GPS frequency shift calculation
Henri Wilson wrote:
On Tue, 07 Aug 2007 11:45:54 GMT, "Androcles"
wrote:
"qbit" wrote in message
...
: For the well known relativistic correction of 38 microseconds per day
: they do a frequence shifting in the transmitters of the GPS satellites.
: They shift the frequence down from 10.23 MHz to 10.22999999543 MHz
instead.
Shifting frequency doesn't change time, it changes N where N = t.f
Example:
t = 1 second, f = 1 Hz, number of cycles counted N = 1
t = 1 second, f = 2 Hz, number of cycles counted N =2
t = 1 second, f = 1 MHz, number of cycles counted N =1,000,000
t = 60 seconds, f = 10 MHz, number of cycles counted N =600,000,000
N = t.f
Questions:
What does the term "4.465 parts in 10^10" mean?
The number of extra cycles that suddenly appeared out of nowhere.
They were not sent but they did arrive.
If you send 10,229,999,995.43 cycles in a second (or an hour or a day) and
10,230,000,000 arrive in a second (or an hour or day) then 45.7 cycles
magically appeared out of thin aether. The number of cycles sent has to
match the number of cycles received no matter what time frame they are
sent in.
What does it represent? The 38 us/d ? How?
How is this value calculated?
As a matter of interest, Ballistic theory comes up with exactly the same figure
of 45.7.
BaTh says photons accelerate as they fall to Earth, just like anything else.
The fractional change in speed multiplied by the number of seconds in a day
just happens to produce the magic figure of 45.7
**********************************
G=6.67E-11
Solar Mass = 5.983E24 kgm
Equatorial Radius = 6378388 m
GPS : velocity of 3.874 km/s at an altitude of 20,184 km = 26562388 m from
centre
______________________
For unit mass starting at velocity c:
F= -GM/r^2
O---------o 26600
d(PE)=$Fdr= [GMm/r] from r1 to r2
_____________
GM=6.67E-11 * 5.983E24 kgm
= 3.9907 E14
_____________
Determine 1/r1-1/r2
1/Re= 15.68E-8
1/Rs= 3.76E-8
1/r1-1/r2= 1.192E-7
(altrnatively: 20,184,000/169e12 = 1.19E-7)
Lost PE= 4.757E7
This equals gained KE = 1/2[(c+v)^2] - 1/2(c^2)
~cv
velocity gained = 4.757E7/2.997E8
= 1.59E-1 m/sec
as proportion of c: v/c = 5.3E-10
multiply by seconds per day= 457920E-10
= 45.7E-6
Does this mean that the BaTh predicts that clocks on
a higher gravitational potential will run faster?
Paul
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