Time dilatation in circular motion
On May 8, 9:47 am, "Greg Neill" wrote:
"El Enrrabadore-mor" wrote in message
"Tom Roberts" escreveu na mensagem
. ..
\tau = \integral_T1^T2 sqrt(1-v(t)^2/c^2) dt
You mean that "T1^T2" is T1 exponential to T2?
Or else, is it "T1 times T2"?
Oy vey. It's "standard" ascii notation for the
definite integral from T1 to T2.
Standard ASCII, that's an oxymoron.
Ken
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