Time dilatation in circular motion
El Enrrabadore-mor wrote:
"Tom Roberts" escreveu na mensagem
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1 - Your solution:
\tau = sqrt(1-|v|^2/c^2)
You're not paying attention, and you are MISQUOTING. I said "For
circular motion, v(t) is constant," (TYPO: I of course meant |v(t)| is
constant.)
\tau = sqrt(1-|v|^2/c2) (T2 - T1)
Just MISquoting the formula is not sufficient, you must also read the
words that give the conditions under which the formula is valid.
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Can't see what's wrong.
What is wrong is that it is not possible to perform that integral
without knowing the functional form of v(t). When |v(t)| is constant,
the integral is trivial, and has the value given above. When |v(t)| is
not constant, you must know its functional form in order to do the integral.
Tom Roberts
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