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| Tags: acoustic, sources, sum, two |
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#1
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If I have two acoustic sources transmitting the exact same signal
(perfectly correlated), i.e., a stereo system playing a monaural signal, then what total power would be perceived at the listening position without accounting for path loss? Let's say each channel (left and right) is transmitting the exact same acoustic power, P watts. Let's also assume we're in an anechoic chamber so that there are no reflections, and that the positioning and symmetry is perfect. On the one hand, you'd expect 2P watts at the listening position, i.e., a 3 dB increase. That makes sense - two speakers, 3 dB increase in power. But on the other hand, you might expect acoustic pressures to sum, so that you'd get a 6 dB increase. But this doesn't seem to make sense since you'd be getting 3 dB better than the available power. Does near-field/far-field matter? Any help educating me would be appreciated. I have the Beranak and Zwicker texts but obviously and not too familiar with them, but they are available for reference should you care to point me to the right page. -- % Randy Yates % "And all that I can do %% Fuquay-Varina, NC % is say I'm sorry, %%% 919-577-9882 % that's the way it goes..." %%%% % Getting To The Point', *Balance of Power*, ELO http://home.earthlink.net/~yatescr |
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#2
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"Randy Yates" wrote in message ... If I have two acoustic sources transmitting the exact same signal (perfectly correlated), i.e., a stereo system playing a monaural signal, then what total power would be perceived at the listening position without accounting for path loss? Let's say each channel (left and right) is transmitting the exact same acoustic power, P watts. Let's also assume we're in an anechoic chamber so that there are no reflections, and that the positioning and symmetry is perfect. On the one hand, you'd expect 2P watts at the listening position, i.e., a 3 dB increase. That makes sense - two speakers, 3 dB increase in power. But on the other hand, you might expect acoustic pressures to sum, so that you'd get a 6 dB increase. But this doesn't seem to make sense since you'd be getting 3 dB better than the available power. Does near-field/far-field matter? Any help educating me would be appreciated. I have the Beranak and Zwicker texts but obviously and not too familiar with them, but they are available for reference should you care to point me to the right page. -- % Randy Yates % "And all that I can do %% Fuquay-Varina, NC % is say I'm sorry, %%% 919-577-9882 % that's the way it goes..." %%%% % Getting To The Point', *Balance of Power*, ELO http://home.earthlink.net/~yatescr I'll vote for getting a maximum of twice the power. You will have to ignore the possibility that there will be some interference between the two, in which case you could get zero power in some places. Michael |
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#3
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Randy Yates wrote: If I have two acoustic sources transmitting the exact same signal (perfectly correlated), i.e., a stereo system playing a monaural signal, then what total power would be perceived at the listening position without accounting for path loss? Let's say each channel (left and right) is transmitting the exact same acoustic power, P watts. Let's also assume we're in an anechoic chamber so that there are no reflections, and that the positioning and symmetry is perfect. On the one hand, you'd expect 2P watts at the listening position, i.e., a 3 dB increase. That makes sense - two speakers, 3 dB increase in power. But on the other hand, you might expect acoustic pressures to sum, so that you'd get a 6 dB increase. But this doesn't seem to make sense since you'd be getting 3 dB better than the available power. Does near-field/far-field matter? Google "ripple tank" http://demo.physics.uiuc.edu/LectDem....idc?DemoID=48 http://www.physics.montana.edu/demon...aterwaves.html http://en.wikipedia.org/wiki/Ripple_tank Two waves will either add or subtract intensity, depending on their relative *phase*, which will vary with their distance from their sources (and the relative phase at the moment they are emitted). The pattern produced is one of 'beams' of waves spreading out as they get further from the source. 'On' the beam the intensity adds up, but between the beams the intensity subtracts and a 'dead space' is produced. The exact geometry of these 'beams' will depend on the wavelength of the wave and the distance between the sources as well as the speed of the waves. In ripple tank images, the 'beams' are zones where the wave pattern is clear and strongest, and the 'dead zones' are the areas where the ripple pattern is fuzziest and grey. As the images in the Wiki article suggest, the presence of reflective barriers complicates the acoustics immensely as each point on the wall can be treated as another 'source'. HTH Tom Davidson Richmond, VA |
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