On Mar 9, 2:45 pm, JanPB wrote:
On Mar 9, 2:37 pm, Koobee Wublee wrote:
On Mar 8, 10:10 pm, Koobee Wublee wrote:

Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

You said ds^2 was a scalar.

Yes, I did. Thank your for repeating it many times. You must know
that by heart by now.

If this is so, then why can't you tell us
what number is ds^2 equal to on the sphere?

I told you already. As soon as you can give me the numbers for these
elements, I can give you a number. What are these numbers again?

There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

I'm buying off Microsoft, did I tell you?

Please keep on dreaming, you majesty. It is also good for your sanity
to dream about your fat castle in the air able to withstand more than
200 years of nonsense, BS, and lies.