Len Gaasenbeek wrote:
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I take that to be a negative response to my question.
I encourage you to spend a bit more time with Feynman's
path integral approach because it *does* model the VLTI
in interference mode.

Kind regards,

Sue...
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To Sue,

I don't want to cut you off as long as we are having a real discussion.
So I will give it one more try.

When we look at a multicoloured light image of a body, the light consists
of many colours and frequencies in a multiple complex phase relationship.

Consequently if we do the two slit experiment with two separate white light
images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source
and split it in two by letting it go trough two adjoining slits, will an
interference pattern show on the screen.

On the other hand if we take two separate monochromatic laser light sources
and have one shine on each slit, an interference pattern will once more show
at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO
SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a
single colour can only be either in or out of phase with another laser of
exactly the same monochrome colour.

Get a pair of laser pointers and try it.


In the case of two separate slide projectors projecting the same image on
the screen at the same location, the light source that illuminates each
slide is NOT the same. Consequently, interference between the two projected
images will not result even though the projected image is the same.
(In addition it is difficult to make two identical copies of a slide.)

They will be twice as bright because it is random light.


In the case of the multiple telescopes, the same star is used as a light
source which means that an interference pattern may result, although not to
the same extend as would have occurred if we had used the star in a two slit
experiment. This is the case because it is much harder to make two
telescopes which are exactly alike than two slits.

Click on the VLTI delay line to see just how hard it is.
Flying machines are hard too, but I don't discount that
such devices might exist just because the problem is difficult.

I hope this answers your question since I am still not quite sure what was
bothering you about my previous postings.

You have the photon clocks of Feynman's path integral but
you seem to be lacking the abilty to explore all paths.

Asking about the VLTI is just a convenient way to inquire
about your theory because a real device leaves no ambiguity.

Without ability to explore all paths, your theory predicts that
VLTI does not work in interferometer mode...
but it does work so you need to go break their telescope. ;o)

Sue...



Good luck, Len.
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