rbwinn wrote:
Bryan Olson wrote:
rbwinn wrote:
Bryan Olson wrote:
rbwinn wrote:
Look, after ten or twelve times of trying to get a scientist to admit
that two clocks running at different rates cannot be represented by
the equation t'=t, I think that this basic principle has been
emphasized enough.
There's no question that the same variable cannot represent two
non-equal quantities. The problem is that you claim to use the
Galilean transform, then you contradict the Galilean transform.
I understand what you are saying. �You are a
respected scientist and Party member,
You must have me confused with someone else.

Spoken like a scientist. �Only a scientist could claim that I am
contradicting the Galilean transformation equations by using them.
Spoken like a true kook. It's not the using and no one said it was.

Exactly how am I contradicting the Galilean transformation equations?

You say devices to measure time at rest in S' will find it to be
something other than t'.

The earth rotates on its axis the same number of times in S' as it
does in S. The Sun rotates on its axis the same number of times in S'
as it does in S. The planets revolve around the sun the same number
of times in S' as they do in S. So how is t' different in S' than in
S?

Robert, *you* came up with n' for time measured in S', and *your* n'
does not equal t in general. "How" time is different between frames
is an interesting question (which has a well-established answer that
many of us have tried to explain in this newsgroup), but you
contradict Galileo's theory regardless of that issue.

Contradicting Galileo's transform makes sense. His theory turns out
not to hold when |v| is a significant fraction of the speed of light.

Accepting Galileo's transform can also make sense. Considering the
objects we encounter, "v c" holds with few exceptions. Galileo
never had the chance to observe the phenomena that motivated
development of the Lorentz transform and special relativity.

What makes no sense is to do both simultaneously. To assert that
time measured in S' will be n', while also holding that time in S'
is t'=t, makes sense if and only if n'=t'=t in general. Robert, in
your system n' does not equal t' in general.


--
--Bryan