View Single Post
  #107  
Old May 7th 08 posted to sci.physics.relativity,sci.physics
Dono
external usenet poster
 
Posts: 3,746
Default Time dilatation in circular motion

On May 7, 8:30*am, bz wrote:
"El Enrrabadore-mor" wrote :







"bz" escreveu na mensagem
. 198.139...
"El Enrrabadore-mor" wrote in
:


"Tom Roberts" escreveu na mensagem
...


One can analyze their experiment (including comparison to muon decay
at rest) in two different ways:
a) use the overall inertial frame of their storage ring
* *and apply SR.
b) use the equivalence principle of GR, and treat the LOCAL
* *acceleration of the stored muons as a gravitational field
* *and compute the gravitational time dilation in LOCAL
* *coordinates in which the stored muon is at rest.
These obtain the same answer.


Moreover:
Your a) appeals on velocity as the cause of
time dilatation.
Your b) appeals on acceleration (or gravity
by equivalence principle) to be the cause on
time dilatation.


It is not the velocity or the acceleration (in SR) that explains the
time difference.
It is the different trajectory.
Trajectory through space-time.


And that space-time is a Gaussian coordinate
system made of curved lines like two orthogonal
mirror spirals?


Please explain Bob.


Look at the particle that has just made one trip around the ring.
It is now back at its starting point in space but has moved in time.
The particle that stayed stationary at the center of the ring has NOT
moved in space but it, too has move in time. The integral along both
trajectories must have the same length. Therefore the moving particle has
traveled less distance along 'its time axis' (but the same distance along the 'Lab' time axis.


This is one of the nicest explanations of the effect. :-)


Ads
 

Credit Counseling - Auto Loan - eBay - Free Ringtone - Pay Day Loans