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| Tags: current, electric, field, velocity, wire |
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#1
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Hi all,
I mysef wondered why the electric field velocity is a fraction of c. I thik I understand why the drift velocity is so low (some mm/s or lower) because of electrons being scattered by the positive ions in the metal lattice, but I cannot reconcile this mechanism for explainig (to myself) the electric field propagation between the two extremes of the wire. Any enlightening is much appreciated. Regards Angelo |
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#2
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The speed of light in a medium (conductor) is less than the speed of
light in vacuum. The speed of the electric field propagation in a conductor is less than the speed of light in a vacuum but I think it is equal to the speed of light in the conductor. I have seen it suggested that the reason for the slow down of the speed of light in media is because the photons are absorbed by the atoms (bumping orbiting electrons up to higher states) then re-emitted by the atoms. So, in a strange way, the reason for the slow down of the propagation of fields may have some similarity to the reason for the slow drift velocity. While the drift velocity is way slow due to 'scattering', electrons would not move at light speed regardless (being massive). The electrons do get some pretty good speed (10^6 m/s) even though there is so little room for acceleration between collisions. "Angelo" wrote in message ... Hi all, I mysef wondered why the electric field velocity is a fraction of c. I thik I understand why the drift velocity is so low (some mm/s or lower) because of electrons being scattered by the positive ions in the metal lattice, but I cannot reconcile this mechanism for explainig (to myself) the electric field propagation between the two extremes of the wire. Any enlightening is much appreciated. Regards Angelo |
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#3
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Angelo wrote:
I mysef wondered why the electric field velocity is a fraction of c. I thik I understand why the drift velocity is so low (some mm/s or lower) because of electrons being scattered by the positive ions in the metal lattice, but I cannot reconcile this mechanism for explainig (to myself) the electric field propagation between the two extremes of the wire. Any enlightening is much appreciated. Firstly, it doesn't really make sense to talk about "electric field velocity". Do you mean the velocity of electromagnetic waves? The velocity of electromagnetic waves along a wire is _not_ the same as the electron drift velocity. For a single wire, the EM waves move along the wire at c. In a coax, somewhat slower, firstly, because a coax cable is a hollow waveguide, and secondly, because it isn't free space (or air, which is close enough often enough), but an insulating dielectric. You could think about the drift velocity as being a local response to the local electric field, which is the local effect of EM waves moving along the wire (or coax, or whatever) at c, very close to c, or at some (large) fraction of c determined by the geometry of the conductors and the dielectric constant of the insulation. Feel free to ask more. -- Timo |
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#4
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On 24 Mag, 22:51, wrote:
Thank you Timo for this sound answer, and sorry for the delay of this mine. Angelo wrote: I mysef wondered why the electric field velocity is a fraction of c. I thik I understand why the drift velocity is so low (some mm/s or lower) because of electrons being scattered by the positive ions in the metal lattice, but I cannot reconcile this mechanism for explainig (to myself) the electric field propagation between the two extremes of the wire. Any enlightening is much appreciated. Firstly, it doesn't really make sense to talk about Here I should have forget some basic concepts. If possible, could you give me, if possible ( I know that not always it is possible), a hint about why "it doesn't really make sense"? "electric field velocity". Do you mean the velocity of electromagnetic waves? Most probably. I had in mind a DC regime, so a constant current, and a constant magnetic field. The velocity of electromagnetic waves along a wire is _not_ the same as the electron drift velocity. yes, of course, I said so above. For a single wire, the EM waves move along the wire at c. In a coax, somewhat slower, firstly, because a coax cable is a hollow waveguide, and secondly, because it isn't free space (or air, which is close enough often enough), but an insulating dielectric. OK, I understand. You could think about the drift velocity as being a local response to the local electric field, which is the local effect of EM waves moving along the wire (or coax, or whatever) at c, very close to c, or at some (large) fraction of c determined by the geometry of the conductors and the dielectric constant of the insulation. Feel free to ask more. You've cleared up my main problems! -- Timo Regards Angelo |
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