On 14 mayo, 13:53, kenseto wrote:
On May 14, 11:22 am, " wrote:



On 14 mayo, 10:03, kenseto wrote:

On May 13, 6:36 pm, "Simple Simon" wrote:

3. Einstein asserted that the train observer is rushing toward the
light front from the front and receding away from the light front from
the rear.
These assertions means that the light front from the front
will take less transit time to reach the train observer and that the
light front from the rear will take more transit time to reach the
train observer.

Obviously (assuming that the specificity that you omit has the observers and
events at the same times and locations as the classic thought experiment
does).

No I didn't assume anything of the sort. Einstein's assertion implies
that the light front from the front will take less transit time to
reach the train observer and the light front fron the rear will take
longer transit time to reach the train observer. This can only mean
one thing: Einstein's assertion violates the isotropy of the speed of
light in the train.

Once more you show you do not understand English!. Stop lying!

On the contrary, what Einstein said, and everybody else but you
understands, is that the train observer is moving towards the light
signal coming from the front of the train, and that light signal is,
for sure, traveling at c to reach him (as the back light signal is
also doing). Isotropy is never touched here

****ing idiot....the light signal from the front and the rear were
generated at equal distance from the train observer. if the signal
from the front reaches the train observer before the signal from the
rear that means that it takes different transit times for light to
travel equal distance in different directions.That means that the
speed of light is not isotropic.



Better look yourself in a mirror....you will see there a real idiot.
Light signals were generated at equal distances from the train
observer....when that very same train observer location was coincident
with the location of the track observer. That is, for your empty skull
sake, at t=0, x=0, the initial location of the track and train
observers, those strokes were at x=+100000km and x=-100000km away.
Then...what happened? Well... after 0.33 seconds the track observer
saw two simultaneous light signals at his location x=0. But in the
mean time, the train and the train observer are away from x=0
(precisely when the track observer sees the light signals the train
observer is at x59000km). So what you conclude from these facts?.
Think about it....if you can.


The exact wording from Einstein is "...he is hastening towards the
beam of light coming from B, whilst he is riding on ahead of the beam
of light coming from A. Hence the observer will see the beam of light
emitted from B earlier than he will see that emitted from A.."

Right....that means that the speed of light from B is (c+v) and the
speed of light from A is (c-v). So again what Einstein is saying is
that the train observer is seeing anisotropy light speed from A and B.
You are so stupid.

Ken Seto


No Seto....you do not "see anisotropy light speed from A and B", so
everybody is quite sure of whom is the stupid one in this discussion.
Go back to your dictionary and read about the meaning of isotropy, and
then try to remember.

Miguel Rios