocity (dot product) Power = Time derivative of energy This is hard stuff. Uniform circular motion and uniformly accelerated motions have somehow the same basic equations: displacement = 1/2 g t^2 velocity = g t acceleration = g Gravity is an uniformly accelerated motion. Also remember that kinetic energy is frame dependent, even for Newtonian physics, so time dilation poses no conceptual problems for energy in this regard. Sure, that's why I keep the point about the center of rotation being a fixed point in space. You'll no doubt be even more disturbed to learn that General Relativity essentially discards nonlocal conservation of energy. If so, the mystery is solved. |
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#33
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On May 4, 1:49*pm, "El Enrrabadore-mor"
wrote: "Eric Gisse" escreveu na ... On May 4, 10:07 am, "El Enrrabadore-mor" wrote: "Greg Neill" escreveu na sting.com..."El Enrrabadore-mor" wrote in message Can you see how much out-of-topic you are? Hey, *you're* the one who posted the nonsense, "A system in resonance is a closed system that exchanges no energy with surroundings. Energy is conserved in resonance." I just pointed out your misconceptions and errors. Obviously you must agree that for a case of electromagnetic radiation I'm right. Why? Microwave ovens have a nonunity Q factor. I'll tell you why. Because no friction, dissipation, or damping exists in electromagnetic radiation (or Maxwell equations). The Q factor is a direct measurement of the dissipation factor. Dissipation is the CAUSE that limits the theoretical infinite displacement value of resonance. Did you know? Or do I need to draw you a picture? Like I said, NO MORE RESONANCE please. Yes, let's go back to you not understanding the Mossbauer effect. |
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#34
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"Prof Barnhart" escreveu na mensagem . .. To progress further requires conceptualization, not about more transient particles, but about the true electromagnetic nature of reality. I'm not sure about a "true electromagnetic nature of reality". Sure there are lots of important "mechanisms" into electromagnetism, that show effects acting instantaneously at orthogonal directions (axis). Light is an electric field acting 90 degrees out-of-phase from the associated magnetic field. (90 degrees out-of-phase means orthogonal to my understanding). Reality is made of mass and electromagnetism (massless). Both don't seam to mix quite well. In terms of mass behaviour, orthogonal like phenomenon only in gyroscopes. |
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#35
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On May 3, 2:25 pm, "El Enrrabadore-mor"
wrote: It is said that a speeding clock shows less elapsed time than the stay-at-home clock, because (if already speeding) it is running at a slower rate. Or else, because it had run at a slower rate when it was speeding, assuming now it is stopped near the stay-at-home clock. The funny thing about this is that time and length change at the same time, but not the ratio between both (velocity). If we keep length constant, the only possible solution is uniform circular motion. That is a twin travelling in circles, of constant radius r, around the first twin assumed to be stopped at the center of rotation. Let's say the radius r is a constant value of 100 light-seconds (r = 100c). The speeding twin goes on a spaceship at 0.999c. Therefore, the angular speed 'omega' is v/r = 0.999c/100c = 0.01 rad/s. The speeding twin takes 628 seconds to have a complete turn of 360 degrees. For small values of t, the speeding twin is almost going in a straight line, but is fact it has a centripetal force f = m c^2/r = m c/100, being the centripetal acceleration c/100, towards the first stopped twin in the center of rotation. Both twins have powerful antennas that broadcast radio spherically around the entire space. Both twins are tuned to each other frequency/radio-station. Since the distance r = 100c between the emitter and the receptor is constant, obviously that both twin will hear each other radio (music) in perfect conditions. Nevertheless, relativity says that the clock synchronising the emission of the speeding twin must be running at a clock rate close to zero. Theoretically, the speeding twin won't have any trouble receiving the stay-at-home radio emission, but the stay-at-home twin cannot receive the speeding twin radio emission, because the speeding clock is running near zero. The speeding twin radio emission will take infinite time to broadcast one single spoken word. The stay-at-home will be dead by the time the speeding twin could say a single word. The trouble seams to be the acceleration: a = (0.999)^2 c/100 which is about c/100. (Here the number 100 means 100 seconds). That's a huge gravity field of 300,000g at a radius of 100 light-seconds, just imagine the value it will be at Earth radius based on the inverse-square Law.) I presume that such acceleration of 300,000g will be responsible for a clock speed up rate that should keep time unchanged after all. Ys, Einstein proposed this as a thought experiment. However, his analysis was done using the inertial frame as seen by an observer at the center of the earth. The moving clock on the edge of the circle will seem to be slowed down relative to the clock at the center of the circle, the one that is not accelerating. The clock in the center will seem speeded up compared to the clock on the circle. However, this clock is not accelerating. Yes, the assymmetry come from the centripetal force. The twin in the center does not experience the centripetal force as the twin on the circle. The clocks relative to each other will see differences in the rate of ticking. The clock with the largest acceleration ticks the fastest. The other clocks lag behind. However, the clock that accelerates least (i.e., moves at the slowest tangential speed on the circle) lags behind the clocks with more acceleration. Any comments welcome. This is a description of the Hafele-Keating experiment. The experiment was performed, and matched Einsteins predictions. Hafele had two articles in Nature that describe both the experiment and the analysis of the results. The experiment was performed with atomic clocks. It is a classic validation of special relativity. |
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#36
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"Darwin123" escreveu na mensagem ... On May 3, 2:25 pm, "El Enrrabadore-mor" wrote: It is said that a speeding clock shows less elapsed time than the stay-at-home clock, because (if already speeding) it is running at a slower rate. Or else, because it had run at a slower rate when it was speeding, assuming now it is stopped near the stay-at-home clock. The funny thing about this is that time and length change at the same time, but not the ratio between both (velocity). If we keep length constant, the only possible solution is uniform circular motion. That is a twin travelling in circles, of constant radius r, around the first twin assumed to be stopped at the center of rotation. Let's say the radius r is a constant value of 100 light-seconds (r = 100c). The speeding twin goes on a spaceship at 0.999c. Therefore, the angular speed 'omega' is v/r = 0.999c/100c = 0.01 rad/s. The speeding twin takes 628 seconds to have a complete turn of 360 degrees. For small values of t, the speeding twin is almost going in a straight line, but is fact it has a centripetal force f = m c^2/r = m c/100, being the centripetal acceleration c/100, towards the first stopped twin in the center of rotation. Both twins have powerful antennas that broadcast radio spherically around the entire space. Both twins are tuned to each other frequency/radio-station. Since the distance r = 100c between the emitter and the receptor is constant, obviously that both twin will hear each other radio (music) in perfect conditions. Nevertheless, relativity says that the clock synchronising the emission of the speeding twin must be running at a clock rate close to zero. Theoretically, the speeding twin won't have any trouble receiving the stay-at-home radio emission, but the stay-at-home twin cannot receive the speeding twin radio emission, because the speeding clock is running near zero. The speeding twin radio emission will take infinite time to broadcast one single spoken word. The stay-at-home will be dead by the time the speeding twin could say a single word. The trouble seams to be the acceleration: a = (0.999)^2 c/100 which is about c/100. (Here the number 100 means 100 seconds). That's a huge gravity field of 300,000g at a radius of 100 light-seconds, just imagine the value it will be at Earth radius based on the inverse-square Law.) I presume that such acceleration of 300,000g will be responsible for a clock speed up rate that should keep time unchanged after all. Ys, Einstein proposed this as a thought experiment. However, his analysis was done using the inertial frame as seen by an observer at the center of the earth. The moving clock on the edge of the circle will seem to be slowed down relative to the clock at the center of the circle, the one that is not accelerating. The clock in the center will seem speeded up compared to the clock on the circle. However, this clock is not accelerating. Yes, the assymmetry come from the centripetal force. The twin in the center does not experience the centripetal force as the twin on the circle. The clocks relative to each other will see differences in the rate of ticking. The clock with the largest acceleration ticks the fastest. The other clocks lag behind. However, the clock that accelerates least (i.e., moves at the slowest tangential speed on the circle) lags behind the clocks with more acceleration. Any comments welcome. This is a description of the Hafele-Keating experiment. The experiment was performed, and matched Einsteins predictions. Hafele had two articles in Nature that describe both the experiment and the analysis of the results. The experiment was performed with atomic clocks. It is a classic validation of special relativity. Clearly, your arguments blame acceleration to be the cause of time dilatation. Fine. The circular motion at constant angular velocity and constant radius adds something more. Not only you have acceleration, but also velocity relative to any inertial frame of reference nearby. You cannot add both effects: Velocity + Acceleration If you sum both effects chances are that you come up with the conclusion that they cancel each other out. That's what happens for a stable orbit anyway. a) - Acceleration causes the clock to speed up. b) - Velocity causes the clock to speed down. Summing both a) and b) will give what ? 1 - Absolute time? 2 - Partially absolute time? 3 - Discard one of the effects and have relativity time dilatation solution? I bet on conservation of energy, but I was already told that General Relativity essentially discards nonlocal conservation of energy. That simply shots down a Physics pillar stone, but who cares? Unfortunately, the local process looks to be irreversible. If it was reversible, non-conservation of energy locally leads to local free-energy generation. |
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#37
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On May 4, 6:53*am, Tom Roberts wrote in
sci.physics.relativity: El Enrrabadore-mor wrote: It is said that a speeding clock shows less elapsed time than the stay-at-home clock, because (if already speeding) it is running at a slower rate. Or else, because it had run at a slower rate when it was speeding, assuming now it is stopped near the stay-at-home clock. While that may be "said", it is wrong in SR. In SR, the motion of a clock does not affect its rate. But when one compares identical clocks that have traveled different paths, their elapsed proper times can differ, due to their different trajectories, not due to any change in their tick rates. [... circular motion] Bailey et al put muons into a storage ring and measured their lifetime for their circular path. Within experimental resolutions, they have the same lifetime as muons traveling in a straight line, so their circular path did NOT affect the internal "clock" that controls their decay. They were subject to an acceleration of about 10^18 g (1 g = 9.8 m/s^2), which is FAR greater than claimed in your example. Note this experiment is a direct implementation of the circular twin scenario, when combined with measurements of muon decay at rest. Tom Roberts Roberts Roberts how exactly do you measure the lifetime of muons at rest? When cosmic-ray muons bump into an obstacle so that their speed instantly changes from about 300000km/s to zero, their forced disintegration makes Einsteinians sing "Divine Einstein" and go into convulsions. Simply because in Einstein zombie world, when a muon undergoes a terrible crash, this muon is "at rest" during the crash and, in pefect accordance with Divine Albert's Divine Theory, disintegrates more quickly than another muon that has not undergone a crash: http://web.mit.edu/c_hill/www/muons_paper.pdf "In this experiment, we measure two of the basic properties of the muon, namely, its mean lifetime and mass in its rest frame. We measure the decay curve of cosmic-ray muons that have come to rest in a plastic scintillator by looking for electrons produced in their decay." Pentcho Valev |
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#38
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"El Enrrabadore-mor" wrote in
: "Tom Roberts" escreveu na mensagem ... One can analyze their experiment (including comparison to muon decay at rest) in two different ways: a) use the overall inertial frame of their storage ring and apply SR. b) use the equivalence principle of GR, and treat the LOCAL acceleration of the stored muons as a gravitational field and compute the gravitational time dilation in LOCAL coordinates in which the stored muon is at rest. These obtain the same answer. Moreover: Your a) appeals on velocity as the cause of time dilatation. Your b) appeals on acceleration (or gravity by equivalence principle) to be the cause on time dilatation. It is not the velocity or the acceleration (in SR) that explains the time difference. It is the different trajectory. Trajectory through space-time. Physics say: c) Acceleration is the time derivative of velocity. My c) proves your a) and b) to be incompatible, since time used on the derivative is ABSOLUTE TIME. a = dv/dt says nothing about ABSOLUTE time. Where did you get the impression that it did? dt is CHANGE in time. How can a time derivative be based on absolute time and the time himself not being absolute time? Tom Roberts -- bz please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set. -- bz please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set. remove ch100-5 to avoid spam trap |
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#39
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"El Enrrabadore-mor" wrote in message
"Greg Neill" escreveu na mensagem m... "El Enrrabadore-mor" wrote in message [aka "Phantom"?] Now, energy is the time derivative of the angular momentum, and that time is an absolute time. Huh? The time derivative of angular momentum is torque. Remember T = dL/dt? Just because the units of Torque can be equated to Joules does not mean that it is appropriate to interpret them in such a way. Rotational kinetic energy is still given by (1/2)*I*w^2, the analog of the linear (1/2)*m*v^2. I'm surprised that you would attempt to perpetrate such a flimsy subterfuge. You've missed the fact that during a given amount of time a torque T = dL/dt have moved the body a given angle theta (which is a basic coordinate). No, I didn't miss anything. A torque doesn't have to be accompanied by an angular movement any more than a static force does. You forget the fact that derivatives are of the form: d/dt f(x(t)) = x df/dt x - is an angular displacement Energy = Torque . angular displacement (dot product) No. Work is torque x displacement. Power = Torque . angular velocity (dot product) Power = Time derivative of energy This is hard stuff. Not for everyone. Uniform circular motion and uniformly accelerated motions have somehow the same basic equations: displacement = 1/2 g t^2 velocity = g t acceleration = g Gravity is an uniformly accelerated motion. Also remember that kinetic energy is frame dependent, even for Newtonian physics, so time dilation poses no conceptual problems for energy in this regard. Sure, that's why I keep the point about the center of rotation being a fixed point in space. You'll no doubt be even more disturbed to learn that General Relativity essentially discards nonlocal conservation of energy. If so, the mystery is solved. |
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#40
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"El Enrrabadore-mor" wrote in message
"Prof Barnhart" escreveu na mensagem . .. To progress further requires conceptualization, not about more transient particles, but about the true electromagnetic nature of reality. I'm not sure about a "true electromagnetic nature of reality". Sure there are lots of important "mechanisms" into electromagnetism, that show effects acting instantaneously at orthogonal directions (axis). Light is an electric field acting 90 degrees out-of-phase from the associated magnetic field. (90 degrees out-of-phase means orthogonal to my understanding). No, in a propagating transverse electromagnetic wave the electric and magnetic fields may be orthogonal, but they are in phase. http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html Reality is made of mass and electromagnetism (massless). Both don't seam to mix quite well. In terms of mass behaviour, orthogonal like phenomenon only in gyroscopes. |
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