On May 11, 4:38 pm, Dono wrote:
On May 11, 8:35 am, Albert****o wrote:



On May 11, 4:09 pm, Dono wrote:

On May 11, 8:03 am, Albertito wrote:

On May 11, 12:04 am, Dono wrote:

We know that E and B transform as follows for S and S' moving with
relative speed V :

E'=E
B'=B for the components of E,B along the direction parallel with V

and

E'=gamma(V) (E+VxB)
B'=gamma(V) (B=VxE/c^2) for the components of E,B along the direction
perpendicular to V

Now, imagine that the axis x,y are rotating with the uniform angular
speed omega in the plane x-y while S' moves with uniform speed V along
the common axis x.
How can I find the transformation that ties E,B,E',B'? Any reference
that you can suggest? Thank you.

Dono****o, the problem you've set up is
physically meaningless. The frames S and S'
have been left void. Where is the source of that
electric/magnetic field located? Is it at rest in frame
S' or in S. Which is the rest frame for that source,
Dono****o? Is that source's rest frame rotating?
Or is it that you have a third different frame S''
implicitly involved, where the source of the field
is at rest?

Read the problem statement, cretin.

Dono****o, your problem is bull****. If you don't know
how the source of the field is moving in S and S', your
problem has no solution. You must tie the source in a
fixed point, and see how that point moves in S while
the xy plane rotates, and see how it moves in S'.

The source is fixed in S, retardo.
S' moves along the common x-axis wit speed v
S and S' rotate together with fixed angular speed omega.
You can't even read the problem statement.

Ok, the source is fixed in S.
S' moves along the common x-axis wit speed v.
S and S' rotate together with fixed angular speed
omega. With respect to what are S and S' rotating
together with fixed angular speed, retardo? If
S rotates with angular speed omega with respect to
S', then S' rotates with minus omega wrt S. Where is
the axis of rotation located? And, how does the source
moves? Does the axis of rotation intersect the source
or not?