constancy of light
On 5 mayo, 17:32, rbwinn wrote:
On May 5, 1:44�pm, YBM wrote:
rbwinn a �crit :
You neglect the fact that if x or x' is negative in the equations
x=ct, x'=ct', then either the velocity of light has to be negative or
time has to be negative. �
You're right that in the case of x=ct, when t in negative, so is x...
So what ?
The equations you gave would apply only to
positive values of x and x',
Where did you get this ? I used the equation of propagation
of light x=ct, which applies either when t or x are negative
or positive, and the LT which apply for any x,t, positive or
negative.
Well, for example, light is emitted at the origins of S and S' when
they coincide. According to Einstein, the light would propagate in S
as a sphere with a radius of ct, and in S' as a sphere with a radius
of ct', except that the sphere in S' is an oblate sphere because of
the distance contraction. So we consider a photon proceeding from the
origins of S and S' at t=t'=0 in the -x direction. When a time of t
has transpired in S, a time of t' has transpired in S'. The photon is
at the coordinate x in S and at the coordinate x' in S'. Both x and
x' are negative. Both t and t' are positive. The velocity of the
photon is -c, not c as you insist it would be. The Lorentz equations
themselves show that x=(-c)t.
meaning that a photon is traveling in the
+x direction relative to the x axis. �
x=ct means that light is traveling in the (Ox) (call this
+x if you want) direction and that x=0 at t=0. This equation
of movement applies as well for x,t being negative or positive.
The Lorentz equation works because it is showing velocity of light,
not speed of light as scientists say it does. If the equations were
using speed of light, you would be able to reduce them down by the
rules of algebra, and they would still work. They will not work if
you reduce them down past
t'=(t-vx/c^2)/sqrt(1-v^2/c^2)
with the equations x=ct, x'=ct', because if you do, the velocity of a
photon is wrong. Why not reduce the numerator to t(1-v/c)?
If you did, you would have to put a -c into the equation for c
every time x was negative. So if you reflect light from a mirror, the
velocity of a photon changes, and you have to change from c to -c.
The Lorentz equations do this automatically with the value of x,
however, they do so at the price of a distance contraction.
So what is your theory about how light exists if nothing can be
accellerated to the speed of light?
Robert B. Winn
We all agree with you. So in the interest of science, and since you
have the uttermost knowledge about this subject, please disconnect
yourself right now from your Internet and start writing a book or
paper about this new science. We, in the mean time will contact the
editors of some prestigious Journals, such as Science and Nature, and
let them know that you are about to provide to the scientific
community with the most important discovery of this century, so they
can be ready when your work is ready.
Miguel Rios
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