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Old May 8th 08 posted to sci.physics.relativity,sci.physics
N:dlzc D:aol T:com \(dlzc\)[_1204_]
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Default Time dilatation in circular motion

Dear El Enrrabadore-mor:

"El Enrrabadore-mor" wrote in
message ...
....
With constant acceleration you can double, triple, or
10^101 the distance, that nothing changes about the
acceleration caused by the effect.


With Hubble expansion, you double the distance, you
double the effect. If you want to apply it in some other
fashion, you need another model. You should know
this. You Have No Model.


If I double the distance, then I double the effect?
This one is very funny.
It is not Hubble constant a CONSTANT?
If it's a constant effect, how can it double?


http://www.astro.ucla.edu/~wright/cosmo_02.htm
.... especially
v = H_o * D_now

.... and ...
1+z = exp(v/c)
.... with (1+z) = wavelength_measured / original_wavelength

Double distance, more than double wavelength observed.

I cannot believe you don't even remember the formula Ho came
from.

Yet the "blue shift" (not "red shift") never varies as the
distance increases.

Since you are now in the "duck and hide" stage, I will leave you
to your personal misery. Good luck with whatever it is you think
you accomplish with showing off your ignorance this way.

How can someone work with the tools of others, and have no
conception of what they were created for? "Convenience" seems
too easy an answer...

David A. Smith


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