Time dilatation in circular motion
Dear El Enrrabadore-mor:
"El Enrrabadore-mor" wrote in
message ...
"dlzc" escreveu na mensagem
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Dear El Enrrabadore-mor:
On May 6, 8:10 am, "El Enrrabadore-mor"
wrote:
Hubble constant is an acceleration, as everybody
knows.
km/sec / megaparsec = distance / time / distance
= 1/time
You might want to start a study in "dimensional analysis".
The 1700's and 1800's were a productive time.
Maybe I went a little bit to fast claiming "as everybody
knows". Even so, "Hubble acceleration" gives 730 hits
for an exact query.
And is horse**** still.
Hubble constant is an acceleration because, as I've
already explained, it's a velocity taken per a
distance (Megaparcec).
So it is a velocity at a distance. It is also a frequency change
at a distance. But it is no "acceleration".
So that, we know that during the time
it takes for light to travel that distance (1 Mpc) the
velocity of celestial bodies increase 85 m/s - we
have a "dv". So the time it takes for light to travel
the distance of 1 Mpc can be calculated - it will
be our "dt". dv / dt = 85m/s / (time for light to
travel 1Mpc) = Pioneer 11 acceleration.
Wrong. It is pretty close the the recession rate of the Moon
too. But that is not Hubble expansion either.
What I didn't mention was that Hubble constant
only becomes an acceleration when combined
with the velocity of light. Sorry.
It is not an acceleration even then. Sorry.
Seriously, you need to work on a different tack. You have played
this one out, and your chewing gum and string will no longer hold
it together.
David A. Smith
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