On Mar 9, 8:50 pm, Koobee Wublee wrote:
On Mar 9, 2:45 pm, JanPB wrote:



On Mar 9, 2:37 pm, Koobee Wublee wrote:
On Mar 8, 10:10 pm, Koobee Wublee wrote:
Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

You said ds^2 was a scalar.

Yes, I did. Thank your for repeating it many times. You must know
that by heart by now.

If this is so, then why can't you tell us
what number is ds^2 equal to on the sphere?

I told you already. As soon as you can give me the numbers for these
elements, I can give you a number. What are these numbers again?

You said ds^2 was a scalar. That means it gives you a number once you
give it a point. Can you tell me why you cannot answer this question?

--
Jan Bielawski