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Old May 7th 08 posted to sci.physics.relativity,sci.physics
El Enrrabadore-mor[_2_]
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Posts: 173
Default Time dilatation in circular motion


"N:dlzc D:aol T:com (dlzc)" escreveu na mensagem
...
Dear El Enrrabadore-mor:

"El Enrrabadore-mor" wrote in message
...

"dlzc" escreveu na mensagem
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Dear El Enrrabadore-mor:

On May 6, 8:10 am, "El Enrrabadore-mor"
wrote:

Hubble constant is an acceleration, as everybody
knows.

km/sec / megaparsec = distance / time / distance
= 1/time

You might want to start a study in "dimensional analysis".
The 1700's and 1800's were a productive time.


Maybe I went a little bit to fast claiming "as everybody
knows". Even so, "Hubble acceleration" gives 730 hits
for an exact query.


And is horse**** still.


Horse****?
So far this one have passed 3 or 4 times.
You 're the first to insist that Hubble constant combined
with a constant speed of light doesn't generate an "Hubble
acceleration".


Hubble constant is an acceleration because, as I've
already explained, it's a velocity taken per a
distance (Megaparcec).


So it is a velocity at a distance. It is also a frequency change at a
distance. But it is no "acceleration".


Well, this is only a matter of putting neurons working
together.
You know that per each Mpc distance, the speed of celestial
objects increase by 85 m/s, as seen by earth telescopes and
by means of light. This effect was called Hubble constant.
So, a stopped object at 1 Mpc distance will be seen at
a speed of 85 m/s.
A stopped object at 2 Mpc distance will be seen at
a speed of 170 m/s. And so on.
In fact, it doesn't matter if the object is stopped or moving.
Depending on the distance to Earth telescopes, one needs to
add a velocity increase of 85 m/s per Mpc.

Since the speed of light is constant and the standard
taken to define distance (the meter and all astronomical
distances), working a little bit further with our brain, one
can easily figure that Hubble constant states there is velocity
increase of celestial objects dependent on the time it
takes for light emitted by those celestial objects to
reach the Earth.
H = 85m/s / Mpc
If instead of units of Mpc for distance, you chose to use
such distance expressed in terms of time it takes for
like to travel that distance, what changed?
Nothing changes, since the speed of light is a
Universal constant taken to measure distances,
nothing changes.

Therefore, I can call Hubble constant an acceleration
of about 8.5x10^-10 m/s^2, and no one can ever
prove me wrong. Unless you don't agree that the
velocity of light is constant in vacuum and a good
standard for distances.

The effect is the same, but the value is not.
Call it H' = 8.5x10^-10 m/s^2 = Pioneer anomalous
acceleration.



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