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Old May 11th 08 posted to sci.physics.relativity
Dono
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Default Relativitistic transformation for E and B in rotating frames

On May 11, 8:35 am, Albert****o wrote:
On May 11, 4:09 pm, Dono wrote:



On May 11, 8:03 am, Albertito wrote:


On May 11, 12:04 am, Dono wrote:


We know that E and B transform as follows for S and S' moving with
relative speed V :


E'=E
B'=B for the components of E,B along the direction parallel with V


and


E'=gamma(V) (E+VxB)
B'=gamma(V) (B=VxE/c^2) for the components of E,B along the direction
perpendicular to V


Now, imagine that the axis x,y are rotating with the uniform angular
speed omega in the plane x-y while S' moves with uniform speed V along
the common axis x.
How can I find the transformation that ties E,B,E',B'? Any reference
that you can suggest? Thank you.


Dono****o, the problem you've set up is
physically meaningless. The frames S and S'
have been left void. Where is the source of that
electric/magnetic field located? Is it at rest in frame
S' or in S. Which is the rest frame for that source,
Dono****o? Is that source's rest frame rotating?
Or is it that you have a third different frame S''
implicitly involved, where the source of the field
is at rest?


Read the problem statement, cretin.


Dono****o, your problem is bull****. If you don't know
how the source of the field is moving in S and S', your
problem has no solution. You must tie the source in a
fixed point, and see how that point moves in S while
the xy plane rotates, and see how it moves in S'.




The source is fixed in S, retardo.
S' moves along the common x-axis wit speed v
S and S' rotate together with fixed angular speed omega.
You can't even read the problem statement.
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