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#71
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"John C. Polasek" wrote in message ... On Tue, 01 Jul 2008 17:28:17 GMT, "Bill Miller" wrote: "John C. Polasek" wrote in message news ![]() ruthless snip Even in introductory texts, it wouldn't be terribly difficult to say something like, "Maxwell's equations demonstrate a clear relationship between Electric(E) and Magnetic (H) fields. This is sometimes erroneously interpreted as meaning that E causes H and H causes E. However, a careful analysis shows that E fields and H fields are sololy caused by charges and the movement of charges."" Not too hard. You are full of beans. Yep... Had some last night. As soon as the currents pulse up and down in the antenna, a good portion of the energy exits as EM waves that take off across the country. They're on their own and don't need overt charges or currents. E, D, B and H are taken care of by polarization of eps0 and mu0, properties of the vacuum. They exchange energies as they go along. Your case would be stronger if E and H (in an EM wave) were out of phase. Then we would have a situation analagous to -- say -- a spring or water waves, wherein kinetic energy gets swapped for potential energy, etc. BUT E and H are in phase! How in the world can anyone imagine that two in phase and contiguaous signals are *swapping* energy? If you can do so, I believe we would all love to hear how it works. OK, here's how they swap energy, (and remember, you promised to love to hear this). Using spring mass for simplicity I just dropped everything, rushed outside and looked at my antennas. No matter how hard I looked, I couldn't find a spring. and recognizing that the wave will be sinusoidal, the force on the spring is proportional to displacement Fk = F0 sin wt (say) The force on the mass is proportional to acceleration, two derivatives removed, so it's 180 degrees out of phase. Fm = - w^2F0 sin wt The energies likewise peak 180 degrees apart. I'm sorry, John. I still don' see no spring! And while Saint Albert (and the bomb) taught us that Energy and Mass have equivalency, I do not see where mass enters into this situation. Are you perhaps suggesting that the free space epsilon exhibits the same type of spring-like latency that we see in the epsilon of many solid dielectrics? If so, then, yes, we see a phase shift. But I am not aware of any such phase shift that has bee measured in free space. If this is your suggestion, then show us the free space experimental evidence, please. So you were approximately correct, that they are in phase, yes, in a larger sense. After all, what's a minus sign? Well, shucks, let's just admit that they are out of phase, as you were opining, making my case stronger as you point out. I'm gratified. THEN stand by your phone for the Stockholm call! Your assumption of currents and charges being present and essential is just as valid as the teams now looking for Wimps and Machos to explain the dark matter problem. Currents and charges are essential to LAUNCH the wave(s). Afterwards, the separate E and H signals are in lock step and isolated. By the way which do you prefer: D = E and B = H or D = eps0E and B = mu0H ? I pick.... Let's see... Door number... Ummm...Well... Oh gosh, I just can't decide! You dodged the D=E bullet. That's a sure sign of a benighted cgs'er who at least has the decency to feel a little guilty. OK You caught me! I choose... British Thermal Units and Furlongs Per Fortnight Bill Bill Timo Nieminen - Home page: http://www.physics.uq.edu.au/people/nieminen/ E-prints: http://eprint.uq.edu.au/view/person/...,_Timo_A..html Shrine to Spirits: http://www.users.bigpond.com/timo_nieminen/spirits.html John Polasek |
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#72
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On Tue, 01 Jul 2008 21:40:52 GMT, "Bill Miller"
wrote: "John C. Polasek" wrote in message .. . On Tue, 01 Jul 2008 17:28:17 GMT, "Bill Miller" wrote: "John C. Polasek" wrote in message news ![]() ruthless snip Even in introductory texts, it wouldn't be terribly difficult to say something like, "Maxwell's equations demonstrate a clear relationship between Electric(E) and Magnetic (H) fields. This is sometimes erroneously interpreted as meaning that E causes H and H causes E. However, a careful analysis shows that E fields and H fields are sololy caused by charges and the movement of charges."" Not too hard. You are full of beans. Yep... Had some last night. As soon as the currents pulse up and down in the antenna, a good portion of the energy exits as EM waves that take off across the country. They're on their own and don't need overt charges or currents. E, D, B and H are taken care of by polarization of eps0 and mu0, properties of the vacuum. They exchange energies as they go along. Your case would be stronger if E and H (in an EM wave) were out of phase. Then we would have a situation analagous to -- say -- a spring or water waves, wherein kinetic energy gets swapped for potential energy, etc. BUT E and H are in phase! How in the world can anyone imagine that two in phase and contiguaous signals are *swapping* energy? If you can do so, I believe we would all love to hear how it works. OK, here's how they swap energy, (and remember, you promised to love to hear this). Using spring mass for simplicity I just dropped everything, rushed outside and looked at my antennas. No matter how hard I looked, I couldn't find a spring. and recognizing that the wave will be sinusoidal, the force on the spring is proportional to displacement Fk = F0 sin wt (say) The force on the mass is proportional to acceleration, two derivatives removed, so it's 180 degrees out of phase. Fm = - w^2F0 sin wt The energies likewise peak 180 degrees apart. I'm sorry, John. I still don' see no spring! You have not looked at my model of the ether (pairspace) on my website. The springs are right in front of your nose; capacitive energy is stored in the extension of the springs: dx = E*e/K. It is the only arrangement that will duplicate the action of eps0. The spring/mass resonance for the bound charges in space is w = sqrt(K/m) = 1.693e22 rad/sec. The frequency response of any radiation frequency f or w, fits on a Bode diagram, showing the mass has very little effect till we approach resonance: Kx = mW^2x Fm/Fk = w^2/W^2 And while Saint Albert (and the bomb) taught us that Energy and Mass have equivalency, I do not see where mass enters into this situation. Are you perhaps suggesting that the free space epsilon exhibits the same type of spring-like latency that we see in the epsilon of many solid dielectrics? If so, then, yes, we see a phase shift. Of course I am. See the website. It all works. But I am not aware of any such phase shift that has bee measured in free space. If this is your suggestion, then show us the free space experimental evidence, please. So you were approximately correct, that they are in phase, yes, in a larger sense. After all, what's a minus sign? Well, shucks, let's just admit that they are out of phase, as you were opining, making my case stronger as you point out. I'm gratified. THEN stand by your phone for the Stockholm call! Your assumption of currents and charges being present and essential is just as valid as the teams now looking for Wimps and Machos to explain the dark matter problem. Currents and charges are essential to LAUNCH the wave(s). Afterwards, the separate E and H signals are in lock step and isolated. By the way which do you prefer: D = E and B = H or D = eps0E and B = mu0H ? I pick.... Let's see... Clearly it would be fruitless for me to go through a whole lot of handsprings for someone who still thinks the vacuum is empty and D=E and B=H, equations that are easy to memorize, but which, even with a little more substance added, barely approach tautology. Maxwell's Ddot lives! Oh gosh, I just can't decide! You dodged the D=E bullet. That's a sure sign of a benighted cgs'er who at least has the decency to feel a little guilty. OK You caught me! I choose... British Thermal Units and Furlongs Per Fortnight Bill Bill John Polasek http://www.dualspace.net |
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#73
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"John C. Polasek" wrote in message ... On Tue, 01 Jul 2008 21:40:52 GMT, "Bill Miller" wrote: "John C. Polasek" wrote in message . .. On Tue, 01 Jul 2008 17:28:17 GMT, "Bill Miller" wrote: "John C. Polasek" wrote in message news
ruthless snipEven in introductory texts, it wouldn't be terribly difficult to say something like, "Maxwell's equations demonstrate a clear relationship between Electric(E) and Magnetic (H) fields. This is sometimes erroneously interpreted as meaning that E causes H and H causes E. However, a careful analysis shows that E fields and H fields are sololy caused by charges and the movement of charges."" Not too hard. You are full of beans. Yep... Had some last night. As soon as the currents pulse up and down in the antenna, a good portion of the energy exits as EM waves that take off across the country. They're on their own and don't need overt charges or currents. E, D, B and H are taken care of by polarization of eps0 and mu0, properties of the vacuum. They exchange energies as they go along. Your case would be stronger if E and H (in an EM wave) were out of phase. Then we would have a situation analagous to -- say -- a spring or water waves, wherein kinetic energy gets swapped for potential energy, etc. BUT E and H are in phase! How in the world can anyone imagine that two in phase and contiguaous signals are *swapping* energy? If you can do so, I believe we would all love to hear how it works. OK, here's how they swap energy, (and remember, you promised to love to hear this). Using spring mass for simplicity I just dropped everything, rushed outside and looked at my antennas. No matter how hard I looked, I couldn't find a spring. and recognizing that the wave will be sinusoidal, the force on the spring is proportional to displacement Fk = F0 sin wt (say) The force on the mass is proportional to acceleration, two derivatives removed, so it's 180 degrees out of phase. Fm = - w^2F0 sin wt The energies likewise peak 180 degrees apart. I'm sorry, John. I still don' see no spring! You have not looked at my model of the ether (pairspace) on my website. The springs are right in front of your nose; capacitive energy is stored in the extension of the springs: dx = E*e/K. It is the only arrangement that will duplicate the action of eps0. The spring/mass resonance for the bound charges in space is w = sqrt(K/m) = 1.693e22 rad/sec. The frequency response of any radiation frequency f or w, fits on a Bode diagram, showing the mass has very little effect till we approach resonance: Kx = mW^2x Fm/Fk = w^2/W^2 And while Saint Albert (and the bomb) taught us that Energy and Mass have equivalency, I do not see where mass enters into this situation. Are you perhaps suggesting that the free space epsilon exhibits the same type of spring-like latency that we see in the epsilon of many solid dielectrics? If so, then, yes, we see a phase shift. Of course I am. See the website. It all works. But I am not aware of any such phase shift that has bee measured in free space. If this is your suggestion, then show us the free space experimental evidence, please. So you were approximately correct, that they are in phase, yes, in a larger sense. After all, what's a minus sign? Well, shucks, let's just admit that they are out of phase, as you were opining, making my case stronger as you point out. I'm gratified. THEN stand by your phone for the Stockholm call! Your assumption of currents and charges being present and essential is just as valid as the teams now looking for Wimps and Machos to explain the dark matter problem. Currents and charges are essential to LAUNCH the wave(s). Afterwards, the separate E and H signals are in lock step and isolated. By the way which do you prefer: D = E and B = H or D = eps0E and B = mu0H ? I pick.... Let's see... Clearly it would be fruitless for me to go through a whole lot of handsprings for someone who still thinks the vacuum is empty and D=E and B=H, equations that are easy to memorize, but which, even with a little more substance added, barely approach tautology. Maxwell's Ddot lives! John... Extraordinary claims require extraordinary proofs. Although you may have forgotten, you and I swapped several private messages after I visited your website a year or so a go. (This was about the time that Benj asked about magnetism caused by D & I pointed him at Jefimenko.) At that time, I told you that -- primarily due to the appearance of your site and the quality of the writeup(s) -- I found your fascinating propoition to dramatically lack credibility. I gave you some epecific suggestions as to how you could improve both. I'm afraid I still have my original opinion. All the best, Bill Oh gosh, I just can't decide! You dodged the D=E bullet. That's a sure sign of a benighted cgs'er who at least has the decency to feel a little guilty. OK You caught me! I choose... British Thermal Units and Furlongs Per Fortnight Bill Bill John Polasek http://www.dualspace.net |
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#74
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On 2 Jul, 03:04, John C. Polasek wrote:
On Tue, 01 Jul 2008 21:40:52 GMT, "Bill Miller" wrote: "John C. Polasek" wrote in message .. . On Tue, 01 Jul 2008 17:28:17 GMT, "Bill Miller" wrote: "John C. Polasek" wrote in message news
ruthless snipEven in introductory texts, it wouldn't be terribly difficult to say something like, "Maxwell's equations demonstrate a clear relationship between Electric(E) and Magnetic (H) fields. This is sometimes erroneously interpreted as meaning that E causes H and H causes E. However, a careful analysis shows that E fields and H fields are sololy caused by charges and the movement of charges."" Not too hard. You are full of beans. Yep... Had some last night. As soon as the currents pulse up and down in the antenna, a good portion of the energy exits as EM waves that take off across the country. They're on their own and don't need overt charges or currents. E, D, B and H are taken care of by polarization of eps0 and mu0, properties of the vacuum. They exchange energies as they go along. Your case would be stronger if E and H (in an EM wave) were out of phase. Then we would have a situation analagous to -- say -- a spring or water waves, wherein kinetic energy gets swapped for potential energy, etc. BUT E and H are in phase! How in the world can anyone imagine that two in phase and contiguaous signals are *swapping* energy? If you can do so, I believe we would all love to hear how it works. OK, here's how they swap energy, (and remember, you promised to love to hear this). Using spring mass for simplicity I just dropped everything, rushed outside and looked at my antennas. No matter how hard I looked, I couldn't find a spring. and recognizing that the wave will be sinusoidal, the force on the spring is proportional to displacement Fk = F0 sin wt *(say) The force on the mass is proportional to acceleration, two derivatives removed, so it's 180 degrees out of phase. Fm = - w^2F0 sin wt The energies likewise peak 180 degrees apart. I'm sorry, John. I still don' see no spring! You have not looked at my model of the ether (pairspace) on my website. The springs are right in front of your nose; capacitive energy is stored in the extension of the springs: *dx = E*e/K. It is the only arrangement that will duplicate the action of eps0. The spring/mass resonance for the bound charges in space is * * * * w = sqrt(K/m) = 1.693e22 rad/sec. The frequency response of any radiation frequency f or w, fits on a Bode diagram, showing the mass has very little effect till we approach resonance: * * * * Kx = mW^2x * * * * Fm/Fk = w^2/W^2 And while Saint Albert (and the bomb) taught us that Energy and Mass have equivalency, I do not see where mass enters into this situation. Are you perhaps suggesting that the free space epsilon exhibits the same type of spring-like latency that we see in the epsilon of many solid dielectrics? If so, then, yes, we see a phase shift. Of course I am. See the website. It all works. But I am not aware of any such phase shift that has bee measured in free space. If this is your suggestion, then show us the free space experimental evidence, please. So you were approximately correct, that they are in phase, yes, in a larger sense. After all, what's a minus sign? Well, shucks, let's just admit that they are out of phase, as you were opining, making my case stronger as you point out. I'm gratified. THEN stand by your phone for the Stockholm call! Your assumption of currents and charges being present and essential is just as valid as the teams now looking for Wimps and Machos to explain the dark matter problem. Currents and charges are essential to LAUNCH the wave(s). Afterwards, the separate E and H signals are in lock step and isolated. By the way which do you prefer: D = E *and B = H or D = eps0E and B = mu0H *? I pick.... Let's see... Clearly it would be fruitless for me to go through a whole lot of handsprings for someone who still thinks the vacuum is empty and D=E and B=H, equations that are easy to memorize, but which, even with a little more substance added, barely approach tautology. Maxwell's Ddot lives! Oh gosh, I just can't decide! You dodged the D=E bullet. That's a sure sign of a benighted cgs'er who at least has the decency to feel a little guilty. OK You caught me! I choose... British Thermal Units and Furlongs Per Fortnight Bill Bill John Polasekhttp://www.dualspace.net- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - This mechanical model of yours describes how EM waves propagate through the vacuum, so does that mean EM waves will propagate at different speeds relative to a laboratory moving at varying speeds relative to this "ether"? |
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#75
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This mechanical model of yours describes how EM waves propagate through the vacuum, so does that mean EM waves will propagate at different speeds relative to a laboratory moving at varying speeds relative to this "ether"? You probably haven't taken the time to study the permittivity paper or you would see that my model first defines how electron pairs are bound in place in "pairspace" by the equivalent of linear springs to exactly account for the permittivity of space. It has an exact spring constant K, which is a major improvement over the Nobel-winning "strong force" that's just a good idea without any calibration that I know of. PS is a solid with the Youngs modulus and density that convey EM signals at the speed of light = sqrt(Y/rho) just as with sqrt(eps/rho). The signals travel absolutely in a rigid pairspace, and with c-v relative to a receding laboratory which will detect a redshift. No one actually measures the speed of light, much as you might think it's a given. This pairspace is a dual space to our space. Ancient methods tried to find an ether that had these properties, but that you could also walk through. It's all in the book. John Polasek |
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