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Old May 8th 08 posted to sci.physics.relativity,sci.physics
Ken S. Tucker
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Default Time dilatation in circular motion

On May 8, 9:47 am, "Greg Neill" wrote:
"El Enrrabadore-mor" wrote in message



"Tom Roberts" escreveu na mensagem
. ..


\tau = \integral_T1^T2 sqrt(1-v(t)^2/c^2) dt


You mean that "T1^T2" is T1 exponential to T2?
Or else, is it "T1 times T2"?


Oy vey. It's "standard" ascii notation for the
definite integral from T1 to T2.


Standard ASCII, that's an oxymoron.
Ken
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