View Single Post
  #19  
Old February 3rd 08 posted to sci.physics, sci.physics.relativity, rec.org.mensa
Koobee Wublee
external usenet poster
 
Posts: 2,895
Default Einstein questioned his Nobel Prize

On Feb 2, 10:21 am, JanPB wrote:

So you have nothing to say beyond cutting and pasting same old
balonium.


You need to peruse what I have to say about GR as well.

* * * * General Theory of Relativity (GR) * * * *

The development of GR first diverged from Newtonian physics around the
middle of the nineteenth century, when Riemann wrote down the
relationship of an actual displacement segment to how an observer
observes this same displacement segment.

ds^2 = g_ij dq^i dq^j

Where

** ds = Invariant geometry in displacement
** g_ij = Elements of the metric
** dg^i = Observer's choice of coordinate system
** i, j = 1, 2, 3 (3 spatial dimensions)

The shortest distance through the actual space (invariant geometry)
can now be computed using the calculus of variations. This was
exactly how Christoffel did it in the famous geodesic equations.

d^2q^n/ds^2 + g^nk (@g_ik/@q^j + @g_jk/@q^i - @g_ij/@q^k) @q^i/@s @q^j/
@s / 2 = 0

Where

** i, j, k, n = 1, 2, 3
** @ = Partial derivative operator

The quantities called the connection coefficients in the geodesic
equations become the Christoffel symbols of the second kind below.

Y^n_ij = g^nk (@g_ik/@q^j + @g_jk/@q^i - @g_ij/@q^k) / 2

Where

** d^2q^n/ds^2 + Y^n_ij @q^i/@s @q^j/@s = 0

However, due to the symmetry in the metric, there is at least another
way of presenting the geodesic equations.

d^2q^n/ds^2 + g^nk (@g_ik/@q^j - @g_ij/@q^k / 2) @q^i/@s @q^j/@s = 0

In doing so, the connection coefficients are very different from the
Christoffel symbols of the second kind.

Z^n_ij = g^nk @g_ik/@q^j - @g_ij/@q^k / 2

Where

** d^2q^n/ds^2 + Z^n_ij @q^i/@s @q^j/@s = 0

About a decade before the transition of the nineteenth and the
twentieth centuries, Ricci defined the covariant derivative based on
the geodesic equations and the connection coefficients. However,
Ricci did not know there is another set of connection coefficients
that are equally valid to describe the geodesic equations as the
Christoffel symbols of the second kind.

DX^n/Ds = dX^n/ds + Y^n_ij dq^i/ds X^j

Where

** DX^n/DS = Covariant derivative on X, a vector

The idea is to allow the covariant derivative of (X = dq^n/ds) to be
null in accordance with the geodesic equations. However,
mathematically there exists another operator that can achieve the
exact same thing.

EX^n/Es = dX^n/ds + Z^n_ij dq^i/ds X^j

Where

** EX^n/ES = Another operator on X, a vector

Ricci went on to derive (invent) the Riemann tensor which just like
the metric is merely a matrix. The derivation takes us through the
null geodesic variations.

R^n_ikj = @Y^n_ij/@q^k - @Y^n_ik/@q^j + Y^n_kl Y^l_jk - Y^n_jl Y^l_ik

Or

R^n_ikj = @Y^n_ij/@q^k - @Y^n_ik/@q^j + Y^n_jl Y^l_ik - Y^n_jl Y^l_ik

Ricci, however, only discovered the first tensor above while the
second one is also very mathematically valid in accordance with the
method of null geodesic variations. Ricci's student Levi-Civita then
invented the Ricci tensor based on the Riemann tensor derived by Ricci
(the first equation above).

R_ij = @Y^k_ij/@q^k - @Y^k_ik/@q^j + Y^k_kl Y^l_ij - Y^k_jl Y^l_ik

Where

** R_ij = R^k_ikj

The Ricci scalar follows as described below.

R = g^ij R_ij

Where

** g^ij = inverse of the matrix g_ij the metric

After the introduction of the Lorentz transformation, the Goettingen
group of physicists including Minkowski, Hilbert, Schwarzschild, and
Klein extended Riemann's description of curved space into a four-
dimensional spacetime.

ds^2 = g_ij dq^i dq^j

Where

** ds = Invariant geometry in spacetime
** g_ij = Elements of the metric
** dg^i = Observer's choice of coordinate system
** i, j = 0, 1, 2, 3 (1 temporal and 3 spatial dimensions)

In 1915, Hilbert finally invented the following Lagrangian which does
not even satisfy as a Lagrangian according to the variations of
calculus.

L = (H R + p c^2) sqrt(-det(g^ij))

Where

** L = Hilbert's Lagragian
** R = Ricci scalar
** p = density of matter
** det() = determinant of the matrix as operand
** H = a constant

Hilbert then went on to take the partial derivative of this Lagrangian
with respect to each element of the metric represented by g^ij and
setting it to zero.

@L/@g^ij = H sqrt(-det(g^ij)) @R/@g^ij - H R @det(g^ij)/@g^ij / sqrt(-
det(g^ij)) / 2 - p c^2 @det(g^ij)/@g^ij / sqrt(-det(g^ij)) / 2 = 0

Where (mathematical identity)

** @R/@g^ij = R_ij
** @det(g^ij)/@g^ij = g_ij det(g^ij)

The result is the set of Einstein field equations.

R_ij - R g_ij / 2 = c^2 p g_ij / H / 2

Or

G_ij = T_ij

Where

** G_ij = R_ij - R g_ij / 2
** T_ij = c^2 p g_ij / H / 2

Einstein played no role. His rediscovery of the equivalence principle
also finds no role in the derivation. The derivation of GR is totally
based on mathematical nonsense.

Very soon after the introduction of the field equations, Schwarzschild
discovered the following static and spherically symmetric solution
(metric).

ds^2 = c^2 (1 - R / (r^3 + R^3)^(1/3)) dt^2 - r^4 dr^2 / (r^3 + R^3) /
((r^3 + R^3)^(1/3) - R) - (r^3 + R^3)^(2/3) dO^2

Where

** R = G M / c^2
** dO^2 = cos^2Phi dTheta^2 + dPhi^2

There are actually an infinite number of solutions (metric) to the
field equations using the same set of coordinate system. The most
popular one was derived by Hilbert in 1916 now called the
Schwarzschild metric.

ds^2 = c^2 (1 - 2 R / r) dt^2 - dr^2 / (1 - 2 R / r) - r^2 dO^2

Notice Schwarzschild's original solution does not manifest black holes
but Schwarzschild metric does. The following solution also as simple
as the Schwarzschild metric does not manifest black holes as well.

ds^2 = c^2 dt^2 / ( 1 + 2 R / r) - (1 + 2 R / r) dr^2 - (r + R)^2 dO^2

Although not all the static and spherically symmetric solutions
degenerate to Newtonian law of gravity, all these three metrics above
do. This means the universe must be expanding and finally collapsing
back to itself. After observing the universe to be static, Einstein
correctly identified the field equations and Newtonian law of gravity
as not fit this observation. He cleverly introduced (pull out of his
*ss) a negative mass density to counter the attraction of gravity.
The reason is very simple. Positive mass manifests attraction in
gravity; negative mass manifests repulsion in gravity. In order to
hide the embarrassment of introducing negative mass in vacuum, he
again cleverly called this quantity as the Cosmological constant. The
development of GR at this stage is a total joke, but the nonsense did
not end here. Friedman, Lemaitre, Robertson, and Walker discovered a
non-static but spherically symmetric solution to the field equations
called the Friedman-Lemaitre-Robertson-Walker (FLRW) metric.

ds^2 = c^2 dt^2 - a^2 (dr^2 / (1 - r^2 / R^2) + r^2 dO^2)

Where

** a = Function of t only
** R = Constant

This means two of the field equations are

** (da/dt)^2 / a^2 + c^2 / R^2 / a^2 = 8 pi G p / 3
** 2 d^2a/dt^2 / a + (da/dt)^2 / a^2 + c^2 / R^2 / a^2 = 8 pi G p

We can very easily solve these differential equations.

If R^2 = 0,

** a^2 = c^2 cosh^2(w(t+T)) / (w^2 R^2)
** p = 3 w^2 / (4 pi G)

If R^2 0,

** a^2 = - c^2 cos^2(w(t+T)) / (w^2 R^2)
** p = - 3 w^2 / (4 pi G)

Where

** w, T = Integration constants

The density of the universe, p, must always remain constant. This
means the universe must be static as observed back then. Even with
the introduction of the Cosmological constant, the basic form of the
solution above remains the same. The Cosmological becomes totally
useless. The introduction of the Cosmological constant is the only
blunder in Einstein's contribution in GR.

There are two problems with this FLRW metric.

** There is no solution combining the Schwarzschild metric and the
FLRW metric. This means the FLRW metric does not satisfy the
Newtonian law of gravity. Gravity is not caused by a curvature in
spacetime in general but only the gravitational time dilation.

** When Lemaitre first then Hubble discovered the red shift of
distant galaxies, there is no remedy for the FLRW metric to satisfy
this observation even with the Cosmological constant.

There are so many problems with GR right from the start. The most
basic is even more embarrassing. Any diligent grade school children
can identify the mathematical relationship below.

Given that

A = B C

If (A = constant and B != 0), then (C = A / B).

This blunder came as early as during Ricci's time when the Riemann
tensor which is merely a matrix was incorrectly identified as a tensor
which means invariance to any coordinate transformation. Similarly,
the metric is merely a matrix. Ricci deified the metric into a
tensor. Mathematically, this can easily be proven wrong.

We have two different geometries described by the same coordinate
system with two different metrics.

** ds^2 = [g] * [dq^2] = g_ij dq^i dq^j
** ds'^2 = [g'] * [dq^2] = g'_ij dq^i dq^j

Where

** ds^2 = Geometry #1
** ds'^2 = Geometry #2
** [g] = Metric #1
** [g'] = Metric #2
** [dq^2] = Coordinate system, same
** * = Dot/inner product of two matrices

Or we have the same geometry described below by different metrics and
different coordinate systems. One example involves the linearly
rectangular and the spherically symmetric polar coordinate systems.

** ds^2 = [g] * [dq^2] = [g']* [dq'^2]
** ds^2 = g_ij dq^i dq^j = g'_ab dq'^a dq'^b

The geometry, ds^2, must be invariant due to obvious reason. The
choice of coordinate system, d[q^2], is observer dependent. This can
only mean the metric, [g], must also be observer dependent. The
metric, the Riemann, and the Ricci tensors cannot be tensors after
all. All solutions to the field equations must be unique and
independent of each one where all solutions must reference to the same
choice of coordinate system in describing vastly different invariant
geometries. What good is the set of field equations that can generate
an infinite numbers of solutions to describe infinitely different and
independent universes? What good is the set of field equations that
can either generate a solution that manifests black holes and also
ones that don't?


* * * * Malicious Troll McCullough's Stupid Question * * * *

The static and spherically symmetric solutions to the field equations
in general take one such form below.

ds^2 = c^2 dt^2 / (1 + K / R) - (1 + K / R) (dR/dr)^2 dr^2 - (R + K)^2
dO^2

Where

** R(r) = Function of r
** dO^2 = cos^2(Phi) dTheta^2 + dPhi^2
** K = Integration constant
** dr, dTheta, dPhi = Choiced coordinate system

Only if the following is true, you get the Schwarzschild metric.

** R = r - K

Where

** K = 2 G M / c^2

If the following is true, you get Schwarzschild's original solution
which does not manifest any black holes.

** R = (r^3 + K^3)^(1/3) - K

If the following is true, you get another solution just as simple as
the Schwarzschild metric but without manifestation of black holes.

** R = r

If the following is true, you get a constantly expanding universe that
also obeys the Schwarzschild metric --- a trait that even the FLRW
metric fails to do so.

** R = r / (1 + r^2 / K / L)

Where

** L = Cosmic constant

If the following is true, you get an accelerated expanding universe.

** R = r / (1 + r^2 / K / L + r^3 / K / L / N)

Where

** L, N = Cosmic constants

Each of these solutions is uniquely independent of the others.
Claiming these solutions being the same is utter nonsense --- a
misunderstanding on your part of failure to understand the metric is
not a tensor but merely a matrix. In addition, the last two metrics
prove the Birkhoff's theorem wrong.
Ads
 

Pay Day Loans - Personal Loans - Loan - MPAA - Loans