On Mar 9, 1:37 pm, Koobee Wublee wrote:
On Mar 9, 12:10 am, JanPB wrote:



On Mar 8, 10:10 pm, Koobee Wublee wrote:
Given

(ds)^2 = g_ij dq^i dq^j

Where

** i, j = 1, 2

Then,

(ds)^2 = g_11 dq_1 dq_1 + g_12 dq_1 dq_2 + g_21 dq_2 dq_1 + g_22 dq_2
dq_2

So, wise guy, go ahead and assign the numbers to g_11, g_12, g_21,
g_22, dq_1, and dq_2. Then, you will find a number for (ds)^2.
shrug

Where is the number? You said ds^2 was a scalar. Which number is ds^2
equal to on the sphere? Either write down the actual number or say
that you were wrong.

Oh, no. I am not wrong on this one.

If you are either incompetent in arithmetic or incapable of using a
calculator, as soon as you give me the numbers, g_11, g_12, g_21,
g_22, dq_1, and dq_2, we will give you an answer.

There is no other exit.

In the meantime, keep whining in that fat castle in the air. It is
crumbling as we speak. shrug

I was thinking ds=0, which is true for light,
then take the path on/at an event horizon so
the light is a world line around a sphere.
Of course ds being a differential can't be
non-zero.
Regards
Ken S. Tucker