On May 3, 9:50*pm, Koobee Wublee wrote:
On May 3, 10:01 pm, Eric Gisse wrote:

Schwarzschild’s original solution to the field equations does not
manifest black holes, but Hilbert’s solution does which is known as
the Schwarzschild metric. *Both solutions are asymptotically flat,
spherically symmetric, and static. *Both solutions at weak gravitation
are compatible with Newtonian law of gravity. *In fact, there are an
infinity numbers of such solutions that fit these criteria.

They are all the same solution, idiot.

Oh, excuse me. *I am still getting BS responses from a multi-year
super senior at the University of Alaska. *Well, my post still
stands. *CHECKMATE

Having black holes or no black holes is a serious matter and not an
issue of terminology. *You are very guilty of creating mysticism and
passing it on as wisdom.

** *MYSTICISM IS NOT WIDSOM

Schwarzschild’s original solution to the field equations does not
manifest black holes, but Hilbert’s solution does which is known as
the Schwarzschild metric. *Both solutions are asymptotically flat,
spherically symmetric, and static. *Both solutions at weak gravitation
are compatible with Newtonian law of gravity. *In fact, there are an
infinity numbers of such solutions that fit these criteria.
Scientifically, there should be no preference as to which solution is
more valid. *But through mysticism, you favor the Schwarzschild metric
for some reasons involving the black art.

What you were told before and still do not understand:

* The Schwarzschild and Hilbert solutions are the same solution. There
is a coordinate mapping between the two.

* Black holes are still there. Changing coordinates doesn't make the
trapped surface go away.

* You are stupid.