wrote in message
oups.com...
"newedana" wrote in message
oups.com...


Now, assume the particle comes to rest, i.e., v = 0. How shall we
interpret E = mc^2? It's not an energy associated with speed and it's
not dependent on any model of the particle. We shall interpret it as a
latent energy. How latent energy is to be transformed into kinetic or
some other form of energy is separate question.

....

The real problem with E=Mc^2 is that this equation does not suggest any
information concerning the nuclear activities producing the nuclear
energy in the atomic nuclear structures.

That's because it's not an equation dependent on a particular atomic
theory or model. Furthermore, it's been shown to apply rigorously at
the subatomic level.


Leaving aside Relativism, which I regard as adolescent philosophy - one step
above infantilism (Absolutism- -Categoricalism) - and attempting to be
Effectuationist:

Re "E=mc^2": Let's start over; let's attempt to make our own formula.

Taking "E": Before quantification of something effects, the concept
effects - the identity emerges.

So, (perhaps somewhat the reverse of the equation) what is this energy -
which we want to address - which becomes packeted as mass?

Presumably, we talk of "latent energy" or, perhaps better, "the nuclear
activities producing the nuclear energy in the atomic nuclear structures".
So, what do we have there?

(Nothing ventured, nothing gained).

Peter Kinane
http://www.effectuationism.com