On Mon, 19 May 2008 22:27:25 +0200, "Paul B. Andersen"
wrote:

Dr. Henri Wilson skrev:
On Mon, 19 May 2008 00:35:11 +0200, "Paul B. Andersen"
wrote:

I'll do it again with doppler shift included.
Done. Same result.

I got it right,
Check it again.

Did you get something right?
What was that?

Displacement = 2Ln^2v/(c.lambda)

versus SR: Displacement = 4Ln^2v/(c.lambda)(1-1/n^3) and anogther one:
Displacement = 4Ln^2v/(c.lambda)(1-1/n^2)

I told you, (1-1/(n^2.6)) ~= 0.5

Michelson agrees with my equation , refutes SR's.


Henri Wilson. ASTC,BSc,DSc(T)
www.users.bigpond.com/hewn/index.htm

.....specialising in teaching physics to engineers and mathematicians....